[PHP-DB] Passing selection to next page
I have a drop down list created using the following code and am having trouble passing my selection to the next page. Can anyone help? ? $query = select distinct department from courses order by department; $result = mysql_query($query); echo SELECT ID='Category Combo Box' NAME='department'; echo OPTION VALUE=' ' SELECTEDSelect Department/OPTION; While ($row = mysql_fetch_assoc($result)) { echo OPTION VALUE='; echo stripslashes($row[department]); echo ' ; echo stripslashes($row[department]); echo /OPTION; } echo /SELECT; mysql_free_result($result); ? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Passing selection to next page
I guess this all is in a form so on the next page it should be in: echo $_POST[department]; or in echo $department depending on the php version -Original Message- From: Alex Francis [mailto:[EMAIL PROTECTED]] Sent: donderdag 19 december 2002 12:05 To: [EMAIL PROTECTED] Subject: [PHP-DB] Passing selection to next page I have a drop down list created using the following code and am having trouble passing my selection to the next page. Can anyone help? ? $query = select distinct department from courses order by department; $result = mysql_query($query); echo SELECT ID='Category Combo Box' NAME='department'; echo OPTION VALUE=' ' SELECTEDSelect Department/OPTION; While ($row = mysql_fetch_assoc($result)) { echo OPTION VALUE='; echo stripslashes($row[department]); echo ' ; echo stripslashes($row[department]); echo /OPTION; } echo /SELECT; mysql_free_result($result); ? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Passing selection to next page
Hi, you have to put this list in a form... form name=select_name action=eval.php method=post select option /select /form in eval.php you may write like: $variable1=$_POST['select_name']; //and variable1 is now the option_value selected echo $variable1; where option_value is the value written in the list...generated by php if I have a list with 4 values like: option value=onevalue number one-first/option option value=twovalue number two -second/option option value=threevalue number three -third/option option value=fourvalue number four fourth/option here the option_value is one or two or three or four so variable1 is now passed from one page to another.. if you have any questions or you are of a different opinion write to me again cybercop78 On Thu, 19 Dec 2002 11:04:34 -, Alex Francis wrote I have a drop down list created using the following code and am having trouble passing my selection to the next page. Can anyone help? ? $query = select distinct department from courses order by department; $result = mysql_query($query); echo SELECT ID='Category Combo Box' NAME='department'; echo OPTION VALUE=' ' SELECTEDSelect Department/OPTION; While ($row = mysql_fetch_assoc($result)) { echo OPTION VALUE='; echo stripslashes($row[department]); echo ' ; echo stripslashes($row[department]); echo /OPTION; } echo /SELECT; mysql_free_result($result); ? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php http://www.idilis.ro - Stiri, e-mail gratuit, download, SMS, server de counter-strike, hosting gratuit, servicii internet... Fii cu un pas inaintea celorlati! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php