Re: Easier way to load a buffer?
> You could think: what does "comb(2)" do? Perhaps look at the documentation? > And then maybe realize that Simon forgot that the comb(2) should be a method > on $hex? Otherwise, how would it know what to parse? Ah, I did wonder why $hex wasn't in the 2nd line in any way. > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 > my Buf $b=Buf.new($hex.comb(2).map( *.parse-base(16) )); Buf:0x<2A 54 FF 53 A5 F1 D3 6F 1C EA 7E 61 FC 37 A2 0D 54 A7 7F E7 B7 08> So, take $hex 2 at a time and run that through the parse-base(16), assigning it to $buf From: Elizabeth Mattijsen Sent: Friday, June 10, 2022 5:28 PM To: ToddAndMargo via perl6-users Subject: Re: Easier way to load a buffer? CAUTION - EXTERNAL: > On 10 Jun 2022, at 23:28, ToddAndMargo via perl6-users > wrote: > >>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users >>> mailto:perl6-users@perl.org>> wrote: >>>Hi All, >>>I am looking for an easier way to load a buffer. >>>I know about this way >>>[4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); >>>Buf:0x<2A 54 FF 53> >>>I would like to do it on one big blast: >>>my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); >>>Cannot unbox 170 bit wide bigint into native integer >>>But do not know the proper syntax. >>>Any words of wisdom? Am I stuck with the hard way? >>>Many thanks, >>>-T > > On 6/10/22 08:36, Simon Proctor wrote: >> So Buf is expecting a list of integers. If' you've got one long one in a >> string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split >> it into smaller values so something like this? >> my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; >> my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); >> Which does the trick I think. > > > [0] > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; > 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 > [1] > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); > ===SORRY!=== Error while compiling: > Calling comb(Int) will never work with signature of the proto ($, $, $?, *%) > --> my Buf $b=Buf.new(⏏comb(2).map( *.parse-base(16) )); > [1] > You could think: what does "comb(2)" do? Perhaps look at the documentation? And then maybe realize that Simon forgot that the comb(2) should be a method on $hex? Otherwise, how would it know what to parse? I know it is hard to think when you're in a hurry. But you should really learn to be able to read code, instead of copying examples only and not understanding *how* they work. CAUTION - EXTERNAL EMAIL: This email originated outside the Judiciary. Exercise caution when opening attachments or clicking on links.
Re: Easier way to load a buffer?
On 6/10/22 07:49, ToddAndMargo via perl6-users wrote: Hi All, I am looking for an easier way to load a buffer. I know about this way [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); Buf:0x<2A 54 FF 53> I would like to do it on one big blast: my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); Cannot unbox 170 bit wide bigint into native integer But do not know the proper syntax. Any words of wisdom? Am I stuck with the hard way? Many thanks, -T Came up with a Raku way of doing what I want. And dropping the need for Buf at the same time: > use BigRoot; > BigRoot.precision = 40; 40 > my $root5 = BigRoot.newton's-sqrt: 5; > $y = sprintf $root5.base(16) 2.3C6EF372FE94F82BE73980C0B9DB90681F > $y ~~ s/ $( Q[.] ) //; ｢.｣ > say $y 23C6EF372FE94F82BE73980C0B9DB90681F Add a loop and and some chr's and ord's and happy camping will proceed! :-) -T
Re: Easier way to load a buffer?
> On 10 Jun 2022, at 23:28, ToddAndMargo via perl6-users > wrote: > >>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users >>> mailto:perl6-users@perl.org>> wrote: >>> Hi All, >>>I am looking for an easier way to load a buffer. >>>I know about this way >>>[4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); >>>Buf:0x<2A 54 FF 53> >>>I would like to do it on one big blast: >>>my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); >>>Cannot unbox 170 bit wide bigint into native integer >>>But do not know the proper syntax. >>>Any words of wisdom? Am I stuck with the hard way? >>>Many thanks, >>>-T > > On 6/10/22 08:36, Simon Proctor wrote: >> So Buf is expecting a list of integers. If' you've got one long one in a >> string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split >> it into smaller values so something like this? >> my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; >> my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); >> Which does the trick I think. > > > [0] > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; > 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 > [1] > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); > ===SORRY!=== Error while compiling: > Calling comb(Int) will never work with signature of the proto ($, $, $?, *%) > --> my Buf $b=Buf.new(⏏comb(2).map( *.parse-base(16) )); > [1] > You could think: what does "comb(2)" do? Perhaps look at the documentation? And then maybe realize that Simon forgot that the comb(2) should be a method on $hex? Otherwise, how would it know what to parse? I know it is hard to think when you're in a hurry. But you should really learn to be able to read code, instead of copying examples only and not understanding *how* they work.
Re: Easier way to load a buffer?
On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users mailto:perl6-users@perl.org>> wrote: Hi All, I am looking for an easier way to load a buffer. I know about this way [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); Buf:0x<2A 54 FF 53> I would like to do it on one big blast: my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); Cannot unbox 170 bit wide bigint into native integer But do not know the proper syntax. Any words of wisdom? Am I stuck with the hard way? Many thanks, -T On 6/10/22 08:36, Simon Proctor wrote: So Buf is expecting a list of integers. If' you've got one long one in a string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split it into smaller values so something like this? my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); Which does the trick I think. [0] > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 [1] > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); ===SORRY!=== Error while compiling: Calling comb(Int) will never work with signature of the proto ($, $, $?, *%) --> my Buf $b=Buf.new(⏏comb(2).map( *.parse-base(16) )); [1] > -- ~~ Computers are like air conditioners. They malfunction when you open windows ~~
Re: Easier way to load a buffer?
> On 10 Jun 2022, at 22:47, ToddAndMargo via perl6-users
> wrote:
>
>>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users
>>> mailto:perl6-users@perl.org>> wrote:
>>> Hi All,
>>>I am looking for an easier way to load a buffer.
>>>I know about this way
>>>[4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53);
>>>Buf:0x<2A 54 FF 53>
>>>I would like to do it on one big blast:
>>>my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78);
>>>Cannot unbox 170 bit wide bigint into native integer
>>>But do not know the proper syntax.
>>>Any words of wisdom? Am I stuck with the hard way?
>>>Many thanks,
>>>-T
>
> On 6/10/22 08:36, Simon Proctor wrote:
>> So Buf is expecting a list of integers. If' you've got one long one in a
>> string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split
>> it into smaller values so something like this?
>> my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78";
>> my Buf $b=Buf.new(comb(2).map( *.parse-base(16) ));
>> Which does the trick I think.
>
> What does the * i *.parse-base do?
*.parse-base(16) is an example of a WhateverCode object.
It is basically syntactic sugar for easy creation of Callable blocks. In this
case,
it created -> $_ { .parse-base(16) }
The * is interpreted in the Raku Grammar as a sign to create a WhateverCode
object: it basically
represents the $_ in the signature of the created Block, and of course the $_
inside that block.:
Re: Easier way to load a buffer?
On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users mailto:perl6-users@perl.org>> wrote: Hi All, I am looking for an easier way to load a buffer. I know about this way [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); Buf:0x<2A 54 FF 53> I would like to do it on one big blast: my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); Cannot unbox 170 bit wide bigint into native integer But do not know the proper syntax. Any words of wisdom? Am I stuck with the hard way? Many thanks, -T On 6/10/22 08:36, Simon Proctor wrote: So Buf is expecting a list of integers. If' you've got one long one in a string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split it into smaller values so something like this? my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); Which does the trick I think. What does the * i *.parse-base do?
Re: Easier way to load a buffer?
So Buf is expecting a list of integers. If' you've got one long one in a string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split it into smaller values so something like this? my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); Which does the trick I think. On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users < perl6-users@perl.org> wrote: > Hi All, > > I am looking for an easier way to load a buffer. > > I know about this way > > [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); > Buf:0x<2A 54 FF 53> > > I would like to do it on one big blast: > > my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); > Cannot unbox 170 bit wide bigint into native integer > > But do not know the proper syntax. > > Any words of wisdom? Am I stuck with the hard way? > > Many thanks, > -T > -- Simon Proctor Cognoscite aliquid novum cotidie http://www.khanate.co.uk/
Easier way to load a buffer?
Hi All, I am looking for an easier way to load a buffer. I know about this way [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); Buf:0x<2A 54 FF 53> I would like to do it on one big blast: my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); Cannot unbox 170 bit wide bigint into native integer But do not know the proper syntax. Any words of wisdom? Am I stuck with the hard way? Many thanks, -T
