Re: [Matplotlib-users] logairthmic contour plot
List, I'm making a scatter plot using a for loop. Here's a simple example.. for i in range(10): x=rand() y=rand() scatter(x,y,label='point') legend() show() When you do this, you get a legend entry for every single point. In this case, I get 9 entries in my legend. Is there a way to only get a single entry? I have looked into creating the legends by hand, but I'm not having much luck. Googling, only turned up a single example of someone else with the same problem. Help me list, you're my only hope. Steven -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] logairthmic contour plot
If all your values are positive (and you are sure of it), you could use the SymmetricalLogScale It uses log scale for large values (both positive and negative), and linear for small ones. http://matplotlib.sourceforge.net/devel/add_new_projection.html I believe there is a way to do it without going symetrical (ie, only defined for positive values), but I am unable to find it. On Wed, Jun 13, 2012 at 7:31 PM, jonasr jonas.rueb...@web.de wrote: Hi, im actually trying to make a countour plot Z=f(X,Y) from two variables X,Y . My Problem is that i have to use a logarithmic scale for the Z values. If i plot the data with the logarithmic scale it gets pretty ugly, because i have a lot of values which are zero, which means on the log scale the value goes to -inf. Here is an example what i mean http://www.imagebanana.com/view/qh1khpxp/example.png I acutally have no idea how to make the plot look better, maybe somebody has an idea ? thank you -- View this message in context: http://old.nabble.com/logairthmic-contour-plot-tp34007155p34007155.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] logairthmic contour plot
First, this is another topic, so please, change the subject of the message so it doesn't get messed up with others (and possible help lost in the process). Now, you are indeed plotting one dot at the time and generating a label for it. If you don't want that, you have to plot the whole list at the time: x=[rand() for i in xrange(10)] y=[rand() for i in xrange(10)] scatter(x,y, label='points') legend() show() where the definition of x includes a list comprehension (equivalent at for i in xrange(10): x.append(rand()) ). On another topic, people are not usually fan of using from MODULEX import *, as it can turn into poor code and name collisions. It is nicer if you write import pylab as plt, and refer to the functions as plt.scatter and so on. Regards. On Wed, Jun 13, 2012 at 9:21 PM, Steven Boada bo...@physics.tamu.edu wrote: List, I'm making a scatter plot using a for loop. Here's a simple example.. for i in range(10): x=rand() y=rand() scatter(x,y,label='point') legend() show() When you do this, you get a legend entry for every single point. In this case, I get 9 entries in my legend. Is there a way to only get a single entry? I have looked into creating the legends by hand, but I'm not having much luck. Googling, only turned up a single example of someone else with the same problem. Help me list, you're my only hope. Steven -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] logairthmic contour plot
On Thursday, June 14, 2012, Daπid wrote: First, this is another topic, so please, change the subject of the message so it doesn't get messed up with others (and possible help lost in the process). Now, you are indeed plotting one dot at the time and generating a label for it. If you don't want that, you have to plot the whole list at the time: x=[rand() for i in xrange(10)] y=[rand() for i in xrange(10)] scatter(x,y, label='points') legend() show() where the definition of x includes a list comprehension (equivalent at for i in xrange(10): x.append(rand()) ). On another topic, people are not usually fan of using from MODULEX import *, as it can turn into poor code and name collisions. It is nicer if you write import pylab as plt, and refer to the functions as plt.scatter and so on. Regards. Point of style: in general, yes, but pylab was intended for that to help transition matlab users. Pylab really shouldn't be loaded as plt, because that is what pyplot is usually imported as. Of course, this is all just a matter of style and preference. Cheers ! Ben Root -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] logairthmic contour plot
On 06/13/2012 07:31 AM, jonasr wrote: Hi, im actually trying to make a countour plot Z=f(X,Y) from two variables X,Y . My Problem is that i have to use a logarithmic scale for the Z values. If i plot the data with the logarithmic scale it gets pretty ugly, because i have a lot of values which are zero, which means on the log scale the value goes to -inf. Here is an example what i mean http://www.imagebanana.com/view/qh1khpxp/example.png I acutally have no idea how to make the plot look better, maybe somebody has an idea ? Use np.ma.masked_less to mask out values below some threshold before taking the log. e.g., import matplotlib.pyplot as plt import numpy as np x = np.arange(0, 1, 0.01) y = np.arange(0, 8, 0.05) X, Y = np.meshgrid(x, y) Z = 10 ** (-5 + 11 * X * np.sin(Y)) Z = np.ma.masked_less(Z, 1e-4) Zlog = np.ma.log10(Z) CS = plt.contourf(X, Y, Zlog, levels=np.arange(-3, 5.01, 1.0), extend='both') plt.colorbar() Eric thank you -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
