Re: [PHP-DB] mysqldump permissions
Give the user show view permission http://dev.mysql.com/doc/refman/5.1/en/privileges-provided.html#priv_show-view On 06/06/2011 7:57 AM, Ron Piggott ron.pigg...@actsministries.org wrote: I created a VIEW “table” yesterday. Last night when the cron job ran to back up the database I received this error: mysqldump: Couldn't execute 'show create table `bible_anagrams_rss_feed_summary`': SHOW VIEW command denied to user I use the following syntax to do the backup of the database each day within the context of a cron job: date=`date -I` ; mysqldump –uUSER –pPASS --all-databases | gzip /home/path/backup_$date.sql.gz Even when I have given the mysql backup user all the permissions available within the control panel of my web site hosting company I still get the same error. These are the permissions I have available. SELECT INSERT UPDATE DELETE INDEX CREATE TEMPORARY TABLE EXECUTE CREATE ALTER DROP LOCK TABLES REFERENCES CREATE ROUTINE How to resolve the error? Ron The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info
Re: [PHP-DB] SELECT WHERE length of content question
Have a look at this: http://dev.mysql.com/doc/refman/5.1/en/string-functions.html#function_char-length On Thu, Mar 10, 2011 at 9:49 AM, Ron Piggott ron.pigg...@actsministries.org wrote: Is there a command in mySQL that would allow me to SELECT the rows where the `fax` column is more than 11 characters long? OR Do I need to use PHP to assess this? Ron The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info
Re: [PHP-DB] Oracle PDO UTF-8 problem
Try increasing this: PDO::MYSQL_ATTR_MAX_BUFFER_SIZE
More info here: http://php.net/manual/en/ref.pdo-mysql.php
On Thu, Jan 13, 2011 at 7:23 PM, Karsten Lehmann lehm...@maqsima.de wrote:
Hello
I try to read a 2000 character long string out of database. The database is
an oracle 10g Express Edition with UTF-8 character set. To read the string
we use the PDO abstraction layer with oci-driver. If the 2000 character
contains one or more UTF-8 characters we get the problem that PDO truncate
the result of the database, with the following message:
Warning: PDOStatement::fetchAll() [pdostatement.fetchall]: column 5 data
was too large for buffer and was truncated to fit it in
C:\wamp\www\wp\bp.php on line 115
The definition of the database column is
TESTSTRING VARCHAR2(2000 CHAR)
CHAR means that we can store up to 2000 characters independent from the
encoding of the character (e.g. UTF8).
I also init the PDO with UTF8
$dbh = new PDO('oci:dbname=' . $db_name . ';charset=UTF8', $db_user,
$db_pw);
If i read the same string with java and JDBC-driver it works fine, so i can
exclude a database error.
How i have to configre PHP/PDO to be aware of the truncation of the result
string?
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Re: [PHP-DB] ON DUPLICATE KEY UPDATE
Read through this: http://dev.mysql.com/doc/refman/5.0/en/insert-on-duplicate.html, especially the last 2 paragraphs. On Sun, Nov 28, 2010 at 12:40 PM, Ron Piggott ron.pigg...@actsministries.org wrote: My question is with the syntax below: If the “ON DUPLICATE KEY UPDATE `name` = '$name'” occurs will $_SESSION['referral_clients_reference'] be populated with the mysql_insert_id() value? If not, should I just query for it? Ron mysql_query(INSERT INTO `referral_clients` ( `reference` , `name` , `paypal_email` , `last_update` ) VALUES ( NULL , '$name', '$paypal_email', CURRENT_TIMESTAMP ) ON DUPLICATE KEY UPDATE `name` = '$name';); $_SESSION['referral_clients_reference'] = mysql_insert_id(); The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info
Re: [PHP-DB] Database and Table creation
Hi Ethan, Database Creation: http://www.php.net/manual/en/function.mysql-create-db.php http://www.php.net/manual/en/function.mysql-create-db.phpAdding Tables, Extract Data: http://www.freewebmasterhelp.com/tutorials/phpmysql/1 http://www.freewebmasterhelp.com/tutorials/phpmysql/1Explore the function list on the left from the first link if you are curious. Kesavan. On Wed, Oct 20, 2010 at 9:23 AM, Ethan Rosenberg eth...@earthlink.netwrote: Dear List - Thanks for your help. Using PHP, how do I create a database, add tables to it, then add and extract data from the tables.? Sample code please. Please be aware that I am a newbie. Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] finding out if a user left our website ?
Have a look at this: https://developer.mozilla.org/en/DOM/window.onunload https://developer.mozilla.org/en/DOM/window.onunloadBut, as someone pointed out a few days ago, please do not post stuff that is not related to PHP DB. On Thu, Aug 26, 2010 at 6:32 AM, Vinay Kannan viny...@gmail.com wrote: Hello Guys, Wanted to know if there is a way for us to find out, when a user moves away from our website( closing the window and entering a different url in the address bar ) closing the window i guess, we could use the javascript onclose or something similar but for the user moving away from my website by entering a different URL is what i would like to be able to find out. Thanks, Vinay
Re: [PHP-DB] CURDATE
Try: DATE(date_accessed) = CURDATE(). Have a look at this: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_dateto understand what's happening. Regards, Kesavan. On 17/08/2010 6:26 AM, Ron Piggott ron.pigg...@actsministries.org wrote: I am wondering why: SELECT * FROM `bible_concordance_usage` WHERE `date_accessed` = CURDATE() Doesn't work when `date_accessed` is column type timestamp And What would work? Ron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Help with mysql data sorting using php
take a look at this: http://datatables.net/examples/data_sources/server_side.html On Mon, May 17, 2010 at 5:30 PM, nagendra prasad nagendra802...@gmail.comwrote: Hi Artur, I am a beginner to this stuff. So, If you or anyone can give me some example codes or may be some links for my reference that would be a great help. Best, Guru. On Mon, May 17, 2010 at 12:57 PM, Artur Ejsmont ejsmont.ar...@gmail.com wrote: Hehe. Then a method: ) just make a query builder method like 'findSongs' with all the params ( optional or mandatory ) like page, limit, sortby, filters etc. then inside build SQL based on args. Just be careful - SQL injection is your enemy here. From app pass all the args from get/ post and that's it. Good luck. On 17 May 2010 08:18, nagendra prasad nagendra802...@gmail.com wrote: DB is like more then 500MB and it will grow day by day :) On Mon, May 17, 2010 at 12:46 PM, Artur Ejsmont ejsmont.ar...@gmail.com wrote: If the DB i...
Re: [PHP-DB] Updating MySQL Database after install
You need to use the ALTER statement. doc: http://dev.mysql.com/doc/refman/5.1/en/alter-table.html http://dev.mysql.com/doc/refman/5.1/en/alter-table.htmlexample: http://www.1keydata.com/sql/sql-foreign-key.html On Wed, May 5, 2010 at 8:21 AM, Karl DeSaulniers k...@designdrumm.comwrote: Hi, I am wanting to get some pointers on how to update my MySQL database after there is already members. For eg, I am trying to set some foreign keys that were not part of my database when I installed it. There are members in that database. Can I update the database with the new .sql file without loosing my current info? If so, how? Fields in the user table have not changed except foreign keys have been assigned to it. TIA, Karl DeSaulniers Design Drumm http://designdrumm.com
Re: [PHP-DB] Calculator
http://www.javascriptkit.com/script/cut18.shtml JS based solution would be the easiest. On Wed, Mar 17, 2010 at 3:07 PM, Karl DeSaulniers k...@designdrumm.comwrote: Hello, I have been asked to see if I can set up an online calculator. I was wondering if anyone had some pointers on where I can lear/find a script that calculates percentages. The regular math part I think I can figure out. Its not a complicated calc, just basic math and percentages calc, a payment calc if you will. TIA Karl DeSaulniers Design Drumm http://designdrumm.com
Re: [PHP-DB] Upgrading PHP Version 5.1.6
Well, you can always backup your databases through phpMyAdmin (export) or from commandline using mysqldump just to be on the safer side. On Sat, Mar 6, 2010 at 12:51 PM, David McGlone da...@dmcentral.net wrote: On Friday 05 March 2010 12:35:43 Vinay Kannan wrote: Hello, I am currently using php version 5.1.6 and now m thinking of upgrading, i got php installed long time back using WAMP, i wanted to know if theres an easy way to upgrade directly, without having to remove this version, i also have a good number of databases, and it would be a pain, if i am required to uninstall the current version of wamp and then reinstall the newer version. I am not experienced at all with WAMP, because I've always used LAMP, but I'd suspect that WAMP works like LAMP and uninstalling PHP will not remove any MySQL tables. -- Blessings David M. I have been driven to my knees many times by the overwhelming conviction that I had nowhere else to go. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Prepared Statement Insert Problem
Remove the quotes around the variables in all your statements.
For example, this statement:
mysqli_stmt_bind_param($submitadmin, isss, '$numrows', '$admin',
sha1('$password'), '$email');
could be rewritten as:
mysqli_stmt_bind_param($submitadmin, isss, $numrows, $admin,
sha1($password), $email);
On Tue, Jul 21, 2009 at 8:01 PM, Jason Carson ja...@jasoncarson.ca wrote:
Hello everyone, I have a problem.
I use the following to *try* and insert data into my MySQL database...
//Variables come from a form
$username= $_POST['username'];
$password = $_POST['password'];
$email = $_POST['email'];
//Connect to the database
$connect = mysqli_connect($hostname, $dbusername, $dbpassword,
$database)or die(cannot connect);
//Find out how many rows in the database
$aidcount = mysqli_query ($connect, SELECT * FROM administrator);
$numrows = mysqli_num_rows($aidcount);
//The next 3 lines are using prepared statements to insert data but the
//second line ...mysqli_stmt_bind_param.. results in this error...
//Fatal error: Only variables can be passed by reference in file.php line
46
$submitadmin = mysqli_prepare($connect2, INSERT INTO administrator VALUES
(?, ?, ?, ?));
mysqli_stmt_bind_param($submitadmin, isss, '$numrows', '$admin',
sha1('$password'), '$email');
mysqli_stmt_execute($submitadmin);
...anyone know how I can solve this problem so I can insert data into my
database with prepared statements?
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Re: [PHP-DB] Re: [PHP] A prepared statements question
Why don't using consider using PDO for this purpose? Examples can be found
here: http://au.php.net/manual/en/pdo.prepare.php
On Sun, Jul 12, 2009 at 2:52 PM, Daniel Brown danbr...@php.net wrote:
[Redirected to PHP-DB: php...@lists.php.net]
On Sun, Jul 12, 2009 at 00:31, Jason Carsonja...@jasoncarson.ca wrote:
Hello everyone,
I am having a problem getting my prepared statements working. Here is my
setup...
index.php - authenticate.php - admin.php
1)index.php has a login form on it so when someone enters their username
the form redirects to another page I call authenticate.php.
2)In the authenticate.php file I want to use prepared statements to
interact with the MySQL database. I want to compare the username
submitted
from the form with the username in the database.
3)If the login username was legitimate then you are forwarded to
admin.php
Its step 2 I am having problems with. Here is what I have but I don't
think it makes any sense and it doesn't work.
$link = mysqli_connect($hostname, $dbusername, $password, $database);
$stmt = mysqli_prepare($link, SELECT * FROM administrators WHERE
adminusers=?);
mysqli_stmt_bind_param($stmt, 's', $username);
$result = mysqli_stmt_execute($stmt);
$count=mysqli_num_rows($result);
if($count==1){
header(location:admin.php);
} else {
echo Failure;
}
Any help is appreciated.
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Re: [PHP-DB] Get ID of ROW when using aggregate functions
there is probably a better way to achieve this, but, this is a quick solution mysql SELECT * FROM test where sallary IN (SELECT MAX(SALLARY) FROM test GROUP BY company); +++---+-+ | id | name | company | sallary | +++---+-+ | 2 | Peter | Novell| 12000 | | 3 | Steven | Microsoft | 17000 | +++---+-+ 2 rows in set (0.00 sec) the answer to your question might lie by looking at this: mysql SELECT * FROM `test` GROUP BY company; ++---+---+-+ | id | name | company | sallary | ++---+---+-+ | 1 | Jane | Microsoft | 1 | | 2 | Peter | Novell| 12000 | ++---+---+-+ 2 rows in set (0.00 sec) SQL experts here please enlighten us.. On Wed, Apr 8, 2009 at 6:54 PM, Ondrej Kulaty kopyto...@gmail.com wrote: Hi, I have following table: id int(11) name varchar(255) company varchar(255) sallary int(11) CREATE TABLE `test` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `sallary` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin2 AUTO_INCREMENT=1 ; With rows: INSERT INTO `test` (`id`, `name`, `company`, `sallary`) VALUES (1, 'Jane', 'Microsoft', 1), (2, 'Peter', 'Novell', 12000), (3, 'Steven', 'Microsoft', 17000); I want to select person from each company with a highest sallary. I run this SQL: SELECT id,name,company,MAX(sallary) FROM `test` GROUP BY company; And result is: id name company MAX( sallary ) 1 Jane Microsoft 17000 2 Peter Novell12000 Why it returned Jane (id 1) as a person with highest sallary (17000) when obviously Jane has sallary of 10 000? Thanks for any help. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Retrieving Image Location in MySQL
drop the images into a folder within your WAMP servers htdocs
directory and then update your database tables with the new location..
for security reasons you will not be able access files outside your
web directory through PHP
On Sun, Mar 8, 2009 at 11:34 AM, Sashikanth Gurram sashi...@vt.edu wrote:
Hi,
I have tried it in 3 browsers (Chrome, firefox and internet explorer) and
none of them has given me any image.
-Sashi
Phpster
wrote
Bet the image is not readable from the web server.
Bastien
Sent from my iPod
On Mar 7, 2009, at 5:04, Sashikanth Gurram sashi...@vt.edu wrote:
Hi,
Yes. But I assign the location of the image (
C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg) to the $location
variable by using the mysqli_fetch_array($data) command. I send a query to
the db and the result is obtained and the image location is stored into
$location. So it is pretty straightforward. But I cannot understand why is
it not displaying the picture after retrieving the image. Should I use any
other additional commands to display the picture? Or do I need any changes
in my PHP configuration file? I have checked the Config file and the ;
sign infront of extension=php_gd2.dll has been removed.
Thanks,
Sashi
Hello,
Does something like this work on your php script?
$location=..\..\Bldgs_lots\Burruss.jpg
OR
$location=..\Bldgs_lots\Burruss.jpg
GR
Muhsin
Sashikanth Gurram wrote:
This is the location where I have saved my images.
/C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg
/I have loaded the above location exactly into my database. But when I
call it using
/echo img src='$location' border='1' height='150' width='200'
alt='$build' ;/
It is simply giving me some blank empty space, with the name of the
picture in the blank space (Since I am using alt). So, as I see it,
the retrieval part is working fine, but the displaying of the image is
not functioning properly. I am using a WAMP server. Any kind of
suggestions are welcome.
Thanks,
Sashi
PS: For Reference, I am posting my entire code below again. The image
retrieval part is towards the end of the code.
/html
body
form action=mysqli.php method=post
br
div align=center
Building Name:select name=name
option value= Select a Building/option
option value=Military BuildingMilitary Building/option
option value=Monteith HallMonteith Hall/option
option value=New Residence Hall-Career Services SiteNew
Residence Hall-Career Services Site/option
option value=Williams HallWilliams Hall/option
option value=Women's Softball FieldWomen's Softball
Field/option
option value=Wright HouseWright House/option
/select
/div
input type=submit /
/form
img src=mysqli.php?
?php
// Connects to your Database
$host=**;
$user=***;
$password=;
$dbname=*;
$cxn=mysqli_connect($host, $user, $password, $dbname) ;
if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo Connection established successfully;
}
//Define the variables for Day and Month
$Today=date(l);
$Month=date(F);
$build=$_POST[name];
$low_speed=2.5;
$high_speed=4;
$hour=date(G);
$minute=date(i);
if ($minute=00 $minute=14)
{
$minute=00;
}
elseif ($minute=15 $minute=29)
{
$minute=15;
}
elseif ($minute=30 $minute=44)
{
$minute=30;
}
else
{
$minute=45;
}
$times=10:$minute;
$sql=SELECT buildingname, parking_lot_name, empty_spaces, distance,
round(distance/($low_speed*60),1) AS low_time,
round(distance/($high_speed*60),1) AS high_time, Location FROM
buildings, buildings_lots, parkinglots, occupancy2, Image where
(buildings.buildingcode=occupancy2.building AND
buildings.buildingcode=buildings_lots.building_code AND
parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
parkinglots.parking_lot_code=occupancy2.parking_lot AND
Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build'
AND month='$Month' AND day='Monday' AND Time='$times';
$data = mysqli_query($cxn,$sql);
if (!$data=mysqli_query($cxn,$sql))
{
$error=mysqli_error($cxn);
echo $error;
die();
}
else
{
echo br;
echo Query sent successfully;
}
echo br;
echo h1 PARKING LOT INFORMATION h1;
echo table border='1' cellspacing='5' cellpadding='2';
echo tr\n
thBuilding/th\n
thParking Lot/th\n
thEstimated Number of Empty Spaces/th\n
thDistance (Feet)/th\n
thEstimated walking time to the building/th\n
/tr\n;
while ($row=mysqli_fetch_array($data))
{
extract($row);
$building = $row[0];
$parking_lot = $row[1];
$Number_of_Empty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6]; echo tr\n
td$building/td\n
td$parking_lot/td\n
td$Number_of_Empty_Spaces/td\n
Re: [PHP-DB] Problem with PDO exceptions
yup, I have set the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| and I am still not getting an exception! My Code is something like this: $query = $db-prepare($sql); $query-execute($bind); $row = $query-fetch(PDO::FETCH_ASSOC); wher $db is the PDO obj and $sql is the sql query and $bind is the bound parameter On Sun, Mar 8, 2009 at 5:35 PM, Zoltan Ormandi ormandi.zol...@webfunteam.hu wrote: Hi, Did you set the value of the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION|? Btw, I don't think ||prepare would throw an exception even for a malformed query, but ||execute definitely should. Regards, Z
Re: [PHP-DB] Problem with PDO exceptions
I am sorry, setting |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| *does* throw an Exception when the table cannot be found. Stupid me; I was trying to catch Exception rather than a PDOException. On Sun, Mar 8, 2009 at 6:03 PM, kesavan trichy rengarajan k...@trk7.comwrote: yup, I have set the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| and I am still not getting an exception! My Code is something like this: $query = $db-prepare($sql); $query-execute($bind); $row = $query-fetch(PDO::FETCH_ASSOC); wher $db is the PDO obj and $sql is the sql query and $bind is the bound parameter On Sun, Mar 8, 2009 at 5:35 PM, Zoltan Ormandi ormandi.zol...@webfunteam.hu wrote: Hi, Did you set the value of the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION|? Btw, I don't think ||prepare would throw an exception even for a malformed query, but ||execute definitely should. Regards, Z
