Re: [PHP-DB] SQL for counting comments - is this smart?

2009-03-17 Thread Gerardo Benitez
Chris your answer is the better solution, I thinked that the option suggest
by Martin was fine.

anywhere, tanks for help us to improve us code.

Gerardo.

2009/3/16 Chris dmag...@gmail.com

 Martin Zvarík wrote:

 Is it smart to use all of this on one page?
 Or should I rather do one SQL and let PHP count it?


 $q = $DB-q(SELECT COUNT(*) FROM comments);
 $int_total = $DB-frow($q);

 $q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved IS NULL);
 $int_waiting = $DB-frow($q);

 $q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=0);
 $int_deleted = $DB-frow($q);

 $q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=1);
 $int_approved = $DB-frow($q);

 $q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=2);
 $int_banned = $DB-frow($q);


 Each one of these probably going to scan the whole table because the
 approved column isn't going to be selective enough to use an index.

 You might be better off doing:

 select approved, count(*) from comments group by approved;

 then in php separating them out:

 while ($row = $DB-frow($q)) {
  switch ($row['approved']) {
 case null:
   $waiting = $row['count'];
 break;
 case 0:
   $deleted = $row['count'];
 break;
 case 1:
   $approved = $row['count'];
 break;
  }
 }

 $total = $waiting + $approved + $deleted;

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[PHP-DB] SQL for counting comments - is this smart?

2009-03-16 Thread Martin Zvarík

Is it smart to use all of this on one page?
Or should I rather do one SQL and let PHP count it?


$q = $DB-q(SELECT COUNT(*) FROM comments);
$int_total = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved IS NULL);
$int_waiting = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=0);
$int_deleted = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=1);
$int_approved = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=2);
$int_banned = $DB-frow($q);


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Re: [PHP-DB] SQL for counting comments - is this smart?

2009-03-16 Thread Chris

Martin Zvarík wrote:

Is it smart to use all of this on one page?
Or should I rather do one SQL and let PHP count it?


$q = $DB-q(SELECT COUNT(*) FROM comments);
$int_total = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved IS NULL);
$int_waiting = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=0);
$int_deleted = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=1);
$int_approved = $DB-frow($q);

$q = $DB-q(SELECT COUNT(*) FROM comments WHERE approved=2);
$int_banned = $DB-frow($q);


Each one of these probably going to scan the whole table because the 
approved column isn't going to be selective enough to use an index.


You might be better off doing:

select approved, count(*) from comments group by approved;

then in php separating them out:

while ($row = $DB-frow($q)) {
  switch ($row['approved']) {
 case null:
   $waiting = $row['count'];
 break;
 case 0:
   $deleted = $row['count'];
 break;
 case 1:
   $approved = $row['count'];
 break;
  }
}

$total = $waiting + $approved + $deleted;

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Postgresql  php tutorials
http://www.designmagick.com/


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