Re: [PHP-DB] Placing a form on a page
Hi, Check if you have created a class in which you have already mentioned the font size. If that so look it and change it inside the class. Also, check if you have created or mentioned the font size in CSS. I hope this will help you. On Mon, May 6, 2013 at 6:30 PM, Jim Giner jim.gi...@albanyhandball.comwrote: Centering a form is a simple process - as you stated about your first example form. So - obviously the problem is in all that other crap you presented to us, expecting us to do your debugging. I still don't know what you want to do - perhaps you could have given us a para on what it is wrong. Are you trying to center multiple forms, or just align multiple forms in some fashion? Once again - learn some new stuff and develop code that is easier to read and perhaps you'll find more of your own errors. IE - read about heredocs. (That IS php!) (You might also want to read about security and protecting yourself from malicious input values.) Hope I didn't offend you again, but this post was just more of the same old Ethan Phd stuff. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- *Best, * *Gu®u CEO Founder at, www.myshopads.com *
[PHP-DB] Excel to HTML table using PHP
Hi All, I have searched all around the net and unable to find excel to html table using php. What I want is, say I have an excel sheet and I want to export the excel data to HTML table *without* *opening it*. Then I can use the HTML table for later function. Please help me with this. -- *Best, * *Gu®u*
Re: [PHP-DB] Re: confirm subscribe to php-db@lists.php.net
.cisco.com (localhost.localdomain [127.0.0.1]) by rcdn-webmail-9.cisco.com (8.13.8/8.13.8) with ESMTP id q2H8QATx023331 forphp-db-subscribe@lists.**php.netphp-db-subscr...@lists.php.net; Sat, 17 Mar 2012 08:26:10 GMT Received: from my.linux (rcdn-webmail-9.cisco.com [173.37.180.115]) by rcdn-webmail-9.cisco.com (Scalix SMTP Relay 11.4.6.13676) via ESMTP; Sat, 17 Mar 2012 08:26:09 + (UTC) Date: Sat, 17 Mar 2012 16:25:11 +0800 From: nathhuannathh...@cisco.com To: php-db-subscr...@lists.php.net Message-ID:4F644A67.6080004@**cisco.com 4f644a67.6080...@cisco.com Subject: subscribe x-scalix-Hops: 1 User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:10.0.1) Gecko/20120216 Thunderbird/10.0.1 MIME-Version: 1.0 Content-Type: text/plain; charset=US-ASCII; format=flowed -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- *Best, * *Gu®u*
[PHP-DB] Help with If else if
Hi,
Please help me with this code. I have 2 different fields in mysql table.
What I want is if the field is empty don't show the image. Please look at
the code below.
?php
if($search-plugin-ListViewValue()==)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($search-facebook-ListViewValue()==)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
else if($search-plugin-ListViewValue()==
$search-facebook-ListViewValue()==)
{
echo ;
}
else
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a'.'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
--
*Best,
*
*Gu®u*
Re: [PHP-DB] Help with If else if
The issue is both the images are echoing and no if else statement is working. On Tue, Mar 13, 2012 at 7:22 PM, Matijn Woudt tijn...@gmail.com wrote: On Tue, Mar 13, 2012 at 1:03 PM, Gu®u nagendra802...@gmail.com wrote: Hi, Please help me with this code. I have 2 different fields in mysql table. What I want is if the field is empty don't show the image. Please look at the code below. I have looked at it. Maybe you should tell what is wrong, what it outputs currently, and what it should output. Or perhaps, which errors you get if any? - Matijn -- *Best, * *Gu®u*
Re: [PHP-DB] Help with If else if
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only twitter,
if variable twitter has no value and facebook has a value echo out facebook
only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
On Tue, Mar 13, 2012 at 8:54 PM, Michael Stowe m...@mikestowe.com wrote:
From looking at your code, the issue is that your if statements are
checking for the same criteria as your else statements, meaning that if the
string is empty () the if statements will be triggered, and since the if
statements are true, the elseif statement will not be. Or if the string
isn't empty, neither the if or the elseif statements will be triggered,
causing the else statement to be activated. Either way, the images would
be printed out. *
*
*
*
*Did you mean to do this?*
?php
if($search-plugin-ListViewValue() ==
$search-facebook-ListViewValue() == ) {
// Neither one has a value
} elseif ($search-plugin-ListViewValue() !=
$search-facebook-ListViewValue() != ) {
// Both have a Value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a' . 'a
href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
} elseif ($search-plugin-ListViewValue() != ) {
// Twitter has a value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a';
} else {
// Facebook has a value (only possible option left)
echo 'a href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
Hope that helps,
Mike
On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
---
My command is this: Love each other as I
have loved you. John 15:12
---
--
*Best,
*
*Gu®u*
Re: [PHP-DB] Help with If else if
I tried the below code too considering may be the localhost is really dumb
and we need to tell each and every condition. But still its not working :(
$tweet = $search-plugin-ListViewValue();
$fb = $search-facebook-ListViewValue();
if($tweet== $fb==)
{
echo ;
}
elseif($fb== $tweet!=)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
elseif($tweet== $fb!=)
{
echo 'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
elseif($fb!= $tweet!=)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a'.'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
On Tue, Mar 13, 2012 at 9:44 PM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 4:53 PM, Gu®u nagendra802...@gmail.com wrote:
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only
twitter,
if variable twitter has no value and facebook has a value echo out
facebook
only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
That's exactly what my code does too, except it's a bit simpler. If
mine isn't working too, then your input is probably different, try a
var_dump on the ListViewValue() items.
- Matijn
--
*Best,
*
*Gu®u*
