Re: [SQL] Add: Special sort querstion

2009-04-01 Thread Dirk Jagdmann
I think it can not be done with default PostgreSQL functions and
operators, because you must compare two different columns of two rows
depending which row is on either side of the  comparision.

But I think you can do this with the following steps:

1) create a new type as a 4-tupel of start_lat, end_lat, start_lng, end_lng.
2) write a comparison function for this type
3) write a SQL-Function to convert 4 values into your new type (for
example: ToMyType(start_lat, end_lat, start_lnd, end_lng) returns
MyType...)
4) use ToMyType in the order clause of your select

If this would work, I'm interested in a working example code :-)

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--- Dirk Jagdmann
 http://cubic.org/~doj
- http://llg.cubic.org

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Re: [SQL] Add: Special sort querstion

2009-04-01 Thread Dirk Jagdmann
I think it can not be done with default PostgreSQL functions and
operators, because you must compare two different columns of two rows
depending which row is on either side of the  comparision.

But I think you can do this with the following steps:

1) create a new type as a 4-tupel of start_lat, end_lat, start_lng, end_lng.
2) write a comparison function for this type
3) write a SQL-Function to convert 4 values into your new type (for
example: ToMyType(start_lat, end_lat, start_lnd, end_lng) returns
MyType...)
4) use ToMyType in the order clause of your select

If this would work, I'm interested in a working example code :-)

-- 
--- Dirk Jagdmann
 http://cubic.org/~doj
- http://llg.cubic.org

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Re: [SQL] Add: Special sort querstion

2009-04-01 Thread Scott Marlowe
On Fri, Mar 27, 2009 at 6:10 AM, Dominik Piekarski
d.piekar...@vivawasser.de wrote:
 Oh, actually every row of the same id-range has the same start_lat/start_lng
 coordinates as the predecessors end_lat/end_lng coordinates. But the
 question remains the same. Is there a way to do something like ORDER BY
 (start_lat = end_lat AND start_lng = end_lng) ? Or maybe another way to
 achieve the same result?

Would something like

order by start_lat-endlat, start_lng-end_lng

OR

case when start_lat=end_lat AND start_lng=end_lng then 0 else 1 end

???

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