Re: [HACKERS] postgresql regular expr bug?
2009/6/14 hubert depesz lubaczewski : > On Sun, Jun 14, 2009 at 08:15:55AM +0200, Pavel Stehule wrote: >> postgres=# select '10' ~ '[0..9]+$'; >> ?column? >> -- >> t >> (1 row) > > regexp '[0..9]+$' tests is given strings containst at the end substring > containing only characters "0", "9" and ".". > and yes, it does - the last character is 0, so it matches. > >> postgres=# select '10' ~ '^[0..9]+$'; >> ?column? >> -- >> f >> (1 row) > > this regexp checks if whole string is built only with characters "0", > "9", and ".". and it is not - the first character is "1" which is not > the character list you provided. > > basically ".." has no special meaning in regexps, especially within [] - > i.e. it is just a dot. > my mistake thank you Pavel > Best regards, > > depesz > > -- > Linkedin: http://www.linkedin.com/in/depesz / blog: http://www.depesz.com/ > jid/gtalk: dep...@depesz.com / aim:depeszhdl / skype:depesz_hdl / gg:6749007 > -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
Re: [HACKERS] postgresql regular expr bug?
On Sun, Jun 14, 2009 at 08:15:55AM +0200, Pavel Stehule wrote: > postgres=# select '10' ~ '[0..9]+$'; > ?column? > -- > t > (1 row) regexp '[0..9]+$' tests is given strings containst at the end substring containing only characters "0", "9" and ".". and yes, it does - the last character is 0, so it matches. > postgres=# select '10' ~ '^[0..9]+$'; > ?column? > -- > f > (1 row) this regexp checks if whole string is built only with characters "0", "9", and ".". and it is not - the first character is "1" which is not the character list you provided. basically ".." has no special meaning in regexps, especially within [] - i.e. it is just a dot. Best regards, depesz -- Linkedin: http://www.linkedin.com/in/depesz / blog: http://www.depesz.com/ jid/gtalk: dep...@depesz.com / aim:depeszhdl / skype:depesz_hdl / gg:6749007 -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
Re: [HACKERS] postgresql regular expr bug?
On Sun, Jun 14, 2009 at 1:15 AM, Pavel Stehule wrote: > can somebody explain this behave? > > postgres=# select '10' ~ e'^\\d+$'; > ?column? > -- > t > (1 row) > ok > > postgres=# select '10' ~ '[0..9]+$'; > ?column? > -- > t > (1 row) > ok > > postgres=# select '10' ~ '^[0..9]+$'; > ?column? > -- > f > (1 row) Try '^[0-9]+$'. -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
[HACKERS] postgresql regular expr bug?
Hello can somebody explain this behave? postgres=# select '10' ~ e'^\\d+$'; ?column? -- t (1 row) ok postgres=# select '10' ~ '[0..9]+$'; ?column? -- t (1 row) ok postgres=# select '10' ~ '^[0..9]+$'; ?column? -- f (1 row) ? postgres=# select version(); version --- PostgreSQL 8.3.7 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 4.4.0 20090506 (Red Hat 4.4.0-4) (1 row) tested on fedora 11 Regards Pavel Stehule -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
