[pacman-dev] Versioned packages on the command line.
Hi, If two repos (obviously not both official) provide the same binary package, pacman will install the package from the repo that is listed first in pacman.conf, if specified on the command line, e.g. pacman -S foo. If another package depends on foo, the same thing happens, but if it instead depends on foo=1.4 and only the second repo provides it, then pacman will correctly skip over the first repo and install it from the second. If so, would you consider making it possible to specify versions directly on the command line, e.g. pacman -S foo=1.4. I know that it's possible to first do a search for the package to see which repos contain it, then prepend the repo, e.g. pacman -S second-repo/foo, but it would be more useful sometimes to be able to just specify the version using =, =, etc. This would ideally also work for detecting providers too, e.g. if bar provides foo=1.4 then pacman -S foo=1.4 would install bar (or bring up the provider selection dialogue once that's included... I really like that idea btw... considered doing that in powerpill at some point) For a possible use of this, see the following post on the arch-haskell mailing list: http://www.haskell.org/pipermail/arch-haskell/2010-November/000740.html Regards, Xyne
Re: [pacman-dev] Versioned packages on the command line.
On Thu, Nov 11, 2010 at 8:46 PM, Xyne x...@archlinux.ca wrote: Hi, If two repos (obviously not both official) provide the same binary package, pacman will install the package from the repo that is listed first in pacman.conf, if specified on the command line, e.g. pacman -S foo. If another package depends on foo, the same thing happens, but if it instead depends on foo=1.4 and only the second repo provides it, then pacman will correctly skip over the first repo and install it from the second. If so, would you consider making it possible to specify versions directly on the command line, e.g. pacman -S foo=1.4. I know that it's possible to first do a search for the package to see which repos contain it, then prepend the repo, e.g. pacman -S second-repo/foo, but it would be more useful sometimes to be able to just specify the version using =, =, etc. This would ideally also work for detecting providers too, e.g. if bar provides foo=1.4 then pacman -S foo=1.4 would install bar (or bring up the provider selection dialogue once that's included... I really like that idea btw... considered doing that in powerpill at some point) For a possible use of this, see the following post on the arch-haskell mailing list: http://www.haskell.org/pipermail/arch-haskell/2010-November/000740.html Did you actually try it ?
Re: [pacman-dev] Versioned packages on the command line.
Xavier Chantry wrote: On Thu, Nov 11, 2010 at 8:46 PM, Xyne x...@archlinux.ca wrote: Hi, If two repos (obviously not both official) provide the same binary package, pacman will install the package from the repo that is listed first in pacman.conf, if specified on the command line, e.g. pacman -S foo. If another package depends on foo, the same thing happens, but if it instead depends on foo=1.4 and only the second repo provides it, then pacman will correctly skip over the first repo and install it from the second. If so, would you consider making it possible to specify versions directly on the command line, e.g. pacman -S foo=1.4. I know that it's possible to first do a search for the package to see which repos contain it, then prepend the repo, e.g. pacman -S second-repo/foo, but it would be more useful sometimes to be able to just specify the version using =, =, etc. This would ideally also work for detecting providers too, e.g. if bar provides foo=1.4 then pacman -S foo=1.4 would install bar (or bring up the provider selection dialogue once that's included... I really like that idea btw... considered doing that in powerpill at some point) For a possible use of this, see the following post on the arch-haskell mailing list: http://www.haskell.org/pipermail/arch-haskell/2010-November/000740.html Did you actually try it ? Sorry, I had only tried -Si foo=x.y. Thanks for being pre-emptively awesome. :)
