Re: [perl #130887] [BUG] .perl omits backtrace of exception

2017-02-28 Thread Zefram 
Zoffix Znet via RT wrote:
>Only public attributes of an object get dumped in .perl's output,
>and backtrace isn't one:

That's a fine default, but a problem in this case.  The .backtrace method
is public, so .perl.EVAL ought to be round-tripping the data that it
exposes, however that's stored.

-zefram

[perl #130887] [BUG] .perl omits backtrace of exception

2017-02-28 Thread Zoffix Znet via RT 
On Mon, 27 Feb 2017 14:35:17 -0800, zef...@fysh.org wrote:
> > try { my Int $a; $a = "foo" }; say ?$!.backtrace; say
> > ?$!.perl.EVAL.backtrace
> True
> False
> 
> .perl.EVAL is failing to round-trip the exception object, as
> demonstrated
> by the differing truthiness of the value returned by .backtrace.
> 
> -zefram

Only public attributes of an object get dumped in .perl's output, and backtrace 
isn't one:

$ perl6 -e 'class Foo { has $!foo = 42; has $.bar = 72 }.new.perl.say'
Foo.new(bar => 72)

[perl #130887] [BUG] .perl omits backtrace of exception

2017-02-27 Thread via RT 
# New Ticket Created by  Zefram 
# Please include the string:  [perl #130887]
# in the subject line of all future correspondence about this issue. 
# https://rt.perl.org/Ticket/Display.html?id=130887 >


> try { my Int $a; $a = "foo" }; say ?$!.backtrace; say ?$!.perl.EVAL.backtrace
True
False

.perl.EVAL is failing to round-trip the exception object, as demonstrated
by the differing truthiness of the value returned by .backtrace.

-zefram