RE: [PHP-DB] variable with NULL value
On 03 May 2007 16:22, OKi98 wrote: > Hi, > > one more question. > > Why the variable, that contains NULL value appears to be not > set. U -- because that's how it's defined?? (http://php.net/isset) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, JG125, The Headingley Library, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 812 4730 Fax: +44 113 812 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
Re: [PHP-DB] variable with NULL value
James Gadrow wrote:
OKi98 wrote:
Hi,
one more question.
Why the variable, that contains NULL value appears to be not set. When
you try to echo it the php does not produce warning about using
undefined variable.
//$connection contains database connection handler
$result=mysql_query("select NULL as value",$connection);
$tmp=mysql_fetch_array($result);
$foo=$tmp["value"];
if (!isset($foo)) echo("\$foo is not set but does not produce warning
-$foo-");
OKi98
Someone correct me if I'm wrong but it appears that you should be using
if(!isset($tmp["value"]) before assigning to $foo if you want to ensure
that $foo will, indeed, be set.
Yeh - you need to check before you do the assignment.
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Re: [PHP-DB] variable with NULL value
OKi98 wrote:
Hi,
one more question.
Why the variable, that contains NULL value appears to be not set. When
you try to echo it the php does not produce warning about using
undefined variable.
//$connection contains database connection handler
$result=mysql_query("select NULL as value",$connection);
$tmp=mysql_fetch_array($result);
$foo=$tmp["value"];
if (!isset($foo)) echo("\$foo is not set but does not produce warning
-$foo-");
OKi98
Someone correct me if I'm wrong but it appears that you should be using
if(!isset($tmp["value"]) before assigning to $foo if you want to ensure
that $foo will, indeed, be set.
--
Thanks,
Jim
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