Hello Srini,
Don't speak english! :-)
For example, what is the cost of 500 licenses of Product_ID 143 ?
The slabs do not continue for an infinite number, hence I may only have slab
pricing for 1-10, 11-100, and 101-200 with the assumption that if there are
no higher slabs and I wanted say the rate for 500 licenses, I would use the
highest slab unit available, in this case the 101-200 slab.
My table structure is like so:
Slab_Master
++-+--+-+-++
| Field | Type| Null | Key | Default | Extra |
++-+--+-+-++
| TInt_SlabID| int(11) | | PRI | NULL| auto_increment |
| TInt_ProductID | int(11) | YES | | NULL||
| TInt_StartSlab | int(11) | YES | | NULL||
| TInt_EndSlab | int(11) | YES | | NULL||
| TDbl_SlabRate | float(10,2) | YES | | NULL||
++-+--+-+-++
SKIP
SELECT TDbl_SlabRateFROM Slab_Master WHERE TInt_ProductID = 143
AND TInt_StartSlab = 101; /*$MAX = 101*/
My examples:
CREATE TABLE wm
(
id int(3) unsigned default '0',
tex char(24) default NULL,
lic tinyint(3) unsigned default NULL
)
INSERT INTO wm VALUES(1, w, 6);
INSERT INTO wm VALUES(2, zz, 20);
INSERT INTO wm VALUES(1, www, 5);
INSERT INTO wm VALUES(1, ww, 7);
INSERT INTO wm VALUES(5, z, 2);
INSERT INTO wm VALUES(80, zzz, 1);
My query:
SELECT a.id, a.tex, MAX(a.lic) AS licens
FROM wm a, wm b
WHERE a.id=1 AND a.id=b.id AND a.lic60
GROUP BY a.id, a.tex
HAVING MAX(a.lic)=MAX(b.lic)
^
Result: MAX licens = 7
--
Best regards,
Zubarev Andrey
mailto:[EMAIL PROTECTED]
miranda-icq: 115959232
DelphiKingdom Team [http://www.delphikingdom.com]
KZ - Ekibastuz
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