Re: [PHP-DB] More help with mysql -- solved (bizarre)
It's not bizarre behaviour $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to execute SQL query); returns result of logical OR operation which is TRUE or 1 without || die(...) it returns valid MySQL resource Regards Sasha Evan Morris [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] If I remove the '|| die' part from the mysql_query() statement, it works fine. This is bizarre, but there it is. ie, if I have: $result = mysql_query(SELECT * FROM SOME_TABLE); it works. If I have: $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to execute SQL query); it doesn't work. It gives me: Supplied argument is not a valid MySQL result resource Anyway, since it works I don't suppose I should complain, but it seems pretty weird to me nevertheless. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] More help with mysql -- solved (bizarre)
If I remove the '|| die' part from the mysql_query() statement, it works fine. This is bizarre, but there it is. ie, if I have: $result = mysql_query(SELECT * FROM SOME_TABLE); it works. If I have: $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to execute SQL query); it doesn't work. It gives me: Supplied argument is not a valid MySQL result resource Anyway, since it works I don't suppose I should complain, but it seems pretty weird to me nevertheless. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re[2]: [PHP-DB] More help with mysql -- solved (bizarre)
OK, now I see 8)
$result after your operations contains not SQL result, it's value is 1 (logical
TRUE) -- result of logical operation
mysql_query(SELECT * FROM SOME_TABLE) || die(
If you want to exit after error try this construction:
if(!mysql_query(SELECT * FROM SOME_TABLE))
{
die(
};
EM If I remove the '|| die' part from the mysql_query() statement, it works
EM fine. This is bizarre, but there it is.
EM ie, if I have:
EM $result = mysql_query(SELECT * FROM SOME_TABLE);
EM it works.
EM If I have:
EM $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to execute
EM SQL query);
EM it doesn't work. It gives me: Supplied argument is not a valid MySQL
EM result resource
EM Anyway, since it works I don't suppose I should complain, but it seems
EM pretty weird to me nevertheless.
WBR, Max 'AMiGo' Gashkov
[EMAIL PROTECTED] ]=[ http://diary.otaku.ru/amigo
Distributed.net participant [408228][RC5-72]
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RE: Re[2]: [PHP-DB] More help with mysql -- solved (bizarre)
I believe if you put OR instead of || it will work OK as originally posted..
ie mysql_query(SELECT * FROM SOME_TABLE) OR die(
Nick
-Original Message-
From: Max 'AMiGo' Gashkov [mailto:[EMAIL PROTECTED]]
Sent: 18 February 2003 08:42
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re[2]: [PHP-DB] More help with mysql -- solved (bizarre)
OK, now I see 8)
$result after your operations contains not SQL result, it's value is 1
(logical
TRUE) -- result of logical operation
mysql_query(SELECT * FROM SOME_TABLE) || die(
If you want to exit after error try this construction:
if(!mysql_query(SELECT * FROM SOME_TABLE))
{
die(
};
EM If I remove the '|| die' part from the mysql_query() statement, it works
EM fine. This is bizarre, but there it is.
EM ie, if I have:
EM $result = mysql_query(SELECT * FROM SOME_TABLE);
EM it works.
EM If I have:
EM $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to
execute
EM SQL query);
EM it doesn't work. It gives me: Supplied argument is not a valid MySQL
EM result resource
EM Anyway, since it works I don't suppose I should complain, but it seems
EM pretty weird to me nevertheless.
WBR, Max 'AMiGo' Gashkov
[EMAIL PROTECTED] ]=[ http://diary.otaku.ru/amigo
Distributed.net participant [408228][RC5-72]
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RE: [PHP-DB] More help with mysql -- solved (bizarre)
-Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: 18 February 2003 08:26 If I remove the '|| die' part from the mysql_query() statement, it works fine. This is bizarre, but there it is. ie, if I have: $result = mysql_query(SELECT * FROM SOME_TABLE); it works. If I have: $result = mysql_query(SELECT * FROM SOME_TABLE) || die (Unable to execute SQL query); it doesn't work. It gives me: Supplied argument is not a valid MySQL result resource The || and OR operators, although both doing a Boolean or, have different priorities, so: $result = mysql_query(...) or die(...); is the same as ($result = mysql_query(...)) or die(...); whilst $result = mysql_query(...) || die(...); is the same as $result = (mysql_query(...) || die(...)); In the first case, the result of mysql_query() is assigned into $result, and if it returns FALSE the die() is performed. In the second case, the result of applying the || operator to the mysql_query() and the die() is assigned to $result; because PHP uses short-circuit evaluation, the die() is still only executed if mysql_query returns FALSE, but the || operator still returns a simple Boolean to be assigned to $result -- which, if the die() hasn't fired, must be TRUE (which PHP generally prints as 1). QED. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
