Re: [PHP-DB] MySQL result resource
Agree fully
Try this:
$query = select * from category where id=$scrow-category;
$result = mysql_query($query) or die( mysql_error() );
If your query fails, and u still can't find the reason from the
information that mysql_error() give you, put a echo $query inbetween
to see which string your passing to mysql_query().
Edwin
John W. Holmes wrote:
It means your query failed... it always means your query failed for some
reason (unless you typo a variable name...). Learn to use mysql_error()
in conjunction with mysql_query(). Also, like I said before,
mysql_db_query() is depreciated, you should be using mysql_query().
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
-Original Message-
From: Addison Ellis [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 29, 2003 10:02 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] MySQL result resource
hello,
i have a new issue... :-)
i am getting:
Warning: Supplied argument is not a valid MySQL result resource in
/users/infoserv/web/register/ca/admin/catads.php on line 54
from:
?
while($row = mysql_fetch_object($obj))
{
$scobj = mysql_db_query($dbname,select * from subcategory
where id=$row-subcategory);
$scrow = mysql_fetch_object($scobj);
$cobj = mysql_db_query($dbname,select * from category where
id=$scrow-category);//54
$crow = mysql_fetch_object($cobj);
?
any ideas, of course, are most appreciated. thank you and best,
addison
--
Addison Ellis
small independent publishing co.
114 B 29th Avenue North
Nashville, TN 37203
(615) 321-1791
[EMAIL PROTECTED]
[EMAIL PROTECTED]
subsidiaries of small independent publishing co.
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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RE: [PHP-DB] MySQL result resource
It means your query failed... it always means your query failed for some
reason (unless you typo a variable name...). Learn to use mysql_error()
in conjunction with mysql_query(). Also, like I said before,
mysql_db_query() is depreciated, you should be using mysql_query().
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
-Original Message-
From: Addison Ellis [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 29, 2003 10:02 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] MySQL result resource
hello,
i have a new issue... :-)
i am getting:
Warning: Supplied argument is not a valid MySQL result resource in
/users/infoserv/web/register/ca/admin/catads.php on line 54
from:
?
while($row = mysql_fetch_object($obj))
{
$scobj = mysql_db_query($dbname,select * from subcategory
where id=$row-subcategory);
$scrow = mysql_fetch_object($scobj);
$cobj = mysql_db_query($dbname,select * from category where
id=$scrow-category);//54
$crow = mysql_fetch_object($cobj);
?
any ideas, of course, are most appreciated. thank you and best,
addison
--
Addison Ellis
small independent publishing co.
114 B 29th Avenue North
Nashville, TN 37203
(615) 321-1791
[EMAIL PROTECTED]
[EMAIL PROTECTED]
subsidiaries of small independent publishing co.
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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RE: [PHP-DB] MySQL Result Resource
shouldn't it be PASSWORD('madonna') ??
-Original Message-
From: Necro [mailto:[EMAIL PROTECTED]]
Sent: 11 January 2002 04:39
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
http://www.hotscripts.com/Detailed/4219.html --- that is the script
But I cannot use crypt() on a winodws system. So I tried MD5, now I try
PASSWORD.
Any one got any idea how to make the script work with either of those??
Andrew
-Original Message-
From: Necro [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:30 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Daniel,
I had tried both with and without quotes. Neither work.
Without quotes I get:
select password, 1 as auth from acl where username='andrewd' and password =
PASSWORD(madonna)1054 : Unknown column 'madonna' in 'where clause'
Notice that madonna has not been crypted by the PASSWORD call either.
Andrew
-Original Message-
From: Daniel Barton [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:40 PM
To: Necro
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
Andrew:
Don't put quotes around your MySQL function call.
i.e.
PASSWORD($password)
not
'PASSWORD($password)'
p.s. Looking at this thread, it seems like most of the errors you're
encountering have
nothing to do with md5() or password(), but with syntax, like placement of
quotes, or
whether they are single quotes or double quotes. I would suggest
experimenting with
the syntax a bit, to check out what's kosher, and what's not? Check out the
PHP
manual's sections on 'Resource id's - I think you may find it to be very
important to
understanding how PHP interacts with databases. Resource ids, which are
returned by
quite a few function calls, are not classic variables - they need to be
manipulated or
interpreted before you use them.
Cheers,
db
Necro wrote:
Ok,
I have tried to go to PASSWORD after none of the suggestions worked out.
The current statement is:
$arg = select password, 1 as auth from acl where
username='$username' and
password = 'PASSWORD($password)';
But the error I get now is:
select password, 1 as auth from acl where username='andrewd' and password
=
'PASSWORD(madonna)'Resource id #2
Any ideas?
Andrew
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 8:56 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Addressed to: Necro [EMAIL PROTECTED]
[EMAIL PROTECTED]
** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002
03:41:43 +1100
select password, 1 as auth from acl where (username='andrewd' and
password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in
your
SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1
Does that help give any idea at all as to what the problem is?
There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The
error occurs where it does because '163e06103' is a valid exponential
notation value for a nubmer, but having an 'a' follow it is not valid.
My solution would be:
$Pass = md5( whatever ); # I don't care if you hash just the password
# or the username and password as long as
# you do it the same way as you entered
# the passwords.
mysql_query( SELECT password, 1 AS auth .
FROM acl .
WHERE username = '$username' .
AND password = '$Pass' );
But I question what you are doing returning password, so it might work
as well as:
mysql_query( SELECT count(*) as Authorized .
FROM acl .
WHERE username = '$username' .
AND password = '$Pass' );
This returns 0 or 1 in a field named Authorized depending on if the
password matches or not.
You might also want to look at the MySQL PASSWORD() function and not
mess with md5 at all.
Rick
Rick Widmer
Internet Marketing Specialists
http://www.developersdesk.com
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Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Ok,
I have tried a few things now. I finally got it to echo the errors, firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors, firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors, firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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Re: [PHP-DB] MySQL Result Resource
I was having something similar and solved it by wrapping the column names in
parentheses:
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
It might help. or eliminate something if I'm not right.
George
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 4:09 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where
clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Same error...
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna))1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: George Pitcher [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:10 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
I was having something similar and solved it by wrapping the column names in
parentheses:
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
It might help. or eliminate something if I'm not right.
George
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 4:09 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where
clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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PHP
Re: [PHP-DB] MySQL Result Resource
try this :
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 6:18 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Same error...
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna))1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: George Pitcher [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:10 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
I was having something similar and solved it by wrapping the column names in
parentheses:
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
It might help. or eliminate something if I'm not right.
George
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 4:09 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where
clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
RE: [PHP-DB] MySQL Result Resource
LIGHT just came on!!! Why does ittake so long.
MD5(andrew.madonna) - I think you're goint to have to do this
$passhash = $username . $password
and use MD5($passhash).
MySQL is looking for a table andrewd with the field madonna in the way
the MD5() is presently structured.
Go to it - Miles
At 03:09 AM 1/11/2002 +1100, Necro wrote:
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors, firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
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RE: [PHP-DB] MySQL Result Resource
Parse error: parse error in d:\htdocs\infekt\packages\auth.inc on line 104
$arg = select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
Nope :(
-Original Message-
From: Andrey Hristov [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:28 AM
To: Necro
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
try this :
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 6:18 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Same error...
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna))1109 : Unknown table 'andrewd' in where
clause
Andrew
-Original Message-
From: George Pitcher [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:10 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
I was having something similar and solved it by wrapping the column names
in
parentheses:
select password, 1 as auth from acl where (username='andrewd' and
password=MD5(andrewd.madonna));
It might help. or eliminate something if I'm not right.
George
- Original Message -
From: Necro [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, January 10, 2002 4:09 PM
Subject: RE: [PHP-DB] MySQL Result Resource
Yep,
andrewd is the username im trying to get this script to work with, its
an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where
clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know
where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc
RE: [PHP-DB] MySQL Result Resource
Miles,
You must MD5 the value outside of mysql for it to evaluate it, from the
error I just got.
i have tried
$passhash = MD5($username.$password);
$arg = select password, 1 as auth from acl where (username='andrewd' and
password=($passhash));
And get the following error...
select password, 1 as auth from acl where (username='andrewd' and
password=(c59d088cd3d873af5239cfac1234f370))1054 : Unknown column
'c59d088cd3d873af5239cfac1234f370' in 'where clause'
So at least the MD5 is now evaluated. But there is still and error in there.
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:29 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
LIGHT just came on!!! Why does ittake so long.
MD5(andrew.madonna) - I think you're goint to have to do this
$passhash = $username . $password
and use MD5($passhash).
MySQL is looking for a table andrewd with the field madonna in the way
the MD5() is presently structured.
Go to it - Miles
At 03:09 AM 1/11/2002 +1100, Necro wrote:
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script...
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Line 26: define( DATABASE, imanager );
Line 103: $arg = select password, 1 as auth from acl where
username='$username' and password=MD5('$username','$password');
Line 104: $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
Can anyone help get this to work??
Thankyou.
Andrew
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact
RE: [PHP-DB] MySQL Result Resource
On further investigation it appears to get the correct MD5 value the correct
synatx is:
$passhash = MD5($username.$password); --- needs the
The the error resulting from this is:
select password, 1 as auth from acl where (username='andrewd' and
password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your
SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1
Does that help give any idea at all as to what the problem is?
Andrew
-Original Message-
From: Necro [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:35 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Miles,
You must MD5 the value outside of mysql for it to evaluate it, from the
error I just got.
i have tried
$passhash = MD5($username.$password);
$arg = select password, 1 as auth from acl where (username='andrewd' and
password=($passhash));
And get the following error...
select password, 1 as auth from acl where (username='andrewd' and
password=(c59d088cd3d873af5239cfac1234f370))1054 : Unknown column
'c59d088cd3d873af5239cfac1234f370' in 'where clause'
So at least the MD5 is now evaluated. But there is still and error in there.
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:29 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
LIGHT just came on!!! Why does ittake so long.
MD5(andrew.madonna) - I think you're goint to have to do this
$passhash = $username . $password
and use MD5($passhash).
MySQL is looking for a table andrewd with the field madonna in the way
the MD5() is presently structured.
Go to it - Miles
At 03:09 AM 1/11/2002 +1100, Necro wrote:
Yep,
andrewd is the username im trying to get this script to work with, its an
authentication script..
The result of echo $arg is the following:
select password, 1 as auth from acl where username='andrewd' and
password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where clause
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 3:08 AM
To: Necro; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Can you try this puppy at the MySQL console? I'd dearly love to know where
andrewd is coming from, it sounds like your username.
Before executing mysql_query(), echo $arg and see what it prints.
This is strange, but better than what we had - Miles Thompson
At 02:54 AM 1/11/2002 +1100, Necro wrote:
Ok,
I have tried a few things now. I finally got it to echo the errors,
firstly
there was still a prob with MD5 values being in the apostrophes.
Then next error was no db was selected. So i added a mysql_select_db
statement.
Now i get this:
1109 : Unknown table 'andrewd' in where clause
andrewd being the username I am trying to get it to accept.
Following lines are the current bit:
$arg = select password, 1 as auth from acl where
username='$username' and
password=MD5($username.$password);
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result);
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:36 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] MySQL Result Resource
Break up the code.
I assume you are connecting to the database with mysql_connect() or
mysql_pconnect(). If not, do that.
Echo your query so that you know it contains valid values.
Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg ));
into
$result = mysql_query( $arg ) or die(mysql_errno(). : .
mysql_error() );
$row = mysql_fetch_array($result) )
then do whatever processing you need with the array $row.
Miles
PS Just reply to the list, if you reply directly to me I have one more
message to delete. g /mt
At 02:10 AM 1/11/2002 +1100, Necro wrote:
Yeh, I notice now the MD5 was wrong.
But I still get the same error on line 104. If I try and replace it
with
the
current query function then I get two errors.
e.g.
Warning: Supplied argument is not a valid MySQL-Link resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Warning: Supplied argument is not a valid MySQL result resource in
d:\htdocs\infekt\packages\auth.inc on line 104
Andrew
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Friday, 11 January 2002 2:05 AM
To: Necro; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL Result Resource
The use of the MD5 function in the query doesn't look quite right.
Shouldn't it be MD5('$password') or MD5('$username'.'$password') if
concatenating?
Also, mysql_db_query() has been a deprecated function for some time
now,
mysql_query() is recommended.
Hope this gets you going - Miles Thompson
At 01:33 AM 1/11/2002 +1100, Necro wrote:
Lo all,
Slight problem on an auth script
Re: [PHP-DB] MySQL Result Resource
try : $arg = select password, 1 as auth from acl where (username='andrewd') and password=MD5(concat(username,password)); HTH Andrey - Original Message - From: Necro [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, January 10, 2002 6:29 PM Subject: RE: [PHP-DB] MySQL Result Resource Parse error: parse error in d:\htdocs\infekt\packages\auth.inc on line 104 $arg = select password, 1 as auth from acl where (username='andrewd' and password=MD5(andrewd.madonna)); Nope :( -Original Message- From: Andrey Hristov [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 3:28 AM To: Necro Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] MySQL Result Resource try this : select password, 1 as auth from acl where (username='andrewd' and password=MD5(andrewd.madonna)); - Original Message - From: Necro [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, January 10, 2002 6:18 PM Subject: RE: [PHP-DB] MySQL Result Resource Same error... select password, 1 as auth from acl where (username='andrewd' and password=MD5(andrewd.madonna))1109 : Unknown table 'andrewd' in where clause Andrew -Original Message- From: George Pitcher [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 3:10 AM To: Necro; [EMAIL PROTECTED] Subject: Re: [PHP-DB] MySQL Result Resource I was having something similar and solved it by wrapping the column names in parentheses: select password, 1 as auth from acl where (username='andrewd' and password=MD5(andrewd.madonna)); It might help. or eliminate something if I'm not right. George - Original Message - From: Necro [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, January 10, 2002 4:09 PM Subject: RE: [PHP-DB] MySQL Result Resource Yep, andrewd is the username im trying to get this script to work with, its an authentication script.. The result of echo $arg is the following: select password, 1 as auth from acl where username='andrewd' and password=MD5(andrewd.madonna)1109 : Unknown table 'andrewd' in where clause Andrew -Original Message- From: Miles Thompson [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 3:08 AM To: Necro; [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Can you try this puppy at the MySQL console? I'd dearly love to know where andrewd is coming from, it sounds like your username. Before executing mysql_query(), echo $arg and see what it prints. This is strange, but better than what we had - Miles Thompson At 02:54 AM 1/11/2002 +1100, Necro wrote: Ok, I have tried a few things now. I finally got it to echo the errors, firstly there was still a prob with MD5 values being in the apostrophes. Then next error was no db was selected. So i added a mysql_select_db statement. Now i get this: 1109 : Unknown table 'andrewd' in where clause andrewd being the username I am trying to get it to accept. Following lines are the current bit: $arg = select password, 1 as auth from acl where username='$username' and password=MD5($username.$password); $result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() ); $row = mysql_fetch_array($result); Andrew -Original Message- From: Miles Thompson [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 2:36 AM To: [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Break up the code. I assume you are connecting to the database with mysql_connect() or mysql_pconnect(). If not, do that. Echo your query so that you know it contains valid values. Break $row = mysql_fetch_array(mysql_db_query( DATABASE, $arg )); into $result = mysql_query( $arg ) or die(mysql_errno(). : . mysql_error() ); $row = mysql_fetch_array($result) ) then do whatever processing you need with the array $row. Miles PS Just reply to the list, if you reply directly to me I have one more message to delete. g /mt At 02:10 AM 1/11/2002 +1100, Necro wrote: Yeh, I notice now the MD5 was wrong. But I still get the same error on line 104. If I try and replace it with the current query function then I get two errors. e.g. Warning: Supplied argument is not a valid MySQL-Link resource in d:\htdocs\infekt\packages\auth.inc on line 104 Warning: Supplied argument is not a valid MySQL result resource in d:\htdocs\infekt\packages\auth.inc on line 104 Andrew -Original Message- From: Miles Thompson [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 2:05 AM To: Necro; [EMAIL PROTECTED] Subject: Re: [PHP-DB] MySQL Result Resource The use of the MD5 function in the query doesn't look quite right
RE: [PHP-DB] MySQL Result Resource
Addressed to: Necro [EMAIL PROTECTED] [EMAIL PROTECTED] ** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002 03:41:43 +1100 select password, 1 as auth from acl where (username='andrewd' and password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1 Does that help give any idea at all as to what the problem is? There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The error occurs where it does because '163e06103' is a valid exponential notation value for a nubmer, but having an 'a' follow it is not valid. My solution would be: $Pass = md5( whatever ); # I don't care if you hash just the password # or the username and password as long as # you do it the same way as you entered # the passwords. mysql_query( SELECT password, 1 AS auth . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); But I question what you are doing returning password, so it might work as well as: mysql_query( SELECT count(*) as Authorized . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); This returns 0 or 1 in a field named Authorized depending on if the password matches or not. You might also want to look at the MySQL PASSWORD() function and not mess with md5 at all. Rick Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] MySQL Result Resource
Ok, I have tried to go to PASSWORD after none of the suggestions worked out. The current statement is: $arg = select password, 1 as auth from acl where username='$username' and password = 'PASSWORD($password)'; But the error I get now is: select password, 1 as auth from acl where username='andrewd' and password = 'PASSWORD(madonna)'Resource id #2 Any ideas? Andrew -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 8:56 AM To: Necro; [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Addressed to: Necro [EMAIL PROTECTED] [EMAIL PROTECTED] ** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002 03:41:43 +1100 select password, 1 as auth from acl where (username='andrewd' and password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1 Does that help give any idea at all as to what the problem is? There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The error occurs where it does because '163e06103' is a valid exponential notation value for a nubmer, but having an 'a' follow it is not valid. My solution would be: $Pass = md5( whatever ); # I don't care if you hash just the password # or the username and password as long as # you do it the same way as you entered # the passwords. mysql_query( SELECT password, 1 AS auth . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); But I question what you are doing returning password, so it might work as well as: mysql_query( SELECT count(*) as Authorized . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); This returns 0 or 1 in a field named Authorized depending on if the password matches or not. You might also want to look at the MySQL PASSWORD() function and not mess with md5 at all. Rick Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] MySQL Result Resource
Andrew: Don't put quotes around your MySQL function call. i.e. PASSWORD($password) not 'PASSWORD($password)' p.s. Looking at this thread, it seems like most of the errors you're encountering have nothing to do with md5() or password(), but with syntax, like placement of quotes, or whether they are single quotes or double quotes. I would suggest experimenting with the syntax a bit, to check out what's kosher, and what's not? Check out the PHP manual's sections on 'Resource id's - I think you may find it to be very important to understanding how PHP interacts with databases. Resource ids, which are returned by quite a few function calls, are not classic variables - they need to be manipulated or interpreted before you use them. Cheers, db Necro wrote: Ok, I have tried to go to PASSWORD after none of the suggestions worked out. The current statement is: $arg = select password, 1 as auth from acl where username='$username' and password = 'PASSWORD($password)'; But the error I get now is: select password, 1 as auth from acl where username='andrewd' and password = 'PASSWORD(madonna)'Resource id #2 Any ideas? Andrew -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 8:56 AM To: Necro; [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Addressed to: Necro [EMAIL PROTECTED] [EMAIL PROTECTED] ** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002 03:41:43 +1100 select password, 1 as auth from acl where (username='andrewd' and password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1 Does that help give any idea at all as to what the problem is? There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The error occurs where it does because '163e06103' is a valid exponential notation value for a nubmer, but having an 'a' follow it is not valid. My solution would be: $Pass = md5( whatever ); # I don't care if you hash just the password # or the username and password as long as # you do it the same way as you entered # the passwords. mysql_query( SELECT password, 1 AS auth . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); But I question what you are doing returning password, so it might work as well as: mysql_query( SELECT count(*) as Authorized . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); This returns 0 or 1 in a field named Authorized depending on if the password matches or not. You might also want to look at the MySQL PASSWORD() function and not mess with md5 at all. Rick Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- -- Dan Barton Terrestrial Program Biologist Asst. Data Manager Point Reyes Bird Observatory http://www.prbo.org [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] MySQL Result Resource
Daniel, I had tried both with and without quotes. Neither work. Without quotes I get: select password, 1 as auth from acl where username='andrewd' and password = PASSWORD(madonna)1054 : Unknown column 'madonna' in 'where clause' Notice that madonna has not been crypted by the PASSWORD call either. Andrew -Original Message- From: Daniel Barton [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 2:40 PM To: Necro Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] MySQL Result Resource Andrew: Don't put quotes around your MySQL function call. i.e. PASSWORD($password) not 'PASSWORD($password)' p.s. Looking at this thread, it seems like most of the errors you're encountering have nothing to do with md5() or password(), but with syntax, like placement of quotes, or whether they are single quotes or double quotes. I would suggest experimenting with the syntax a bit, to check out what's kosher, and what's not? Check out the PHP manual's sections on 'Resource id's - I think you may find it to be very important to understanding how PHP interacts with databases. Resource ids, which are returned by quite a few function calls, are not classic variables - they need to be manipulated or interpreted before you use them. Cheers, db Necro wrote: Ok, I have tried to go to PASSWORD after none of the suggestions worked out. The current statement is: $arg = select password, 1 as auth from acl where username='$username' and password = 'PASSWORD($password)'; But the error I get now is: select password, 1 as auth from acl where username='andrewd' and password = 'PASSWORD(madonna)'Resource id #2 Any ideas? Andrew -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 8:56 AM To: Necro; [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Addressed to: Necro [EMAIL PROTECTED] [EMAIL PROTECTED] ** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002 03:41:43 +1100 select password, 1 as auth from acl where (username='andrewd' and password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1 Does that help give any idea at all as to what the problem is? There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The error occurs where it does because '163e06103' is a valid exponential notation value for a nubmer, but having an 'a' follow it is not valid. My solution would be: $Pass = md5( whatever ); # I don't care if you hash just the password # or the username and password as long as # you do it the same way as you entered # the passwords. mysql_query( SELECT password, 1 AS auth . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); But I question what you are doing returning password, so it might work as well as: mysql_query( SELECT count(*) as Authorized . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); This returns 0 or 1 in a field named Authorized depending on if the password matches or not. You might also want to look at the MySQL PASSWORD() function and not mess with md5 at all. Rick Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- -- Dan Barton Terrestrial Program Biologist Asst. Data Manager Point Reyes Bird Observatory http://www.prbo.org [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] MySQL Result Resource
http://www.hotscripts.com/Detailed/4219.html --- that is the script But I cannot use crypt() on a winodws system. So I tried MD5, now I try PASSWORD. Any one got any idea how to make the script work with either of those?? Andrew -Original Message- From: Necro [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 3:30 PM To: [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Daniel, I had tried both with and without quotes. Neither work. Without quotes I get: select password, 1 as auth from acl where username='andrewd' and password = PASSWORD(madonna)1054 : Unknown column 'madonna' in 'where clause' Notice that madonna has not been crypted by the PASSWORD call either. Andrew -Original Message- From: Daniel Barton [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 2:40 PM To: Necro Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] MySQL Result Resource Andrew: Don't put quotes around your MySQL function call. i.e. PASSWORD($password) not 'PASSWORD($password)' p.s. Looking at this thread, it seems like most of the errors you're encountering have nothing to do with md5() or password(), but with syntax, like placement of quotes, or whether they are single quotes or double quotes. I would suggest experimenting with the syntax a bit, to check out what's kosher, and what's not? Check out the PHP manual's sections on 'Resource id's - I think you may find it to be very important to understanding how PHP interacts with databases. Resource ids, which are returned by quite a few function calls, are not classic variables - they need to be manipulated or interpreted before you use them. Cheers, db Necro wrote: Ok, I have tried to go to PASSWORD after none of the suggestions worked out. The current statement is: $arg = select password, 1 as auth from acl where username='$username' and password = 'PASSWORD($password)'; But the error I get now is: select password, 1 as auth from acl where username='andrewd' and password = 'PASSWORD(madonna)'Resource id #2 Any ideas? Andrew -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Friday, 11 January 2002 8:56 AM To: Necro; [EMAIL PROTECTED] Subject: RE: [PHP-DB] MySQL Result Resource Addressed to: Necro [EMAIL PROTECTED] [EMAIL PROTECTED] ** Reply to note from Necro [EMAIL PROTECTED] Fri, 11 Jan 2002 03:41:43 +1100 select password, 1 as auth from acl where (username='andrewd' and password=(163e06103a371fd95b21b4a849bb4b91))1064 : You have an error in your SQL syntax near 'a371fd95b21b4a849bb4b91))' at line 1 Does that help give any idea at all as to what the problem is? There are no quotes around 163e06103a371fd95b21b4a849bb4b91 The error occurs where it does because '163e06103' is a valid exponential notation value for a nubmer, but having an 'a' follow it is not valid. My solution would be: $Pass = md5( whatever ); # I don't care if you hash just the password # or the username and password as long as # you do it the same way as you entered # the passwords. mysql_query( SELECT password, 1 AS auth . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); But I question what you are doing returning password, so it might work as well as: mysql_query( SELECT count(*) as Authorized . FROM acl . WHERE username = '$username' . AND password = '$Pass' ); This returns 0 or 1 in a field named Authorized depending on if the password matches or not. You might also want to look at the MySQL PASSWORD() function and not mess with md5 at all. Rick Rick Widmer Internet Marketing Specialists http://www.developersdesk.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- -- Dan Barton Terrestrial Program Biologist Asst. Data Manager Point Reyes Bird Observatory http://www.prbo.org [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL
Re: [PHP-DB] MySQL Result Resource
On Friday 11 January 2002 10:33, Necro wrote:
Ok,
I have tried to go to PASSWORD after none of the suggestions worked out.
The current statement is:
$arg = select password, 1 as auth from acl where username='$username' and
password = 'PASSWORD($password)';
But the error I get now is:
select password, 1 as auth from acl where username='andrewd' and password =
'PASSWORD(madonna)'Resource id #2
Any ideas?
Andrew
Both PASSWORD and MD5 expect a *string* as an argument so you need to enclose
the argument in either single quotes or double quotes.
$arg = SELECT password, 1 AS auth
FROM acl
WHERE username = '$username'
AND password = PASSWORD('$password');
Hopefully that should work ;-)
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
Love is the process of my leading you gently back to yourself.
-- Saint Exupery
*/
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Re: [PHP-DB] Mysql result resource error
which one was giving you the problem? the first or second mysql try. if it
was the second, try wrapping the $cattyname with single quotes like this
Minor_Category = '$cattyname'. if the $cattyname var has anything but
numbers, the statement won't work.
Jim
- Original Message -
From: Shannon Doyle [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, December 19, 2001 4:19 PM
Subject: [PHP-DB] Mysql result resource error
Hi People,
I am getting a Not a valid Mysql result resource error with the
following code, can someone take a look at this for me and see if there
is anything that stands out
Thanks,
Shannon
?
$cattyname = ;
$sql = select Minor_Category main where Page = 'wines' order by
Minor_Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results2 = mysql_db_query($db,$sql,$dbh);
for($j = 0; $j mysql_num_rows($results2); $j++) {
$array[$j] = mysql_fetch_array($results2);
}
mysql_close($dbh);
for ($h = 0; $h count($array); $h++) {
if ($array[$h][Minor_Category] != $cattyname) {
$cattyname = $array[$h][Minor_Category];
echo trtd colspan='4'a
name='.$cattyname.'/ab.$cattyname./b/td/td/tr;
$catname = ;
$sql = select Category,Code,Description,Pack,Unit,Price from main where
Page = 'wines' Minor_Category = $cattyname order by Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results = mysql_db_query($db,$sql,$dbh);
for($i = 0; $i mysql_num_rows($results); $i++) {
$array[$i] = mysql_fetch_array($results);
}
mysql_close($dbh);
for ($i = 0; $i count($array); $i++) {
if ($array[$i][Category] != $catname) {
$catname = $array[$i][Category];
echo trtd colspan='4'a
name='.$catname.'/ab.$catname./b/tdtd
align='center'pbCarton Size/b/p/tdtd
align='center'pbUnit/b/p/tdtd
align='right'pbPrice/b/p/tdtda href='#top'img
src='images/arrow.gif' border='0'/a/td/tr;
}
echo trtd/tdtdpa
href=javascript:order_now(quot;.$array[$i][Code].quot;)img
src='images/order.gif' border='0'/a/tdtd/tdtd
align='left'p.$array[$i][Description]./p/tdtd
align='center'p.$array[$i][Pack]./p/tdtd
align='center'p.$array[$i][Unit]./p/tdtd
align='right'p$.$array[$i][Price]./p/td/tr\n;
}
}
}
?
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RE: [PHP-DB] Mysql result resource error
Hi Jim,
Ahh yes of courseI have corrected this.
I am still getting the error on the first query...not sure why. And now
I am getting a whole bunch of empty lines being output to the screen.
Like there is supposed to be data in those lines, but nothing happening.
Plus I am getting repeats of the same data. Its like it is doing each
query three times or something.
Don't know why it is doing that.
- Shannon
-Original Message-
From: Jim Lucas [mailto:[EMAIL PROTECTED]]
Sent: Friday, 21 December 2001 03:52 AM
To: Shannon Doyle; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Mysql result resource error
which one was giving you the problem? the first or second
mysql try. if it
was the second, try wrapping the $cattyname with single
quotes like this
Minor_Category = '$cattyname'. if the $cattyname var has anything but
numbers, the statement won't work.
Jim
- Original Message -
From: Shannon Doyle [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, December 19, 2001 4:19 PM
Subject: [PHP-DB] Mysql result resource error
Hi People,
I am getting a Not a valid Mysql result resource error with the
following code, can someone take a look at this for me and
see if there
is anything that stands out
Thanks,
Shannon
?
$cattyname = ;
$sql = select Minor_Category main where Page = 'wines' order by
Minor_Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results2 = mysql_db_query($db,$sql,$dbh);
for($j = 0; $j mysql_num_rows($results2); $j++) {
$array[$j] = mysql_fetch_array($results2);
}
mysql_close($dbh);
for ($h = 0; $h count($array); $h++) {
if ($array[$h][Minor_Category] != $cattyname) {
$cattyname = $array[$h][Minor_Category];
echo trtd colspan='4'a
name='.$cattyname.'/ab.$cattyname./b/td/td/tr;
$catname = ;
$sql = select Category,Code,Description,Pack,Unit,Price
from main where
Page = 'wines' Minor_Category = $cattyname order by Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results = mysql_db_query($db,$sql,$dbh);
for($i = 0; $i mysql_num_rows($results); $i++) {
$array[$i] = mysql_fetch_array($results);
}
mysql_close($dbh);
for ($i = 0; $i count($array); $i++) {
if ($array[$i][Category] != $catname) {
$catname = $array[$i][Category];
echo trtd colspan='4'a
name='.$catname.'/ab.$catname./b/tdtd
align='center'pbCarton Size/b/p/tdtd
align='center'pbUnit/b/p/tdtd
align='right'pbPrice/b/p/tdtda href='#top'img
src='images/arrow.gif' border='0'/a/td/tr;
}
echo trtd/tdtdpa
href=javascript:order_now(quot;.$array[$i][Code].quot;)img
src='images/order.gif' border='0'/a/tdtd/tdtd
align='left'p.$array[$i][Description]./p/tdtd
align='center'p.$array[$i][Pack]./p/tdtd
align='center'p.$array[$i][Unit]./p/tdtd
align='right'p$.$array[$i][Price]./p/td/tr\n;
}
}
}
?
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