Re: [Origami] Fujimoto star spring starting proportions
In the book Invitation to Creative Playing with Origami the used paper is A4 (21x29,7cm) and the division on the short side is 16. Based upon that you make a triangle grid. I folded the model from squares too and used a 24 grid on one side. With this 24 grid the paper gets a bit too long on one side so that it is recommendable to cut a small strip of. A division into 11 is not possible, count again, I'm pretty sure it has to be at least 22. Only make the division in one direction, because what you need is a triangle grid. Here you can see the model folded by me from elephant hide: http://goo.gl/Ob5O5O The one in the middle is from a square and therefore has more stars, the other ones are made from A4 paper. Nice Greetings Anna
Re: [Origami] Fujimoto star spring starting proportions
On 2/5/14 3:47 PM, Rob Hudson wrote: There's a version that starts with a square in La Era Nueva (I think), but that looks like it's divided up into an 11x11 grid, and I'm not sure how to tackle that. Just my buck-two-fitty: Divide into 3rds, then quarter each to get 12ths, then cut off two strips to get 11x11. At least that'll get you started with the fun part of folding it while someone else smarter'n'me sorts out the actual paper ratio. :-) -D'gou When I read about someone having this sort of difficulty, I want to remind about using a grid of evenly (equally) spaced lines. Align one edge of your paper from gridline zero, on one corner, to gridline N (odd integer N=eleven, in this case), on the other adjacent corner. Pick an even number 2M less than N (2M=10 is good), and fold the lower corner to gridline 2M, creasing across the paper. Now either M or N-M is even, so it's easy to crease that part of the paper in half. Some folding sequence such as [M,N-M]=[5,6], [8,3], [4,7], [2,9], [1,10], [6,5], [3,8], [7,4], [9,2], [10,1] gets all N-1 creases to divide the paper into N sections. Crease each section in 2,4,8 . . parts to get 2N, 4N, 8N . . sections. This is such a standard technique, I wonder how it is so very frequently missed. Thank you and have a great day! SVBE(si vales, bene est) The early bird may get the worm, sure, but the second mouse gets the cheese. - Cheers, Ralph Jones
Re: [Origami] Fujimoto star spring starting proportions
On Wed, 2014-02-05 at 16:44 -0500, Ralph Jones wrote: When I read about someone having this sort of difficulty, I want to remind about using a grid of evenly (equally) spaced lines. Align one edge of your paper from gridline zero, on one corner, to gridline N (odd integer N=eleven, in this case), on the other adjacent corner. Pick an even number 2M less than N (2M=10 is good), and fold the lower corner to gridline 2M, creasing across the paper. Now either M or N-M is even, so it's easy to crease that part of the paper in half. Some folding sequence such as [M,N-M]=[5,6], [8,3], [4,7], [2,9], [1,10], [6,5], [3,8], [7,4], [9,2], [10,1] gets all N-1 creases to divide the paper into N sections. Crease each section in 2,4,8 . . parts to get 2N, 4N, 8N . . sections. This is such a standard technique, I wonder how it is so very frequently missed. Thank you and have a great day! SVBE(si vales, bene est) The early bird may get the worm, sure, but the second mouse gets the cheese. - Cheers, Ralph Jones That *is* really nice: essentially Fujimoto's approximate algorithm with a perfect first guess:-) Neil