Re: [PHP-DB] MySQL editor

2003-06-19 Thread Achilles Maroulis
MySQL CONTROL CENTER from mysql.org (very nice)
SQLYOG from sqlyog.com
PHPMYADMIN  from phpmyadmin.net (web interface)

- Original Message -
From: "Angelo Zanetti" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, June 19, 2003 11:40 AM
Subject: [PHP-DB] MySQL editor


Hi all.

I need to get a program (interface) for MySQL, I was using MySQL Front but
they've discontinued its use.

Any suggestions.

thanx in advance

-Angelo


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[PHP-DB] Having more than one id in the same field

2002-11-10 Thread Achilles Maroulis

Hi. I have a database designing question to ask.
I want to build a table of events. Among the other fields there must be a
field that holds the 'responsible organization' of the event. This
organization of course will be responsible for other events as well so I
have to create another table that holds the organizations (id, name, phones,
director etc) and then just pull the organization id to the events table.
The problem is that it happens too often to have 2 organizations responsible
for the same event so I'll have to add them both to the events table in the
same record.

How do you advice me to do that?
I thought that I could use a text field to hold the ids and then when
searching the database just change the MySQL command from
"...where events.id='$id'..." (As it would be if only one id was going to be
used) to
"...where '$id' in (events.ids)..." or maybe something using LIKE.

Do you think it can be done this way? Apart from the responsible
organization I may have other fields in the same table having the same
problem (for example: the event visitors are staying in one hotel and I want
to hold control of the hotels as well. Maybe 2 hotels are used instead of
one). If I solve my problem this way, do you think that it will be too
difficult or 'heavy' to have more than one condition like this in my
queries?
Do you think of any other way?

Thanx in advance
Achilles


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[PHP-DB] Variables coming from forms

2002-09-21 Thread Achilles Maroulis

Hi. I have posted this thread before but didn't come to a solution so I try
again.

I've installed Apache 2.0 and PHP 4.2.3 (both with the msi installers) on
Windows 2000 Pro.
The problem I have is that I get the message

Notice: Undefined variable: var_name in 

every time I pass a new variable into another page whether this happens
using the URL or a form or even sessions.

The strange thing is that if I run phpinfo() in the same page (where the
variable is considered to be undefined) I see that my variables do exist in
the variables section of phpinfo.


For example. If I use a form to pass a variable in a php file like this:

  
  


and have the var.php like this:


I'll get the message:
Notice: Undefined variable: var in C:\Progr.\htdocs\var.php on line 2

while I'll also get a line like this in the variables section of phpinfo():
Variable  Value
_GET["var"] the value I typed before

I think this is really strange. Has anyone something to suggest?

Thanx in advance!!
Achilles


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Re: [PHP-DB] Passwords

2002-04-23 Thread Achilles Maroulis

Thanx guys!!


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[PHP-DB] Passwords

2002-04-22 Thread Achilles Maroulis

Hi folks.

I have a quetion for you which maybe a little silly as I'm still new here..
I want to build a database in which access will have only registered memebers, so I 
need to protect it. The database will have over 10 records and hopefully over 1000 
users-visitors. Everyone of them is going to have his own password. I suppose I will 
have to build a table with usernames and encrypted passwords but what I don't know is 
how to protect the pages not to be seen without authorization. At first I thought 
about the .htaccess and .htpasswd files but I'm not sure yet...
Can anyone suggest the best way to protect my database? If it is to complicated to be 
explained in an email please suggest just the functions names and I'll try to find the 
way...

Thanx
Achilles