[Matplotlib-users] Fixed width - axis equal *and* tight
Hi there,
I want to examine a vector field and therefore i used "quiver" to
visualize said field:
> import numpy as np
> import matplotlib.pyplot as plt
>
> # points
> x, y = np.meshgrid(np.arange(0, 2*np.pi, 0.1),
>np.arange(0, 1*np.pi, 0.1))
> # derivatives
> dx = -2*np.sin(x)*np.cos(y)
> dy =np.cos(x)*np.sin(y)
>
> # plot
> plt.figure()
> plt.quiver(dx, dy, color='b')
>
> # beautiful axis
> a = plt.gca()
> x_a, y_a = a.get_xaxis(), a.get_yaxis()
> a.axis('tight')
> # TODO: We should not multiply with 10 here.
> x_a.set_ticks(np.arange(0, 2*np.pi*10+1, np.pi*10/4))
> y_a.set_ticks(np.arange(0, 1*np.pi*10+1, np.pi*10/4))
> labels = [
> r'$0$',
> r'$\frac{1}{4}\pi$',
> r'$\frac{1}{2}\pi$',
> r'$\frac{3}{4}\pi$',
> r'$\pi$',
> r'$\frac{5}{4}\pi$',
> r'$\frac{3}{2}\pi$',
> r'$\frac{7}{4}\pi$',
> r'$2 \pi$']
> a.set_xticklabels(labels)
> a.set_yticklabels(labels[:5])
>
> # show
> plt.show()
(The plot looks like a double swirl, if anyone is interested in that
information)
At first I do not know why I have to multiply with 10 at the ticks, but
thats not the point.
It is much more important that I would like to set the image to a
certain width before saving. It should be both "tight" and "equal", so
after setting the width the height could be calculated automatically.
As a workaround I use the images and strech them vertically, but then
the x/y axis tick labels look strange.
So: How to set a certain width?
Thanks and a merry Christmas,
Keba
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Re: [Matplotlib-users] Fixed width - axis equal *and* tight
Hi,
Maybe a bad idea to ask a question on x-mas. Well, I hope it’s not that
unpolite to push one‘s questions. :)
Basically I just want to set a fixed width/height on my figure. That
should be possible?
Mario Fuest schrieb am Sat, 24. Dec 16:42:
> Hi there,
>
> I want to examine a vector field and therefore i used "quiver" to
> visualize said field:
>
> > import numpy as np
> > import matplotlib.pyplot as plt
> >
> > # points
> > x, y = np.meshgrid(np.arange(0, 2*np.pi, 0.1),
> >np.arange(0, 1*np.pi, 0.1))
> > # derivatives
> > dx = -2*np.sin(x)*np.cos(y)
> > dy =np.cos(x)*np.sin(y)
> >
> > # plot
> > plt.figure()
> > plt.quiver(dx, dy, color='b')
> >
> > # beautiful axis
> > a = plt.gca()
> > x_a, y_a = a.get_xaxis(), a.get_yaxis()
> > a.axis('tight')
> > # TODO: We should not multiply with 10 here.
> > x_a.set_ticks(np.arange(0, 2*np.pi*10+1, np.pi*10/4))
> > y_a.set_ticks(np.arange(0, 1*np.pi*10+1, np.pi*10/4))
> > labels = [
> > r'$0$',
> > r'$\frac{1}{4}\pi$',
> > r'$\frac{1}{2}\pi$',
> > r'$\frac{3}{4}\pi$',
> > r'$\pi$',
> > r'$\frac{5}{4}\pi$',
> > r'$\frac{3}{2}\pi$',
> > r'$\frac{7}{4}\pi$',
> > r'$2 \pi$']
> > a.set_xticklabels(labels)
> > a.set_yticklabels(labels[:5])
> >
> > # show
> > plt.show()
>
> (The plot looks like a double swirl, if anyone is interested in that
> information)
>
> At first I do not know why I have to multiply with 10 at the ticks, but
> thats not the point.
>
> It is much more important that I would like to set the image to a
> certain width before saving. It should be both "tight" and "equal", so
> after setting the width the height could be calculated automatically.
>
> As a workaround I use the images and strech them vertically, but then
> the x/y axis tick labels look strange.
>
> So: How to set a certain width?
>
> Thanks and a merry Christmas,
> Keba
>
> --
> Write once. Port to many.
> Get the SDK and tools to simplify cross-platform app development. Create
> new or port existing apps to sell to consumers worldwide. Explore the
> Intel AppUpSM program developer opportunity. appdeveloper.intel.com/join
> http://p.sf.net/sfu/intel-appdev
> ___
> Matplotlib-users mailing list
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> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
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[Matplotlib-users] Set width before saving
Hi there,
Currently i use these commands to layout and save my figures:
> figure
> ...
> gca.set_aspect('equal')
> gca.autoscale(tight=True)
> ...
> plt.savefig('fpp.png', bbox_inches='tight', pad_inches=0)
I would like to set the width of this png file, how to do that? If
savefig() does not support setting the width, maybe I can set the width
of my xaxis?
Thanks in advance, Keba
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Re: [Matplotlib-users] Fixed width - axis equal *and* tight
Hi,
Sorry for the late reply.
Tony Yu schrieb am Tue, 03. Jan 17:07:
> You can try
>
> >>> ax.set_aspect('equal')
> >>> ax.autoscale(tight=True)
>
> The order doesn't seem to matter.
That works well, thank you! :)
Kind regars, Keba.
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Re: [Matplotlib-users] Set width before saving
Hi there, John Hunter schrieb am Wed, 29. Feb 07:04: > On Feb 28, 2012, at 4:03 PM, Benjamin Root wrote: > > The size of the PNG will be based on the size of your figure object. When > > you create your figure, you can pass a figsize kwarg which takes a tuple of > > width, height in inches (defaults to 8 x 6, I think). > > > > fig = plt.figure(figsize=(10.0, 6.0)) > > With an existing Figure instance, you can also call > > fig.set_figwidth(width_inches) > > before saving (or set_figheight or set_size_inches) > > http://matplotlib.sourceforge.net/api/figure_api.html#matplotlib.figure.Figure That helps, thanks a lot! :) Regards, Keba -- Virtualization & Cloud Management Using Capacity Planning Cloud computing makes use of virtualization - but cloud computing also focuses on allowing computing to be delivered as a service. http://www.accelacomm.com/jaw/sfnl/114/51521223/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
