Re: [Numpy-discussion] reshaping array question
On Nov 17, 2015 6:53 PM, "Sebastian Berg" wrote: > > On Di, 2015-11-17 at 13:49 -0500, Neal Becker wrote: > > Robert Kern wrote: > > > > > On Tue, Nov 17, 2015 at 3:48 PM, Neal Becker wrote: > > >> > > >> I have an array of shape > > >> (7, 24, 2, 1024) > > >> > > >> I'd like an array of > > >> (7, 24, 2048) > > >> > > >> such that the elements on the last dimension are interleaving the > > >> elements from the 3rd dimension > > >> > > >> [0,0,0,0] -> [0,0,0] > > >> [0,0,1,0] -> [0,0,1] > > >> [0,0,0,1] -> [0,0,2] > > >> [0,0,1,1] -> [0,0,3] > > >> ... > > >> > > >> What might be the simplest way to do this? > > > > > > np.transpose(A, (-2, -1)).reshape(A.shape[:-2] + (-1,)) > > > > I get an error on that 1st transpose: > > > > Transpose needs a slightly different input. If you look at the help, it > should be clear. The help might also point to np.swapaxes, which may be > a bit more straight forward for this exact case. Sorry about that. Was in a rush and working from a faulty memory. ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] reshaping array question
On Di, 2015-11-17 at 13:49 -0500, Neal Becker wrote: > Robert Kern wrote: > > > On Tue, Nov 17, 2015 at 3:48 PM, Neal Becker wrote: > >> > >> I have an array of shape > >> (7, 24, 2, 1024) > >> > >> I'd like an array of > >> (7, 24, 2048) > >> > >> such that the elements on the last dimension are interleaving the > >> elements from the 3rd dimension > >> > >> [0,0,0,0] -> [0,0,0] > >> [0,0,1,0] -> [0,0,1] > >> [0,0,0,1] -> [0,0,2] > >> [0,0,1,1] -> [0,0,3] > >> ... > >> > >> What might be the simplest way to do this? > > > > np.transpose(A, (-2, -1)).reshape(A.shape[:-2] + (-1,)) > > I get an error on that 1st transpose: > Transpose needs a slightly different input. If you look at the help, it should be clear. The help might also point to np.swapaxes, which may be a bit more straight forward for this exact case. > here, 'A' is 'fftouts' > > print (fftouts.shape) > print (np.transpose (fftouts, (-2,-1)).shape) > > (4, 24, 2, 1024) <<< fftouts.shape prints this > Traceback (most recent call last): > File "test_uw2.py", line 194, in > run_line (sys.argv) > File "test_uw2.py", line 190, in run_line > run (opt) > File "test_uw2.py", line 103, in run > print (np.transpose (fftouts, (-2,-1)).shape) > File "/home/nbecker/.local/lib/python2.7/site- > packages/numpy/core/fromnumeric.py", line 551, in transpose > return transpose(axes) > ValueError: axes don't match array > > > > >> > >> A different question, suppose I just want to stack them > >> > >> [0,0,0,0] -> [0,0,0] > >> [0,0,0,1] -> [0,0,1] > >> [0,0,0,2] -> [0,0,2] > >> ... > >> [0,0,1,0] -> [0,0,1024] > >> [0,0,1,1] -> [0,0,1025] > >> [0,0,1,2] -> [0,0,1026] > >> ... > > > > A.reshape(A.shape[:-2] + (-1,)) > > > > -- > > Robert Kern > > > ___ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > https://mail.scipy.org/mailman/listinfo/numpy-discussion > signature.asc Description: This is a digitally signed message part ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] reshaping array question
Robert Kern wrote: > On Tue, Nov 17, 2015 at 3:48 PM, Neal Becker wrote: >> >> I have an array of shape >> (7, 24, 2, 1024) >> >> I'd like an array of >> (7, 24, 2048) >> >> such that the elements on the last dimension are interleaving the >> elements from the 3rd dimension >> >> [0,0,0,0] -> [0,0,0] >> [0,0,1,0] -> [0,0,1] >> [0,0,0,1] -> [0,0,2] >> [0,0,1,1] -> [0,0,3] >> ... >> >> What might be the simplest way to do this? > > np.transpose(A, (-2, -1)).reshape(A.shape[:-2] + (-1,)) I get an error on that 1st transpose: here, 'A' is 'fftouts' print (fftouts.shape) print (np.transpose (fftouts, (-2,-1)).shape) (4, 24, 2, 1024) <<< fftouts.shape prints this Traceback (most recent call last): File "test_uw2.py", line 194, in run_line (sys.argv) File "test_uw2.py", line 190, in run_line run (opt) File "test_uw2.py", line 103, in run print (np.transpose (fftouts, (-2,-1)).shape) File "/home/nbecker/.local/lib/python2.7/site- packages/numpy/core/fromnumeric.py", line 551, in transpose return transpose(axes) ValueError: axes don't match array > >> >> A different question, suppose I just want to stack them >> >> [0,0,0,0] -> [0,0,0] >> [0,0,0,1] -> [0,0,1] >> [0,0,0,2] -> [0,0,2] >> ... >> [0,0,1,0] -> [0,0,1024] >> [0,0,1,1] -> [0,0,1025] >> [0,0,1,2] -> [0,0,1026] >> ... > > A.reshape(A.shape[:-2] + (-1,)) > > -- > Robert Kern ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] reshaping array question
On Di, 2015-11-17 at 10:48 -0500, Neal Becker wrote: > I have an array of shape > (7, 24, 2, 1024) > > I'd like an array of > (7, 24, 2048) > > such that the elements on the last dimension are interleaving the elements > from the 3rd dimension > Which basically means you want to reshape with the earlier index varying faster. This is fortran order (in the simplest case for two axes being reshaped). So you can do: arr.reshape((7, 24, -1), order="F") otherwise, if order seems too confusing or dangerous. Just transpose the two axes first: arr_r = arr.transpose((0, 1, 3, 2)) arr_r = arr_r.reshape((7, 24, -1)) - Sebastian > [0,0,0,0] -> [0,0,0] > [0,0,1,0] -> [0,0,1] > [0,0,0,1] -> [0,0,2] > [0,0,1,1] -> [0,0,3] > ... > > What might be the simplest way to do this? > > > A different question, suppose I just want to stack them > > [0,0,0,0] -> [0,0,0] > [0,0,0,1] -> [0,0,1] > [0,0,0,2] -> [0,0,2] > ... > [0,0,1,0] -> [0,0,1024] > [0,0,1,1] -> [0,0,1025] > [0,0,1,2] -> [0,0,1026] > ... > > > > ___ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > https://mail.scipy.org/mailman/listinfo/numpy-discussion > signature.asc Description: This is a digitally signed message part ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] reshaping array question
On Tue, Nov 17, 2015 at 3:48 PM, Neal Becker wrote: > > I have an array of shape > (7, 24, 2, 1024) > > I'd like an array of > (7, 24, 2048) > > such that the elements on the last dimension are interleaving the elements > from the 3rd dimension > > [0,0,0,0] -> [0,0,0] > [0,0,1,0] -> [0,0,1] > [0,0,0,1] -> [0,0,2] > [0,0,1,1] -> [0,0,3] > ... > > What might be the simplest way to do this? np.transpose(A, (-2, -1)).reshape(A.shape[:-2] + (-1,)) > > A different question, suppose I just want to stack them > > [0,0,0,0] -> [0,0,0] > [0,0,0,1] -> [0,0,1] > [0,0,0,2] -> [0,0,2] > ... > [0,0,1,0] -> [0,0,1024] > [0,0,1,1] -> [0,0,1025] > [0,0,1,2] -> [0,0,1026] > ... A.reshape(A.shape[:-2] + (-1,)) -- Robert Kern ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
[Numpy-discussion] reshaping array question
I have an array of shape (7, 24, 2, 1024) I'd like an array of (7, 24, 2048) such that the elements on the last dimension are interleaving the elements from the 3rd dimension [0,0,0,0] -> [0,0,0] [0,0,1,0] -> [0,0,1] [0,0,0,1] -> [0,0,2] [0,0,1,1] -> [0,0,3] ... What might be the simplest way to do this? A different question, suppose I just want to stack them [0,0,0,0] -> [0,0,0] [0,0,0,1] -> [0,0,1] [0,0,0,2] -> [0,0,2] ... [0,0,1,0] -> [0,0,1024] [0,0,1,1] -> [0,0,1025] [0,0,1,2] -> [0,0,1026] ... ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion
