[pgadmin-support] Question about creating a new server

2005-06-15 Thread Danny Gaethofs
Dear all,

Running postgresql 8.0 on windows xp.

I tried to create a second server from within
pgadminiii. 

address = localhost
Service = pgsql-8.0
user = postgres
port = 5433

When I do so I get the error message
error connecting to the server: could not connect to
server: connection refused (.)
Is the server running on host '127.
and accepting tcp/ip connection on port 5433

Can anyone explain me why it is not possible to create
a new server?  

If I would create a new server using initdb would it
then become visible in pgadminiii?

regards,
Danny



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Re: [pgadmin-support] Question about creating a new server

2005-06-15 Thread Diego Gil
Hi,

I suppose you mean a "second server connection". Do you have a working
connection ?. 

I don't work in Windows but these topic is a recurring one in this list.
Maybe is a firewall preventing you to connect, but it doesn't  make
sense is there is a actual working connection. 

It is obvious, but are you sure postgresql is running ?.

Diego.

El mié, 15-06-2005 a las 09:59 -0700, Danny Gaethofs escribió:
> Dear all,
> 
> Running postgresql 8.0 on windows xp.
> 
> I tried to create a second server from within
> pgadminiii. 
> 
> address = localhost
> Service = pgsql-8.0
> user = postgres
> port = 5433
> 
> When I do so I get the error message
> error connecting to the server: could not connect to
> server: connection refused (.)
> Is the server running on host '127.
> and accepting tcp/ip connection on port 5433
> 
> Can anyone explain me why it is not possible to create
> a new server?  
> 
> If I would create a new server using initdb would it
> then become visible in pgadminiii?
> 
> regards,
> Danny
> 
> 
>   
> __ 
> Discover Yahoo! 
> Get on-the-go sports scores, stock quotes, news and more. Check it out! 
> http://discover.yahoo.com/mobile.html
> 
> ---(end of broadcast)---
> TIP 9: the planner will ignore your desire to choose an index scan if your
>   joining column's datatypes do not match
> 
> 


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