Re: [PD] [expr] for if, then, else?
--- On Fri, 5/15/09, padovani josepadov...@yahoo.com.br wrote: From: padovani josepadov...@yahoo.com.br Subject: Re: [PD] [expr] for if, then, else? To: Cc: pd-list@iem.at Date: Friday, May 15, 2009, 2:15 PM You don't need to declare the variables... it is just: [expr if ($f3 0, $f1 + $f2, 0); if ($f3 0, $f1 - $f2, 0)] but you will have 2 outlets (one for each if), and not an else for the same outlet in fact, it would be nice to have an else on Yadegari's externals... For more information see: http://www.crca.ucsd.edu/~yadegari/expr.html Hi José I think the final 0 before the semicolon is the else part of the statement. [expr if ($f3 0, $f1 + $f2, $f1 - $f2)] will give you only one outlet. You can even nest if statements: [expr if ($f3 0, $f1 + $f2, if ($f3 0, $f1 - $f2, 0))] -Jonathan ___ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management - http://lists.puredata.info/listinfo/pd-list
[PD] [expr] for if, then, else?
I would like to use [expr] for an if, then, else statement: If $f3 0, then $f1 + $f2, else $f1 - $f2 In the help for [expr], I see the following: [expr $f1; if ($f1 0, $f1 * 2, 0); if ($f1 = 0, $f1 / 2, 0)] So I try: [expr $f1, $f2, $f3; if ($f3 0, $f1 + $f2, 0); if ($f3 0, $f1 - $f2, 0)] but it doesn't create. I also tried without the final ,0 in each statement, and also this way: [expr $f1, $f2, $f3; if ($f3 0, $f1 + $f2, $f1 - $f2)] Can someone explain to me the proper syntax for this? D. ps... gotta love the fact I can copy/paste text in and out of objects etc these days! -- ::: derek holzer ::: http://blog.myspace.com/macumbista ::: http://www.vimeo.com/macumbista ::: ---Oblique Strategy # 142: Shut the door and listen from outside ___ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management - http://lists.puredata.info/listinfo/pd-list
Re: [PD] [expr] for if, then, else?
You don't need to declare the variables... it is just: [expr if ($f3 0, $f1 + $f2, 0); if ($f3 0, $f1 - $f2, 0)] but you will have 2 outlets (one for each if), and not an else for the same outlet in fact, it would be nice to have an else on Yadegari's externals... For more information see: http://www.crca.ucsd.edu/~yadegari/expr.html josé Derek Holzer escreveu: I would like to use [expr] for an if, then, else statement: If $f3 0, then $f1 + $f2, else $f1 - $f2 In the help for [expr], I see the following: [expr $f1; if ($f1 0, $f1 * 2, 0); if ($f1 = 0, $f1 / 2, 0)] So I try: [expr $f1, $f2, $f3; if ($f3 0, $f1 + $f2, 0); if ($f3 0, $f1 - $f2, 0)] but it doesn't create. I also tried without the final ,0 in each statement, and also this way: [expr $f1, $f2, $f3; if ($f3 0, $f1 + $f2, $f1 - $f2)] Can someone explain to me the proper syntax for this? D. ps... gotta love the fact I can copy/paste text in and out of objects etc these days! -- http://www.padovani.googlepages.com ___ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management - http://lists.puredata.info/listinfo/pd-list
Re: [PD] [expr] for if, then, else?
Derek Holzer wrote: So I try: [expr $f1, $f2, $f3; this is the problem, delete that section ___ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management - http://lists.puredata.info/listinfo/pd-list
Re: [PD] [expr] for if, then, else?
Thanks all for sorting me out! D. -- ::: derek holzer ::: http://blog.myspace.com/macumbista ::: http://www.vimeo.com/macumbista ::: ---Oblique Strategy # 175: What are the sections sections of? Imagine a caterpillar moving ___ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management - http://lists.puredata.info/listinfo/pd-list
