Problem found with PERL6LIB environment variable (cont)
ls, Also seems to go wrong for RAKUDOLIB Example (in tcsh shell); $ setenv RAKUDOLIB .:lib:/home/marcel/Software/lib/perl6/lib $ setenv PERL6LIB .:lib:/home/marcel/Software/lib/perl6/lib $ perl6 some-program.pl6 some-program.pl6 .. ===SORRY!=== Could not find Semi-xml in any of: file#.:lib:/home/marcel/Software/lib/perl6/lib file#.:lib:/home/marcel/Software/lib/perl6/lib file#/home/marcel/.perl6/2015.05-139-g2281689/lib inst#/home/marcel/.perl6/2015.05-139-g2281689 file#/home/marcel/Software/lib/perl6/share/perl6/lib file#/home/marcel/Software/lib/perl6/share/perl6/vendor/lib file#/home/marcel/Software/lib/perl6/share/perl6/site/lib inst#/home/marcel/Software/lib/perl6/share/perl6 inst#/home/marcel/Software/lib/perl6/share/perl6/vendor inst#/home/marcel/Software/lib/perl6/share/perl6/site Now both aren't split on the colon to get multiple paths. Greetings, Marcel Timmerman
Problem found with PERL6LIB environment variable
ls, Found another problem in the new rakudo (understood that was from 4/8). Version: 'This is perl6 version 2015.05-139-g2281689 built on MoarVM version 2015.05-49-g07fbd62' It seems that perl6 doesn't understand the environment variable PERL6LIB anymore. Example (in tcsh shell); $ setenv PERL6LIB .:lib:/home/marcel/Software/lib/perl6/lib $ perl6 some-program.pl6 some-program.pl6 .. ===SORRY!=== Could not find Semi-xml in any of: file#.:lib:/home/marcel/Software/lib/perl6/lib file#/home/marcel/.perl6/2015.05-139-g2281689/lib inst#/home/marcel/.perl6/2015.05-139-g2281689 file#/home/marcel/Software/lib/perl6/share/perl6/lib file#/home/marcel/Software/lib/perl6/share/perl6/vendor/lib file#/home/marcel/Software/lib/perl6/share/perl6/site/lib inst#/home/marcel/Software/lib/perl6/share/perl6 inst#/home/marcel/Software/lib/perl6/share/perl6/vendor inst#/home/marcel/Software/lib/perl6/share/perl6/site You can find the PERL6LIB text back in the first line of the error message. It isn't split on the colon to get multiple paths. Greetings, Marcel Timmerman
Re: [perl #125334] min(+'a', +'a').say prints Inf but should produce an error
On Mon, Jun 08, 2015 at 06:08:33AM -0700, Will Coleda via RT wrote: I agree that this should be throwing the same conversion error. I disagree to the extent that making min() throw the conversion error seems to go against the purpose of designing soft/lazy Failure types into Perl 6 in the first place. Sometimes we speak about not having the entire rocket explode simply because of a few errors in the input set. In this case, min() is designed to silently ignore undefined values in its calculations. Since in this example all of the input values were undefined, min returned its 0-arg case of Inf. Perhaps an argument could be made that if min() is invoked on a list consisting only of undefined values, it should return the first (undefined) value instead of Inf. In other words, undefined values end up in this middle-region between lowest defined value and Inf, or something like that. At any rate, at this moment it's more of a specification issue than an actual rakudobug. Pm
Re: Problem found with PERL6LIB environment variable
On Mon, Jun 8, 2015 at 3:09 PM, Fields, Christopher J cjfie...@illinois.edu wrote: I had the same problem recently, tied to the revised path names (e.g. the ‘file#’ prefix). Any reason for the change? Kinda caught me by surprise. It's so that there can be things that are not directories of files that can be sources of modules (think: database, or a custom object that can look up modules somewhere else and import them from there). IIRC the colon separator was replaced with a semicolon? -- brandon s allbery kf8nh sine nomine associates allber...@gmail.com ballb...@sinenomine.net unix, openafs, kerberos, infrastructure, xmonadhttp://sinenomine.net
Re: Problem found with PERL6LIB environment variable
Hi, you might use this: say $*DISTRO.cur-sep rakudo-moar 228168: OUTPUT«,» Am 08.06.2015 um 21:17 schrieb Brandon Allbery: On Mon, Jun 8, 2015 at 3:09 PM, Fields, Christopher J cjfie...@illinois.edu mailto:cjfie...@illinois.edu wrote: I had the same problem recently, tied to the revised path names (e.g. the ‘file#’ prefix). Any reason for the change? Kinda caught me by surprise. It's so that there can be things that are not directories of files that can be sources of modules (think: database, or a custom object that can look up modules somewhere else and import them from there). IIRC the colon separator was replaced with a semicolon? -- brandon s allbery kf8nh sine nomine associates allber...@gmail.com mailto:allber...@gmail.com ballb...@sinenomine.net mailto:ballb...@sinenomine.net unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net
Re: Problem found with PERL6LIB environment variable
I had the same problem recently, tied to the revised path names (e.g. the ‘file#’ prefix). Any reason for the change? Kinda caught me by surprise. chris On Jun 8, 2015, at 11:51 AM, mt1957 mt1...@gmail.com wrote: ls, Found another problem in the new rakudo (understood that was from 4/8). Version: 'This is perl6 version 2015.05-139-g2281689 built on MoarVM version 2015.05-49-g07fbd62' It seems that perl6 doesn't understand the environment variable PERL6LIB anymore. Example (in tcsh shell); $ setenv PERL6LIB .:lib:/home/marcel/Software/lib/perl6/lib $ perl6 some-program.pl6 some-program.pl6 .. ===SORRY!=== Could not find Semi-xml in any of: file#.:lib:/home/marcel/Software/lib/perl6/lib file#/home/marcel/.perl6/2015.05-139-g2281689/lib inst#/home/marcel/.perl6/2015.05-139-g2281689 file#/home/marcel/Software/lib/perl6/share/perl6/lib file#/home/marcel/Software/lib/perl6/share/perl6/vendor/lib file#/home/marcel/Software/lib/perl6/share/perl6/site/lib inst#/home/marcel/Software/lib/perl6/share/perl6 inst#/home/marcel/Software/lib/perl6/share/perl6/vendor inst#/home/marcel/Software/lib/perl6/share/perl6/site You can find the PERL6LIB text back in the first line of the error message. It isn't split on the colon to get multiple paths. Greetings, Marcel Timmerman
Re: How to do a substring replacement in Perl 6
On Jun 8, 2015, at 3:51 PM, Douglas E. Miles d...@veritablesoftware.com wrote: Hi all! From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks! Method form: $ perl6 -e 'my $s = abc; $s.substr-rw(1,1) = z; say $s;' azc Function form: $ perl6 -e 'my $s = abc; substr-rw($s, 1,1) = z; say $s;' azc I also do not see substr-rw in doc.perl6.org. It needs to be added. In the meantime, you can find it here: http://design.perl6.org/S32/Str.html — Hope this helps, Bruce Gray (Util of PerlMonks)
panda occurrence of deprecated code message
l.s. Running newest panda code on newest perl6 (This is perl6 version 2015.05-139-g2281689 built on MoarVM version 2015.05-49-g07fbd62). $ panda list ... Method for (from Any) seen at: /home/marcel/Software/Packages/panda/lib/Panda/App.pm, lines 51,54 Deprecated since v2015.5, will be removed with release v2015.9! Please use flatmap instead. Marcel Timmerman
How to do a substring replacement in Perl 6
Hi all! From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks!
Re: How to do a substring replacement in Perl 6
Hi Douglas, From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks! I believe `substr-rw` is what you're looking for: $ perl6 my $s = The black cat climbed the green tree; The black cat climbed the green tree my $z = substr-rw($s, 14, 7) = jumped from; jumped $s.say The black cat jumped from the green tree As far as I know, not all of its behaviour has been implemented yet (FWIW it looks like it shouldn't have returned jumped above; my guess is that it should have been climbed. Nevertheless, it seems to do that which you're looking for. Hope that helps! Cheers, Paul
[perl6/specs] 555788: Correct to - too
Branch: refs/heads/master Home: https://github.com/perl6/specs Commit: 55578889f62c345a325d0f54db72d4b44434a819 https://github.com/perl6/specs/commit/55578889f62c345a325d0f54db72d4b44434a819 Author: Paul Cochrane p...@liekut.de Date: 2015-06-08 (Mon, 08 Jun 2015) Changed paths: M S32-setting-library/Str.pod Log Message: --- Correct to - too
Re: Problem found with PERL6LIB environment variable
On 06/08/2015 09:24 PM, Tobias Leich wrote: say $*DISTRO.cur-sep Hi Tobias, It returns a comma. I've used this in the path and processing is now ok. I was stuck with panda unable to do anything. As a workaround I can continue now. Hopefully this separator will be set back to ':' again. Greets, Marcel
Re: How to do a substring replacement in Perl 6
Thanks Paul! On 6/8/2015 2:46 PM, Paul Cochrane wrote: Hi Douglas, From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks! I believe `substr-rw` is what you're looking for: $ perl6 my $s = The black cat climbed the green tree; The black cat climbed the green tree my $z = substr-rw($s, 14, 7) = jumped from; jumped $s.say The black cat jumped from the green tree As far as I know, not all of its behaviour has been implemented yet (FWIW it looks like it shouldn't have returned jumped above; my guess is that it should have been climbed. Nevertheless, it seems to do that which you're looking for. Hope that helps! Cheers, Paul
Re: How to do a substring replacement in Perl 6
Thanks Bruce! On 6/8/2015 4:04 PM, Bruce Gray wrote: On Jun 8, 2015, at 3:51 PM, Douglas E. Miles d...@veritablesoftware.com wrote: Hi all! From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks! Method form: $ perl6 -e 'my $s = abc; $s.substr-rw(1,1) = z; say $s;' azc Function form: $ perl6 -e 'my $s = abc; substr-rw($s, 1,1) = z; say $s;' azc I also do not see substr-rw in doc.perl6.org. It needs to be added. In the meantime, you can find it here: http://design.perl6.org/S32/Str.html — Hope this helps, Bruce Gray (Util of PerlMonks)
Re: How to do a substring replacement in Perl 6
On Jun 8, 2015, at 3:51 PM, Douglas E. Miles d...@veritablesoftware.com wrote: Hi all! From http://perldoc.perl.org/functions/substr.html: substr has a 4th argument (or you can use substr as an lvalue) for replacement. substr EXPR,OFFSET,LENGTH,REPLACEMENT From http://doc.perl6.org/routine/substr I don't see any way to do a replacement. What is the idiomatic way of doing a positional string replacement in Perl 6? Thanks! Method form: $ perl6 -e 'my $s = abc; $s.substr-rw(1,1) = z; say $s;' azc Function form: $ perl6 -e 'my $s = abc; substr-rw($s, 1,1) = z; say $s;' azc I also do not see substr-rw in doc.perl6.org. It needs to be added. In the meantime, you can find it here: http://design.perl6.org/S32/Str.html — Hope this helps, Bruce Gray (Util of PerlMonks)
Re: [perl #125352] [BUG] Empty object hash listifies to Nil
Fixed with 2281689a0f9e337de935
Liz
On 07 Jun 2015, at 13:57, (via RT) perl6-bugs-follo...@perl.org wrote:
# New Ticket Created by
# Please include the string: [perl #125352]
# in the subject line of all future correspondence about this issue.
# URL: https://rt.perl.org/Ticket/Display.html?id=125352
19:43:05raydiak | m: say (my %h).list.perl
19:43:05 +camelia | rakudo-moar 442a56: OUTPUT«()»
19:43:14raydiak | m: say (my %h{Any}).list.perl
19:43:15 +camelia | rakudo-moar 442a56: OUTPUT«Nil»
19:44:00 masak | raydiak: I don't see why that latter one should be Nil
when the former isn't.
19:44:10 jnthn | Me either
19:44:34raydiak | nor me
19:44:38 masak | even moreso since ISTR Nil was decoupled from meaning
undefined empty list recently.
19:45:06 masak | raydiak: please rakudobug-submit, kthx.
[perl #125334] min(+'a', +'a').say prints Inf but should produce an error
I agree that this should be throwing the same conversion error. Here's probably why it's giving Inf, though: $ perl6 say min() Inf say max() -Inf -- Will Coke Coleda
