The fact that something can be accomplished in Perl doesn't necessarily mean
its the best or most desirable way to do it. I respect the programming
abilities, but
grep { ref($a) eq ref($b) } @b)
is far less intuitive than the proposal. I could perhaps dig into my distant
memory and explain how to accomplish something like this with PDP-8
front-panel switches, but that doesn't mean that we should not attempt a
loftier solution.
IMHO Perl should add a plethora of higher-order functions for arrays and
hashes, and from the chatter here I think a lot of people agree. Put them
there and if people don't want to use them, fine. Give us lots of ways to do
things- we know that's Perlish.
Personally, I don't like the "in" choice- I favor symbols over words, but
its better than not having it at all. Conflicts with barewords, especially
in hash refs, can be a problem. Do away that the conflict by favoring
symbols over words.
Ed
-
From: Garrett Goebel [EMAIL PROTECTED]
To: 'Jonas Liljegren' [EMAIL PROTECTED], [EMAIL PROTECTED]
Subject: RE: $a in @b
Date: Wed, 6 Sep 2000 09:43:03 -0500
From: Jonas Liljegren [mailto:[EMAIL PROTECTED]]
Does any other RFC give the equivalent to an 'in' operator?
I have a couple of times noticed that beginners in programming want to
write if( $a eq ($b or $c or $d)){...} and expects it to mean
if( $a eq $b or $a eq $c or $a eq $d ){...}.
I think it's a natural human reaction to not be repetative. An 'in'
operator will help here. It could be something like this:
$a in @b; # Has @b any element exactly the same as $a
$a == in @b; # Is any element numericaly the same as $a
$a eq in @b;
$a in @b; # Is $a bigger than any element in @b?
$a not in @b; # Yes. Make 'not' context dependent modifier for in.
grep { ref($a) eq ref($b) } @b) # Same type?
grep { $a == $_ } @b)
grep { $a eq $_ } @b)
grep { $a $_ } @b)
(grep { $a != $_ } @b) == @b)
Garrett
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