Hi Robin,
Isn't that obvious? It's because your denominator is zero. You can't compute
anything with zero denominator. The result would be infinity.
Best Regards,
Teerawat Issariyakul
http://www.ns2ultimate.com/
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On Apr 5, 2012, at 12:02 AM, robin turna wrote:
i m using awk script to calculate values of certain parameters but it gives
me error: Fatal division by zero ,,can you help me regarding this. waiting
for reply
with regards
robin
BEGIN {
sends=0;
recvs=0;
routing_packets=0.0;
droppedBytes=0;
droppedPackets=0;
highest_packet_id =0;
sum=0;
recvnum=0;
}
{
time = $3;
packet_id = $41;
# CALCULATE PACKET DELIVERY FRACTION
if ((
$1 == s) ( $35 == cbr ) ( $19==AGT )) { sends++; }
if (( $1 == r) ( $35 == cbr ) ( $19==AGT )) { recvs++; }
# CALCULATE DELAY
if ( start_time[packet_id] == 0 ) start_time[packet_id] = time;
if (( $1 == r) ( $35 == cbr ) ( $19==AGT )) {
end_time[packet_id] = time; }
else { end_time[packet_id] = -1; }
# CALCULATE TOTAL DSR OVERHEAD
if (($1 == s || $1 == f) $19 == RTR $35 ==DSR)
routing_packets++;
# DROPPED DSR PACKETS
if (( $1 == d ) ( $35 == cbr ) ( $3 0 ))
{
droppedBytes=droppedBytes+$37;
droppedPackets=droppedPackets+1;
}
#find the number of packets in the simulation
if (packet_id highest_packet_id)
highest_packet_id = packet_id;
}
END {
for ( i in end_time )
{
start = start_time[i];
end = end_time[i];
packet_duration = end - start;
if ( packet_duration 0 )
{sum += packet_duration;
recvnum++;
}
}
delay=sum/recvnum;
NRL = routing_packets/recvs; #normalized routing load
PDF = (recvs/sends)*100; #packet delivery ratio[fraction]
printf(send = %.2f\n,sends);
printf(recv = %.2f\n,recvs);
printf(routingpkts = %.2f\n,routing_packets++);
printf(PDF = %.2f\n,PDF);
printf(NRL = %.2f\n,NRL);
printf(Average e-e delay(ms)= %.2f\n,delay*1000);
printf(No. of dropped data (packets) = %d\n,droppedPackets);
printf(No. of dropped data (bytes) = %d\n,droppedBytes);
}