Hi Lucas
Yesterday (and the day before), I went to the Illinois number theory
conference.
There (2nd talk of yesterday) J. P. Selfridge announced that he would
give away $1000 US for any factor found of a number which ought to be
prime (he provided a list). On that list was 2^(2^31-1)-1.
To guard against errors in transmitions the factor is 295257526626031
p=295257526626031
I took 2, and squared it 31 times mod p. And got the result
2^(2^31)=2 mod p
Congratulations Lucas, it is indeed a factor of 2^(2^31-1)-1 well done!
Had it already been shown that M(M(p)) is not necessarily prime?
Chris Nash
Lexington KY
UNITED STATES
_
Unsubscribe list info -- http://www.scruz.net/~luke/signup.htm
Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers
