date:20080815


 I apologize for my ignorance, I don't really know much about
 javascript. When I add all that into my form page, when I submit the
 form, it just replaces the page I was on with the form results, rather
 than in the new frame page. I'm assuming I need to put the url for the
 frameset page in that code somewhere. Where does it go? And, which
 part do I replace with the frame name on that frameset page?

 Thank you for taking the time to help me with this, I really appreciate it!



Let's look at the code:

//var1 and var2 are the search criteria the user entered in your search
form(You may have more or less)
function submitForm(var1,var2) {

//top.leftFrame is how you set the focus to the frame you want.  leftFrame
could be different on your system...whatever you named the frame.

//top.leftFrame.document.my_search.text1.value=var1 assumes the form name in
the frame you want data in is named
//my_search and it givs the text object text1 the value of var1 from your
search form
top.leftFrame.document.my_search.text1.value = var1;

//top.leftFrame.document.my_search.text2.value=var2 assumes the form name in
the frame you want data in is named
//my_search and it givs the text object text1 the value of var2 from your
search form
 top.leftFrame.document.my_search.text2.value = var2;

//top.leftFrame.document.my_search.submit() will submit the form in your
target frame then you can use the $_POST values throughout the frame
 top.leftFrame.document.my_search.submit();

//document.search_form.submit() will submit your search page. I use this so
I can reuse the $_POST values to display the search criteria after submit.
 document.search_form.submit();
}

Re: [PHP] Displaying files

If the network resource is the only location where these files exist, what
do you suggest I do?

Use PHP to first copy() the file from the server to a temp directory on my
web server and then open the document from the temp dir?


On 8/14/08, Boyd, Todd M. [EMAIL PROTECTED] wrote:

  -Original Message-
  From: Stut [mailto:[EMAIL PROTECTED]
  Sent: Thursday, August 14, 2008 4:34 PM
  To: Boyd, Todd M.
  Cc: php-general@lists.php.net
  Subject: Re: [PHP] Displaying files
 
  On 14 Aug 2008, at 22:24, Boyd, Todd M. wrote:
 
   -Original Message-
   From: Stut [mailto:[EMAIL PROTECTED]
   Sent: Thursday, August 14, 2008 4:21 PM
   To: Dan Shirah
   Cc: PHP-General List
   Subject: Re: [PHP] Displaying files
  
   On 14 Aug 2008, at 21:57, Dan Shirah wrote:
   That simply means it can't open the file. Make sure the machine
  this
   is running on has everything it needs to access that UNC filename.
  
   -Stut
  
  
   Stut,
  
   If I copy the link from the error message and paste it into a
   browser running from my PHP server, the file comes up just fine.
  
   Should I try mkdir() or mkpath() to set the server and folder
   location and then try it from there?
  
   The user PHP runs as needs to be able to access it, not you. I'm
   guessing you're on Windows...
  
   If you're using IIS then it's the IUSR_machine user which doesn't
   have
   access to the network by default. You can enable it but I can't
   recall
   how off the top of my head and you may want to reconsider because
 it
   leaves the server a lot more open should IIS/PHP/else be
  compromised.
  
   If you're using Apache on Windows then you'll need to check the
   service configuration to see what user it's running as.
  
   It can be done somewhat securely by mapping a network drive and then
   granting permissions to it specifically, rather than the network
   itself.
   (I believe...)
 
  It's been a while since I've used Windows but IIRC you need to enable
  network access for that user at the lowest layer (i.e. system policy)
  and then normal access rules apply, but I could be wrong. Either way
  I'd avoid doing it if at all possible.

 I think after XP SP2 it got a bit more granular. However, I'm no MCSE,
 so don't take my word for it. :) I do agree with you, anyway, that the
 user a webserver is posing as should not have access to network
 resources like this.

 I digress.


 Todd Boyd
 Web Programmer




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Re: [PHP] Displaying files

Okay, I'm perplexed!

If I put the exact same value into a javascript function and open a window
the document comes up perfectly fine.

But, when trying to readfile() copy() or fopen() in PHP I get the failed to
open stream: error.

Any idea why the exact same link would open fine using a HTML link or a
javascript function, but will not work using PHP?

Re: [PHP] Displaying files


On 15 Aug 2008, at 14:07, Dan Shirah wrote:

Okay, I'm perplexed!

If I put the exact same value into a javascript function and open a  
window

the document comes up perfectly fine.

But, when trying to readfile() copy() or fopen() in PHP I get the  
failed to

open stream: error.

Any idea why the exact same link would open fine using a HTML link  
or a

javascript function, but will not work using PHP?


Because as I mentioned before PHP runs as a different user to your  
browser.


-Stut

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Re: [PHP] Displaying files

2008-08-15 Thread Thiago H. Pojda

On 8/15/08, Dan Shirah [EMAIL PROTECTED] wrote:

 Okay, I'm perplexed!

 If I put the exact same value into a javascript function and open a window
 the document comes up perfectly fine.

 But, when trying to readfile() copy() or fopen() in PHP I get the failed
 to
 open stream: error.

 Any idea why the exact same link would open fine using a HTML link or a
 javascript function, but will not work using PHP?


I'm not sure I understand this... Can you provide some new code? :)

-- 
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Re: [PHP] Displaying files


On 15 Aug 2008, at 13:37, Dan Shirah wrote:
If the network resource is the only location where these files  
exist, what

do you suggest I do?

Use PHP to first copy() the file from the server to a temp directory  
on my

web server and then open the document from the temp dir?


PHP cannot access the file because the user it's running as has no  
network access. It has nothing to do with the method you use to access  
the file in PHP so copy will not work either.


If that other server is publicly accessible your best bet is to serve  
the file directly on that server - i.e. do an HTTP redirect to that  
file on the other server. If not then you're left with enabling  
network access for the PHP user. A quick Google got me this: http://support.microsoft.com/kb/207671 
 but there are other references out there.


-Stut


On 8/14/08, Boyd, Todd M. [EMAIL PROTECTED] wrote:



-Original Message-
From: Stut [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 14, 2008 4:34 PM
To: Boyd, Todd M.
Cc: php-general@lists.php.net
Subject: Re: [PHP] Displaying files

On 14 Aug 2008, at 22:24, Boyd, Todd M. wrote:


-Original Message-
From: Stut [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 14, 2008 4:21 PM
To: Dan Shirah
Cc: PHP-General List
Subject: Re: [PHP] Displaying files

On 14 Aug 2008, at 21:57, Dan Shirah wrote:

That simply means it can't open the file. Make sure the machine

this
is running on has everything it needs to access that UNC  
filename.


-Stut


Stut,

If I copy the link from the error message and paste it into a
browser running from my PHP server, the file comes up just fine.

Should I try mkdir() or mkpath() to set the server and folder
location and then try it from there?


The user PHP runs as needs to be able to access it, not you. I'm
guessing you're on Windows...

If you're using IIS then it's the IUSR_machine user which doesn't
have
access to the network by default. You can enable it but I can't
recall
how off the top of my head and you may want to reconsider because

it

leaves the server a lot more open should IIS/PHP/else be

compromised.


If you're using Apache on Windows then you'll need to check the
service configuration to see what user it's running as.


It can be done somewhat securely by mapping a network drive and  
then

granting permissions to it specifically, rather than the network
itself.
(I believe...)


It's been a while since I've used Windows but IIRC you need to  
enable
network access for that user at the lowest layer (i.e. system  
policy)

and then normal access rules apply, but I could be wrong. Either way
I'd avoid doing it if at all possible.


I think after XP SP2 it got a bit more granular. However, I'm no  
MCSE,
so don't take my word for it. :) I do agree with you, anyway, that  
the

user a webserver is posing as should not have access to network
resources like this.

I digress.


Todd Boyd
Web Programmer




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Re: [PHP] Displaying files


  Because as I mentioned before PHP runs as a different user to your
 browser.

 -Stut


Stut,

Are you referring to this?

If you're using IIS then it's the IUSR_machine user which doesn't have
access to the network by default

The IUSR_SERVERNAME account is what it should be connecting as whether I'm
using PHP/Javascript/HTML, unless specifically set in a connection string
such as the database connections.  But, the initial calls always come from
IUSR_SERVERNAME.

Thiago,

HTML WORKS
a href=\\server\folder\file.xls target=_blankOpen/a

Javascript WORKS
function openWin(folder,file) {
 var LeftPosition = (this.screen.width) / 2;
 var TopPosition = (this.screen.height) - this.screen.height;
 var Height = (this.screen.height) - 90;
 var Width = (this.screen.width) /2 - 10;
 MyWin = 
window.open(server\\+folder+\\+file+\.xls,ViewImage,scrollbars=yes,
status=yes,
resizable=no,top=+TopPosition+,left=+LeftPosition+,width=+Width+,height=+Height+);
 MyWin.focus();
}

PHP DOESN'T WORK
$filename = server\\.$folder.\\.$file..xls;
header(Content-Type: application/x-msdownload);
readfile($filename);

I put all three of these examples into the exact same page.  The HTML and
Javascript open the file without any problems, but PHP cannot open it.

Re: [PHP] Displaying files

2008-08-15 Thread Thiago H. Pojda

On 8/15/08, Dan Shirah [EMAIL PROTECTED] wrote:


 Thiago,

 HTML WORKS
 a href=\\server\folder\file.xls target=_blankOpen/a

 Javascript WORKS
 function openWin(folder,file) {
   var LeftPosition = (this.screen.width) / 2;
   var TopPosition = (this.screen.height) - this.screen.height;
   var Height = (this.screen.height) - 90;
   var Width = (this.screen.width) /2 - 10;
   MyWin =
 window.open(server\\+folder+\\+file+\.xls,ViewImage,scrollbars=yes,
 status=yes,

 resizable=no,top=+TopPosition+,left=+LeftPosition+,width=+Width+,height=+Height+);
   MyWin.focus();
 }


You JavaScript works because it's opening a Window and pointing it's URL to
a directory your BROWSER has access, that's client-side.
If I run your JS (or your HTML) code, it will not work as I don't have
access to that \\server share.

PHP (and your HTTP server) are on server-side, and they're not having access
to your file.


PHP DOESN'T WORK

 $filename = server\\.$folder.\\.$file..xls;
 header(Content-Type: application/x-msdownload);
 readfile($filename);



I put all three of these examples into the exact same page.  The HTML and
 Javascript open the file without any problems, but PHP cannot open it.




-- 
Thiago Henrique Pojda

Re: [PHP] Displaying files


On 15 Aug 2008, at 14:26, Dan Shirah wrote:
Because as I mentioned before PHP runs as a different user to your  
browser.


-Stut

Stut,

Are you referring to this?

If you're using IIS then it's the IUSR_machine user which doesn't  
have access to the network by default


The IUSR_SERVERNAME account is what it should be connecting as  
whether I'm using PHP/Javascript/HTML, unless specifically set in a  
connection string such as the database connections.  But, the  
initial calls always come from IUSR_SERVERNAME.


You need to understand that there are 2 sides to a web-based  
application, the client and the server. When you link the browser to a  
file (as in your HTML and JS code below) it's the *client* that's  
accessing the file. Neither IIS nor PHP get involved in that. This  
works because the browser is running as you and has sufficient  
permissions to access that network location.


When you try to do the same with PHP it is running as the  
IUSR_SERVERNAME user which, by default and for good reason, cannot  
access network shares in that way. The link I gave you should give you  
enough information to enable the required access for that user, but  
you might want to think carefully before doing so since it's disabled  
by default for security reasons.


-Stut


Thiago,

HTML WORKS
a href=\\server\folder\file.xls target=_blankOpen/a

Javascript WORKS
function openWin(folder,file) {
 var LeftPosition = (this.screen.width) / 2;
 var TopPosition = (this.screen.height) - this.screen.height;
 var Height = (this.screen.height) - 90;
 var Width = (this.screen.width) /2 - 10;
 MyWin = window.open(server\\+folder+\\+file 
+\.xls,ViewImage,scrollbars=yes, status=yes,   
resizable=no,top=+TopPosition+,left=+LeftPosition+,width=+Width 
+,height=+Height+);

 MyWin.focus();
}

PHP DOESN'T WORK
$filename = server\\.$folder.\\.$file..xls;
header(Content-Type: application/x-msdownload);
readfile($filename);

I put all three of these examples into the exact same page.  The  
HTML and Javascript open the file without any problems, but PHP  
cannot open it.





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Re: [PHP] Displaying files

Wow, I think it finally clicked.

Sorry that took so long.

The whole point behind using PHP was to try and copy or call the file from
the server side so the user does not see the path to the document. Using
HTML and Javascript it is extrememly easy to just view source and see the
path.  Whereas using PHP it would take the regular user a bit more work to
view the path which is why I wanted to go that route.  But having to grant
the anonymous internet account access to the server would be just as bad if
not worse.

My application retrieves a list of docments that the user can view based on
search criteria. When the user clicks on the document I wanted to somehow
mask the location the document is being pulled from.  HTML and Javascript
are so easy to circumvent, even to the everyday user that I wanted to do
something with PHP since it's code is not viewable when you view source
since it is run on the server.

Have any of you attempted something like this?

[PHP] Re: Passing variable to a page in a frameset

2008-08-15 Thread Jay Moore


Jody Cleveland wrote:

Hello,

I've got a website here: http://beta.menashalibrary.org/about

On every page, i've got a search box at the top. This search box 
searches the library's web catalog. The problem is, when someone 
searches, it takes them away from the site. What I'd like to do is take 
what a person searches for, and load it into the bottom frame of this page:
http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html 



Is there a way, with php, to take what someone puts in the search box 
and put the results into the bottom frame of a frameset when the 
originating page does not contain frames?


- jody


Frames?!

As a fellow Wisconsinite and a web developer, I'm going to have to ask 
you to leave the state.  Minnesota can have you.


:P


Jay


PS -  No, but seriously, frames?!?!

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Re: [PHP] Displaying files

2008-08-15 Thread Thiago H. Pojda

On 8/15/08, Dan Shirah [EMAIL PROTECTED] wrote:

 Wow, I think it finally clicked.

 Sorry that took so long.


That's fine, sorry if I sounded rude or something. I didn't mean it.


The whole point behind using PHP was to try and copy or call the file from
 the server side so the user does not see the path to the document. Using
 HTML and Javascript it is extrememly easy to just view source and see the
 path.  Whereas using PHP it would take the regular user a bit more work to
 view the path which is why I wanted to go that route.  But having to grant
 the anonymous internet account access to the server would be just as bad if
 not worse.


My guess is worse. :)


My application retrieves a list of docments that the user can view based on
 search criteria. When the user clicks on the document I wanted to somehow
 mask the location the document is being pulled from.  HTML and Javascript
 are so easy to circumvent, even to the everyday user that I wanted to do
 something with PHP since it's code is not viewable when you view source
 since it is run on the server.

 Have any of you attempted something like this?


You can have a php file called something like getFile.php where you pass
parameters like getFile.php?file=123 and it returns the file (with proper
headers).

But that way you'd have to map all file paths to a database. Then you could
access them thru codes, but remember to check user permissions before
handling him the file as you'd have a serious problem.

Aside of that, at the moment I can't figure another way of serving files for
a user hiding them the path for it.

I'd be happy to see what others have in mind. :)

-- 
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Re: [PHP] Displaying files

2008-08-15 Thread Jason Pruim



On Aug 15, 2008, at 9:57 AM, Dan Shirah wrote:


Wow, I think it finally clicked.

Sorry that took so long.

The whole point behind using PHP was to try and copy or call the  
file from
the server side so the user does not see the path to the document.  
Using
HTML and Javascript it is extrememly easy to just view source and  
see the
path.  Whereas using PHP it would take the regular user a bit more  
work to
view the path which is why I wanted to go that route.  But having to  
grant
the anonymous internet account access to the server would be just as  
bad if

not worse.

My application retrieves a list of docments that the user can view  
based on
search criteria. When the user clicks on the document I wanted to  
somehow
mask the location the document is being pulled from.  HTML and  
Javascript
are so easy to circumvent, even to the everyday user that I wanted  
to do
something with PHP since it's code is not viewable when you view  
source

since it is run on the server.

Have any of you attempted something like this?


What about using some type of a dispatch script? Locate all the files  
outside of the doc root and then just call: viewdocument.php? 
ID=12345678 ? Although now that I've typed that I realize that you  
would still be running the same issue.. Unless you used javascript in  
your PHP to call the file maybe?




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Raoset Inc.
Technology Manager
MQC Specialist
11287 James St
Holland, MI 49424
www.raoset.com
[EMAIL PROTECTED]





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Re: [PHP] Displaying files

  What about using some type of a dispatch script? Locate all the files
 outside of the doc root and then just call: viewdocument.php?ID=12345678 ?
 Although now that I've typed that I realize that you would still be running
 the same issue.. Unless you used javascript in your PHP to call the file
 maybe?


Hmmm, what if I tried to use PHP to write a simple batch file?  Use the
batch file to copy the selected file from one server to another.  And then
open the copied file using any method I wanted since it's new location would
be in a temp directory?

And then maybe use if_exists() to see if the new file is located in the temp
directory and if it is, display it.

The only issue there might be when a file is really large or the network is
sluggish and it could take 1-5 seconds for the file to copy over.  In which
case if_exists() would be false since it is taking a while for the file to
copy.  Hmmm.

Re: [PHP] Re: Passing variable to a page in a frameset


 Frames?!

 As a fellow Wisconsinite and a web developer, I'm going to have to ask you
 to leave the state.  Minnesota can have you.

 :P


 Jay


 PS -  No, but seriously, frames?!?!


There's nothing wrong with a Frame every once in a while!  Granted they
aren't used much anymore, but sometimes they can be useful!

Re: [PHP] Displaying files


On 15 Aug 2008, at 15:17, Dan Shirah wrote:
What about using some type of a dispatch script? Locate all the  
files outside of the doc root and then just call: viewdocument.php? 
ID=12345678 ? Although now that I've typed that I realize that you  
would still be running the same issue.. Unless you used javascript  
in your PHP to call the file maybe?


Hmmm, what if I tried to use PHP to write a simple batch file?  Use  
the batch file to copy the selected file from one server to  
another.  And then open the copied file using any method I wanted  
since it's new location would be in a temp directory?


And then maybe use if_exists() to see if the new file is located in  
the temp directory and if it is, display it.


The only issue there might be when a file is really large or the  
network is sluggish and it could take 1-5 seconds for the file to  
copy over.  In which case if_exists() would be false since it is  
taking a while for the file to copy.  Hmmm.


PHP *cannot* access those files. Doesn't matter if you call a batch  
file from the PHP since that will still be running as PHP.


Your best bet would be to run a periodic sync to copy the files across  
from the other server but it would have to run outside the IIS  
process. There are plenty of solutions around for doing this and they  
have nothing to do with PHP. You can then refer to the local copy of  
the file from PHP and it will then work.


-Stut

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Re: [PHP] Displaying files


  Your best bet would be to run a periodic sync to copy the files across
 from the other server but it would have to run outside the IIS process.
 There are plenty of solutions around for doing this and they have nothing to
 do with PHP. You can then refer to the local copy of the file from PHP and
 it will then work.


This isn't very feasible because the server that contains the documents
contains almost 1 terabyte worth of documents and continues to grow in size.
No way I would want to mirror that amount of information just to hude the
file path.

Instead of just making and executing a batch file, maybe there is a way for
PHP to call a scheduled task?  Since within a scheduled task you specify
what username/password is used to execute it I may be able to get it to
work?

Re: [PHP] Displaying files


On 15 Aug 2008, at 15:41, Dan Shirah wrote:
Your best bet would be to run a periodic sync to copy the files  
across from the other server but it would have to run outside the  
IIS process. There are plenty of solutions around for doing this and  
they have nothing to do with PHP. You can then refer to the local  
copy of the file from PHP and it will then work.


This isn't very feasible because the server that contains the  
documents contains almost 1 terabyte worth of documents and  
continues to grow in size. No way I would want to mirror that amount  
of information just to hude the file path.


Instead of just making and executing a batch file, maybe there is a  
way for PHP to call a scheduled task?  Since within a scheduled task  
you specify what username/password is used to execute it I may be  
able to get it to work?


A scheduled task is messy. IIWY I'd use FTP to pull the file over, but  
that's still pretty messy.


If this is an Intranet then the risks involved in giving that user  
access to the network is minimal and probably would be the best  
solution. Alternatively you could set up an HTTP server on the  
document server and proxy the documents through the IIS server  
(readfile should be happy to take an HTTP URL unless you've disabled  
it in php.ini, and the end user will never see the actual URL).


-Stut

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[PHP] Conditional compilation

2008-08-15 Thread Herman Gomez


Hi,

Here is something I used to do in C/C++ to include/exclude automaticaly 
all debugging code at compiling time:


#define debug TRUE
#ifdef(debug)
//debugging code
#endif

That way I can include/exclude easily all debugging code in the final 
compiled code. In PHP I have not been able to find anything like that.
The only solution I've found is having this kind of code in every debug 
code block:


if ($debug) {
//debugging code
}

But this means that the debugging code is in the final compiled 
(interpreted) code, wasting cpu cycles even if there won't be any 
debugging in production.


Does somebody know if there is something like conditional compilation in 
PHP that I can use?


Regards,
Herman Gomez
Madrid, Spain.

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Re: [PHP] Displaying files


 A scheduled task is messy. IIWY I'd use FTP to pull the file over, but
 that's still pretty messy.

 If this is an Intranet then the risks involved in giving that user access
 to the network is minimal and probably would be the best solution.
 Alternatively you could set up an HTTP server on the document server and
 proxy the documents through the IIS server (readfile should be happy to take
 an HTTP URL unless you've disabled it in php.ini, and the end user will
 never see the actual URL).


I agree, it is really messy to work with and prone to lots of complications.

This application will be used within our network, but will also be used by a
sister agency that is not in our network. Which is why we do not want the
document server complete path floating inbetween us and them where it could
be intercepted by an outside user.

Reading the documents through as a URL would be so nice and probably the
easiest method to accomplish this, but the God's Above want it to remain
strictly a file server.

I guess I will start looking into FTP'ing them between servers as that may
be the simplest solution at this point.

[PHP] Re: PHP editor for linux

2008-08-15 Thread Shawn McKenzie


It flance wrote:

Hi,

What do you think is the best php editor for linux.

I'm using the Debian distribution.

Thanks


  



I use Aptana which is based on eclipse and has built-in HTML/JS/PHP?SVN 
stuff.  Also a cool plugin that lets you easily develop for the iPhone 
and preview it.


-Shawn

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[PHP] PHP Script/Thread ID thingie

2008-08-15 Thread ceo


I'm logging things with error_log, and would like to be able to sort out one 
script run from another.



So I'm looking for some kind of script id or thread id or PHP script run 
execution ID type of function.



getmypid() just returns the same apache child process ID all the time, so 
that's not what I want.



zend_thread_id() looks useful, but I suspect it's not quite what I'm looking 
for.  But I'd have to re-compile with ZTS and --debug-mode and I don't think 
the function I'm looking for should require that...



Perhaps I've just missed the right function name?



Or perhaps this should be a Feature Request?



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RE: [PHP] Removing an element from the middle of an mdlti-dimentsional array

 -Original Message-
 From: Simcha Younger [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 2:49 AM
 To: 'Don'; php-general@lists.php.net
 Subject: RE: [PHP] Removing an element from the middle of an mdlti-
 dimentsional array
 
 
 array_splice($a, 1, 1);
 
 This will remove the second element, and reset the keys.
 
 
 -Original Message-
 From: Don [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 4:30 AM
 To: php-general@lists.php.net
 Subject: [PHP] Removing an element from the middle of an mdlti-
 dimentsional
 array
 
 Hi,
 
 Let's say I have the following array:
 
 $myArray = array(array('1','2','3'), array('4','5','6'),
 array('7','8','9'),
 
 array('10','11','12'));
 
 How do I remove say the second element?
 
 I have tried: $myArray = array_splice($myArray, 1, 1);
 
 But this seems to remove the second element as well as all the
 following
 elements and I am left with:
 
 $myArray = array(array('1','2','3'));
 
 when I really want:
 
 $myArray = array(array('1','2','3'), array('7','8','9'),
 array('10','11','12'));

Yep. He had been using the return value of array_splice(), which is just
the spliced elements--not the resulting array post-splice.

http://www.php.net/array_splice


Todd Boyd
Web Programmer




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Re: [PHP] PHP Script/Thread ID thingie


On 15 Aug 2008, at 16:37, [EMAIL PROTECTED] wrote:
I'm logging things with error_log, and would like to be able to sort  
out one script run from another.


So I'm looking for some kind of script id or thread id or PHP  
script run execution ID type of function.


getmypid() just returns the same apache child process ID all the  
time, so that's not what I want.


zend_thread_id() looks useful, but I suspect it's not quite what I'm  
looking for.  But I'd have to re-compile with ZTS and --debug-mode  
and I don't think the function I'm looking for should require that...


Perhaps I've just missed the right function name?

Or perhaps this should be a Feature Request?


Don't think there is such a thing, but you could generate one by  
combining the pid, timestamp and the script filename, maybe into an  
md5 hash value or similar. Thinking about it, ip.pid would be  
enough, i.e. 127.0.0.1.12345.


-Stut

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RE: [PHP] import XLS sheet into DB

 -Original Message-
 From: Alain R. [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 3:30 AM
 To: php-general@lists.php.net
 Subject: [PHP] import XLS sheet into DB

 Hi,

 I would like to import content of an XLS sheet into a PostgreSQL DB
 (table).

 How can i do that ?
 thanks a lot,

I fail to see how this has anything to do with PHP.

Regardless, I think you could just import it as a text field if you're
wanting to save the entire sheet. I'm not sure that I understand the
scope of your question.

Do you want the elements separated into table columns, or do you just
want to store the XLS for later retrieval as a whole?

Todd Boyd
Web Programmer

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Re: [PHP] PHP Script/Thread ID thingie

2008-08-15 Thread Eric Butera

On Fri, Aug 15, 2008 at 11:37 AM,  [EMAIL PROTECTED] wrote:

 I'm logging things with error_log, and would like to be able to sort out one 
 script run from another.

 So I'm looking for some kind of script id or thread id or PHP script run 
 execution ID type of function.

 getmypid() just returns the same apache child process ID all the time, so 
 that's not what I want.

 zend_thread_id() looks useful, but I suspect it's not quite what I'm looking 
 for.  But I'd have to re-compile with ZTS and --debug-mode and I don't think 
 the function I'm looking for should require that...

 Perhaps I've just missed the right function name?

 Or perhaps this should be a Feature Request?


I suppose if nobody else has better ideas you can fake it with setting
some sort of unique value and combining that with __FILE__ for your
instance run.

?php
$GLOBALS['instance'] = md5(uniqid());
error_log(__FILE__.$GLOBALS['instance'].'  first log');
error_log(__FILE__.$GLOBALS['instance'].' second log');
?

Not very glamorous though. ;)

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RE: [PHP] Re: Passing variable to a page in a frameset

 -Original Message-
 From: Dan Shirah [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 9:20 AM
 To: Jay Moore
 Cc: php-general@lists.php.net
 Subject: Re: [PHP] Re: Passing variable to a page in a frameset

  Frames?!

  As a fellow Wisconsinite and a web developer, I'm going to have to
 ask you
  to leave the state.  Minnesota can have you.

  :P

  Jay

  PS -  No, but seriously, frames?!?!

 There's nothing wrong with a Frame every once in a while!  Granted
they
 aren't used much anymore, but sometimes they can be useful!

I believe frames and framesets are being phased out of XHTML altogether.
It's all about DIVs nowadays. I think there's an XHTML specification for
something like frames, but it's just as ugly.

Todd Boyd
Web Programmer

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[PHP] preg_replace strange behaviour, duplicates

2008-08-15 Thread Adz07


I am trying to nail down a bit of code for changing processor names depending
on matches.
Problem i am having is the replacement takes place then it seems to do it
again replacing the text just replaced as there are similar matches
afterwards. example (easier)

$string = The new Intel Core 2 Duo T8300;

$patterns = array(/Intel Core 2 Duo/,/Intel Core 2/);

$replacements = array(/Intel Core 2 Duo Processor Technology/,/Intel Core
2 Processor Technology/);

I would expect to get the following:

The new Intel Core 2 Duo Processor Technology T8300

but i get 

The new Intel Core 2 Processor Technology Duo Processor Technology T8300

I can see why its doing it, reading the string in and making the replacement
but then reading the string in for the next pattern, but i don't want it to
do this. How do i stop preg_replace from reading in the same part of the
string that has been replaced already?

(it's a bad day! :( )
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Re: [PHP] Passing variable to a page in a frameset



On Aug 15, 2008, at 7:33 AM, Dan Shirah wrote:


I apologize for my ignorance, I don't really know much about
javascript. When I add all that into my form page, when I submit the
form, it just replaces the page I was on with the form results, rather
than in the new frame page. I'm assuming I need to put the url for the
frameset page in that code somewhere. Where does it go? And, which
part do I replace with the frame name on that frameset page?

Thank you for taking the time to help me with this, I really  
appreciate it!



Let's look at the code:

//var1 and var2 are the search criteria the user entered in your  
search form(You may have more or less)

function submitForm(var1,var2) {

//top.leftFrame is how you set the focus to the frame you want.   
leftFrame could be different on your system...whatever you named the  
frame.


//top.leftFrame.document.my_search.text1.value=var1 assumes the form  
name in the frame you want data in is named
//my_search and it givs the text object text1 the value of var1 from  
your search form

top.leftFrame.document.my_search.text1.value = var1;

//top.leftFrame.document.my_search.text2.value=var2 assumes the form  
name in the frame you want data in is named
//my_search and it givs the text object text1 the value of var2 from  
your search form

 top.leftFrame.document.my_search.text2.value = var2;

//top.leftFrame.document.my_search.submit() will submit the form in  
your target frame then you can use the $_POST values throughout the  
frame

 top.leftFrame.document.my_search.submit();

//document.search_form.submit() will submit your search page. I use  
this so I can reuse the $_POST values to display the search criteria  
after submit.

 document.search_form.submit();
}




In the head of my page, I have this:

script type=text/javascript
function submitForm(var1,var2) {
 top.mainFrame.document.my_search.text1.value = var1;
 top.mainFrame.document.my_search.text2.value = var2;
 top.mainFrame.document.my_search.submit();
 document.search_form.submit();
}
/script

Then, for the form code I have this:

form name=search_form method=post action=http://webcat.winnefox.org/web2/tramp2.exe/do_keyword_search/guest 
 id=qpl

input type=hidden name=SETTING_KEY value=Menasha /
input type=hidden name=index value=default /
input TYPE=hidden NAME=hitlist_screen VALUE=hitlist.html /
input TYPE=hidden NAME=record_screen VALUE=Record.html /
input type=hidden name=query_screen value=home.html /
input type=hidden name=servers value=1home /
	Find library books, music, movies and more...input  
class=searchbartextfield id=query name=query type=text  	a  
href 
= 
javascript:submitForm 
(document 
.search_form.var1.value,document.search_form.var2.value)SEARCH/ 
anbsp;a id=topNav_advanced_search href=/sites/ 
beta.menashalibrary.org/themes/salamander/searchframe.htmlAdvanced  
Search/a

/form

If I type in a word in the search box http://beta.menashalibrary.org/about 
 and hit enter, it searches the catalog just fine, but then just  
replaces the current page with the search results. If I click on the  
SEARCH link with the javascript, it does nothing.


I want the results to go to this url: 
http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html
in the frame name of mainFrame. I'm thinking that address needs to go  
in the javascript somewhere so it knows where to go, but where? Does  
the rest of the code look ok?


Thanks again for taking the time to help me with this.

- jody

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Re: [PHP] Re: Passing variable to a page in a frameset



On Aug 15, 2008, at 9:20 AM, Dan Shirah wrote:



Frames?!


As a fellow Wisconsinite and a web developer, I'm going to have to  
ask you

to leave the state.  Minnesota can have you.

:P


Jay


PS -  No, but seriously, frames?!?!



There's nothing wrong with a Frame every once in a while!  Granted  
they

aren't used much anymore, but sometimes they can be useful!


I know, I know. I'm not a fan of frames either, and have never even  
thought of using them until now. The problem is, our library catalog  
is on a different server and provides results for a consortium of 30  
libraries. So, what we've been doing is including a search box for the  
catalog on web pages. Which works fine, but it's easy for people to  
get caught up in the catalog with no good way to get back to the site  
you came from. So, I created a frame page that has a small button in  
the top frame that takes you back to where you came from. So, the site  
itself isn't using frames, only when you search the catalog. Of  
course, that's if I can get it working...


- jody

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Re: [PHP] Passing variable to a page in a frameset


 In the head of my page, I have this:

 script type=text/javascript
 function submitForm(var1,var2) {
  top.mainFrame.document.my_search.text1.value = var1;
  top.mainFrame.document.my_search.text2.value = var2;
  top.mainFrame.document.my_search.submit();
  document.search_form.submit();
 }
 /script

 If I type in a word in the search box http://beta.menashalibrary.org/about and
 hit enter, it searches the catalog just fine, but then just replaces the
 current page with the search results. If I click on the SEARCH link with the
 javascript, it does nothing.



It looks like you haven't adapted the example I gave you to conform to your
page/form structure.

top.mainFrame.document.my_search.text1.value = var1;

The frame you are populating may not be named mainFrame
The form in your destination frame may not be named my_search
The input in you destination frame may not be text1

You have to modify these areas to suit your application and add or remove
more as needed.

Re: [PHP] Re: PHP editor for linux

2008-08-15 Thread Richard Heyes

 What do you think is the best php editor for linux.

pico :-)

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Re: [PHP] Re: PHP editor for linux

2008-08-15 Thread Nathan Nobbe

On Fri, Aug 15, 2008 at 10:40 AM, Richard Heyes [EMAIL PROTECTED] wrote:

  What do you think is the best php editor for linux.

 pico :-)


ed baby; its all about ed!

-nathan

Re: [PHP] Re: PHP editor for linux

On Fri, 2008-08-15 at 10:43 -0600, Nathan Nobbe wrote:
 On Fri, Aug 15, 2008 at 10:40 AM, Richard Heyes [EMAIL PROTECTED] wrote:
 
   What do you think is the best php editor for linux.
 
  pico :-)
 
 
 ed baby; its all about ed!

hexedit /dev/sda1

;)

Cheers,
Rob.
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Application and Templating Framework for PHP


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Re: [PHP] Re: PHP editor for linux

2008-08-15 Thread Davi Vidal

Em Friday 15 August 2008, Robert Cummings escreveu:
 On Fri, 2008-08-15 at 10:43 -0600, Nathan Nobbe wrote:
  On Fri, Aug 15, 2008 at 10:40 AM, Richard Heyes [EMAIL PROTECTED] wrote:
What do you think is the best php editor for linux.
  
   pico :-)
 
  ed baby; its all about ed!

 hexedit /dev/sda1

 ;)


Butterflies. :-)

http://xkcd.com/378/

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[PHP] SESSION problem

2008-08-15 Thread tedd


Hi gang:

Arrggg -- what the heck is going on?

I can't get anything to pass via SESSION -- what's wrong?

Here's the example -- (all the code is there):

I populate the $_SESSIONs here.

http://www.webbytedd.com/b2/session-test/index.php

If you click Proceed to Step 2, you'll see that nothing is passed.

Now, where did I go wrong?

Cheers,

tedd

PS: I've tried this on two different servers and get the same results.

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Re: [PHP] SESSION problem

2008-08-15 Thread Dan Joseph

On Fri, Aug 15, 2008 at 1:09 PM, tedd [EMAIL PROTECTED] wrote:

 Hi gang:

 Arrggg -- what the heck is going on?

 I can't get anything to pass via SESSION -- what's wrong?

 Here's the example -- (all the code is there):

 I populate the $_SESSIONs here.

 http://www.webbytedd.com/b2/session-test/index.php

 If you click Proceed to Step 2, you'll see that nothing is passed.

 Now, where did I go wrong?

 Cheers,

 tedd

 PS: I've tried this on two different servers and get the same results.

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What's in your header.php?

-- 
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www.canishosting.com - Plans start @ $1.99/month.

Build a man a fire, and he will be warm for the rest of the day.
Light a man on fire, and will be warm for the rest of his life.

Re: [PHP] Re: PHP editor for linux

On Fri, 2008-08-15 at 14:06 -0300, Davi Vidal wrote:
 Em Friday 15 August 2008, Robert Cummings escreveu:
  On Fri, 2008-08-15 at 10:43 -0600, Nathan Nobbe wrote:
   On Fri, Aug 15, 2008 at 10:40 AM, Richard Heyes [EMAIL PROTECTED] wrote:
 What do you think is the best php editor for linux.
   
pico :-)
  
   ed baby; its all about ed!
 
  hexedit /dev/sda1
 
  ;)
 
 
 Butterflies. :-)
 
 http://xkcd.com/378/


That's great... I love those cartoons.

Cheers,
Rob.
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Application and Templating Framework for PHP


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Re: [PHP] Passing variable to a page in a frameset



On Aug 15, 2008, at 11:32 AM, Dan Shirah wrote:


In the head of my page, I have this:

script type=text/javascript
function submitForm(var1,var2) {
 top.mainFrame.document.my_search.text1.value = var1;
 top.mainFrame.document.my_search.text2.value = var2;
 top.mainFrame.document.my_search.submit();
 document.search_form.submit();
}
/script

If I type in a word in the search box http://beta.menashalibrary.org/about 
 and hit enter, it searches the catalog just fine, but then just  
replaces the current page with the search results. If I click on the  
SEARCH link with the javascript, it does nothing.



It looks like you haven't adapted the example I gave you to conform  
to your page/form structure.


top.mainFrame.document.my_search.text1.value = var1;

The frame you are populating may not be named mainFrame
The form in your destination frame may not be named my_search
The input in you destination frame may not be text1

You have to modify these areas to suit your application and add or  
remove more as needed.


So, I had this all wrong before. Basically, I need two forms, right?  
One on my originating page, and one on the page within the frameset I  
want to pass the values to. Correct?


My form, which I named my_search has one input field, which I named  
query. In the javascript, I put in this:


script type=text/javascript
function submitForm(var1,var2) {
 top.mainFrame.document.my_search.query.value = var1;
 top.mainFrame.document.my_search.submit();
 document.search_form.submit();
}
/script

In the framset named mainFrame, I have a page which matches the form  
on the originating page.


Am I on the right track? When I click on the search link, nothing  
happens.


- jody

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Re: [PHP] Passing variable to a page in a frameset


  So, I had this all wrong before. Basically, I need two forms, right? One
 on my originating page, and one on the page within the frameset I want to
 pass the values to. Correct?

 My form, which I named my_search has one input field, which I named query.
 In the javascript, I put in this:

 script type=text/javascript
 function submitForm(var1,var2) {
  top.mainFrame.document.my_search.query.value = var1;
  top.mainFrame.document.my_search.submit();
  document.search_form.submit();
 }
 /script

 In the framset named mainFrame, I have a page which matches the form on
 the originating page.

 Am I on the right track? When I click on the search link, nothing happens.


mainFrame should not be the name of your frameset.  Say I have a frameset
with three sections. Top, Left, and Right...you will actually have 4 pages.

Frameset.php //The top level of the frameset that doesn't do much more than
assign the Frame names and pages associated with them
TopSection.php //Anything on this page will be displayed in your top frame
LeftSection.php // Anything on this page will be displayed in your left
frame
RightSection.php //Anything on this page will be displayed in your right
frame

In order to see the names assigned to your different frames you need to open
Frameset.php and look for them.

It will look something like this:

frameset rows=200,* cols=* framespacing=0 frameborder=NO
border=1
  frame src=TopSection.php name=topFrame scrolling=NO noresize 
  frame src=LeftSection.php name=leftFrame
  frame src=RightSection.php name=rightFrame
/frameset

You should never need to reference Framset.php directly.

Say I wanted to pass a value from TopSection.php to a text field in
LeftSection.php I would do this:

TopSection.php
form name=search_form method=post action=?php echo
$_SERVER['PHP_SELF']; ?
input type=text name=search_name value= //The default value will be
blank but will change if someone enters in text.
/form

//Now the persons submits the form and you want the search name to populate
to your other frame.
a
href=javascript:submitForm(document.search_form.search_name.value)SEARCH/a

//The Javascript function this calls will pass the
document.search_form.search_name.value to the new form
function submitForm(name) {
 top.leftFrame.document.my_search.search_name.value = name;
 document.search_form.submit();
}
//top goes to the highest level of your frameset, leftFrame is the frame
name specified for LeftSection.php on your Frameset.php page,
document.my_search is the name of your form in
//LeftSection.php, search_name is the name of your text field within the
form in LeftSection.php

//Your TopSection.php form has now passed the search_name value to the
LeftSection.php page

LeftSection.php
form name=my_search method=post action=
input type=text name=search_name value=
/form

That should be enough to get you going.  If you have any further questions
lets take this Off List since it does not relate to PHP.

Dan

Re: [PHP] SESSION problem

2008-08-15 Thread Philip Thompson


On Aug 15, 2008, at 12:16 PM, Dan Joseph wrote:


On Fri, Aug 15, 2008 at 1:09 PM, tedd [EMAIL PROTECTED] wrote:


Hi gang:

Arrggg -- what the heck is going on?

I can't get anything to pass via SESSION -- what's wrong?

Here's the example -- (all the code is there):

I populate the $_SESSIONs here.

http://www.webbytedd.com/b2/session-test/index.php

If you click Proceed to Step 2, you'll see that nothing is passed.

Now, where did I go wrong?

Cheers,

tedd

PS: I've tried this on two different servers and get the same  
results.




What's in your header.php?


It probably won't make a difference, but you may try:

?php
for ($i = 1; $i = 10; $i++) {
echo($i = {$_SESSION[$i]} br/);
}
?

Throw the $_SESSION into {}.

~Philip

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[PHP] Sessions - Failed to initialize storage...

2008-08-15 Thread Chris Ditty

Can someone tell me what I am missing here?  This is working fine on my 
development machine(5.2.6), but on the production box(4.3.2), it doesn't want 
to work.  I am getting that error on my session_start() function. 

Is the difference in versions what is causing the problems?

I've googled and none of the results fit my problem.  Below is my .htaccess 
file.
php_value session.save_handler files
php_value session.save_path /tmp
php_value session.name PHPSESSID
php_flag session.auto_start off
php_value session.cookie_path /
php_flag session.use_cookies on
php_value session.cache_expire 180
php_flag session.use_trans_sid on



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RE: [PHP] Re: PHP editor for linux

 -Original Message-

 From: Davi Vidal [mailto:[EMAIL PROTECTED]

 Sent: Friday, August 15, 2008 12:07 PM

 To: php-general@lists.php.net

 Subject: Re: [PHP] Re: PHP editor for linux

 

 Em Friday 15 August 2008, Robert Cummings escreveu:

  On Fri, 2008-08-15 at 10:43 -0600, Nathan Nobbe wrote:

   On Fri, Aug 15, 2008 at 10:40 AM, Richard Heyes [EMAIL PROTECTED]

 wrote:

 What do you think is the best php editor for linux.

   

pico :-)

  

   ed baby; its all about ed!

 

  hexedit /dev/sda1

 

  ;)

 

 

 Butterflies. :-)

 

 http://xkcd.com/378/

 

Haha! Yes! That is one of my favorite XKCD strips. Kudos, my friend.

For those of you who are unfamiliar--give it a click. You won't be
sorry.

 

 

Todd Boyd

Web Programmer

Re: [PHP] Sessions - Failed to initialize storage...

2008-08-15 Thread Bojan Tesanovic


Can you give us the exact error that you got, that can help to debug ...


On Aug 15, 2008, at 7:53 PM, Chris Ditty wrote:

Can someone tell me what I am missing here?  This is working fine  
on my development machine(5.2.6), but on the production box(4.3.2),  
it doesn't want to work.  I am getting that error on my  
session_start() function.


Is the difference in versions what is causing the problems?

I've googled and none of the results fit my problem.  Below is  
my .htaccess file.

php_value session.save_handler files
php_value session.save_path /tmp
php_value session.name PHPSESSID
php_flag session.auto_start off
php_value session.cookie_path /
php_flag session.use_cookies on
php_value session.cache_expire 180
php_flag session.use_trans_sid on



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check payment status and pay online,
go to www.mlgw.com and click on the My Account link.
Enroll today!


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Bojan Tesanovic
http://classiccars.carster.us/

Re: [PHP] Displaying files

2008-08-15 Thread Philip Thompson


On Aug 14, 2008, at 3:29 PM, Dan Shirah wrote:



You need to know the mime type for the file you're serving. Call

header('Content-Type: x/y'); where x/y is the mime type. Then call
readfile('/path/to/file/on/server'); to output the file to the  
browser.


-Stut





Stut, trying that method gives me the following: PHP Warning:   
readfile(

\\server\folder\file.xls) [a
href='function.readfile'function.readfile/a]: failed to open  
stream:

Invalid argument on line 44

Here's my code.  Line 44 is where it stated readfile()
This document is located on a seperate server.


?php
$folder = $_GET['folder'];
$file = $_GET['file'];

$filename = server\\.$folder.\\.$file..xls;
header(Content-Type: application/x-msdownload);
readfile($filename);
?


This won't address the permissions issue, but I ran into a similar  
problem where IE wouldn't open the file unless 'exit;' was  present.  
You may want to add:


?php
readfile($filename);
exit;
?

Cheers,
~Philip


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[PHP] Buffering problem

2008-08-15 Thread Anders Norrbring

I'm trying to make php output things sequentially as they're
printed/echoed.. No luck. It's buffered to the end of the script, and then
it comes on to screen.
This is while running Apache2, in a cli session it works fine.

The script does *not* have any buffering commands at all.
The web server does not have mod_gzip installed.

I'm running out of ideas to where to look for this, so can you please give
me some pointers?

Anders.


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Re: [PHP] Sessions - Failed to initialize storage...

2008-08-15 Thread Chris Ditty

Fatal error: session_start(): Failed to initialize storage module. in 
/home/webroot/www/service/payarrange/index.php on line 4

Line 4 is the session_start();

 Bojan Tesanovic [EMAIL PROTECTED] 8/15/2008 1:10 PM 
Can you give us the exact error that you got, that can help to debug ...


On Aug 15, 2008, at 7:53 PM, Chris Ditty wrote:

 Can someone tell me what I am missing here?  This is working fine  
 on my development machine(5.2.6), but on the production box(4.3.2),  
 it doesn't want to work.  I am getting that error on my  
 session_start() function.

 Is the difference in versions what is causing the problems?

 I've googled and none of the results fit my problem.  Below is  
 my .htaccess file.
 php_value session.save_handler files
 php_value session.save_path /tmp
 php_value session.name PHPSESSID
 php_flag session.auto_start off
 php_value session.cookie_path /
 php_flag session.use_cookies on
 php_value session.cache_expire 180
 php_flag session.use_trans_sid on



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 check payment status and pay online,
 go to www.mlgw.com and click on the My Account link.
 Enroll today!


 This e-mail and any attachments represent the views and opinions
 of only the sender and are not necessarily those of
 Memphis Light, Gas  Water Division, and no such inference should  
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RE: [PHP] Re: Passing variable to a page in a frameset

2008-08-15 Thread Warren Vail

Actually you may want to check back with basic html at the target
parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]
 
 

 -Original Message-
 From: Jay Moore [mailto:[EMAIL PROTECTED] 
 Sent: Friday, August 15, 2008 7:03 AM
 To: php-general@lists.php.net
 Subject: [PHP] Re: Passing variable to a page in a frameset
 
 Jody Cleveland wrote:
  Hello,
  
  I've got a website here: http://beta.menashalibrary.org/about
  
  On every page, i've got a search box at the top. This search box 
  searches the library's web catalog. The problem is, when someone 
  searches, it takes them away from the site. What I'd like to do is 
  take what a person searches for, and load it into the 
 bottom frame of this page:
  
 http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/sa
  lamander/searchframe.html
  
  
  Is there a way, with php, to take what someone puts in the 
 search box 
  and put the results into the bottom frame of a frameset when the 
  originating page does not contain frames?
  
  - jody
 
 Frames?!
 
 As a fellow Wisconsinite and a web developer, I'm going to 
 have to ask you to leave the state.  Minnesota can have you.
 
 :P
 
 
 Jay
 
 
 PS -  No, but seriously, frames?!?!
 
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Re: [PHP] Buffering problem

2008-08-15 Thread Dan Joseph

On Fri, Aug 15, 2008 at 2:18 PM, Anders Norrbring [EMAIL PROTECTED]wrote:

 I'm trying to make php output things sequentially as they're
 printed/echoed.. No luck. It's buffered to the end of the script, and then
 it comes on to screen.
 This is while running Apache2, in a cli session it works fine.

 The script does *not* have any buffering commands at all.
 The web server does not have mod_gzip installed.

 I'm running out of ideas to where to look for this, so can you please give
 me some pointers?

 Anders.


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Take a look at http://us.php.net/manual/en/function.ob-flush.php -- There
are some examples at the bottom on how to do this.

-- 
-Dan Joseph

www.canishosting.com - Plans start @ $1.99/month.

Build a man a fire, and he will be warm for the rest of the day.
Light a man on fire, and will be warm for the rest of his life.

[PHP] How to submit form via PHP

2008-08-15 Thread pe . ve . ce

Hello. I'm pretty noob in PHP and would like to know how can I submit some HTML 
form got via file_get_contents(URL). For example:

form name=someform method=post
input type=submit
/form

so how can I submit 'someform' form.

Thanks in advance for any suggestions.

Matěj czech_d3v3l0p3r Grabovský

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[PHP] Re: Buffering problem

2008-08-15 Thread Lupus Michaelis


Anders Norrbring a écrit :

I'm running out of ideas to where to look for this, so can you please give
me some pointers?


  I guess it is that you're seeking for :
http://fr.php.net/manual/en/outcontrol.configuration.php#ini.implicit-flush



--
Mickaël Wolff aka Lupus Michaelis
http://lupusmic.org

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RE: [PHP] How to submit form via PHP

2008-08-15 Thread Jay Blanchard

[snip]
Hello. I'm pretty noob in PHP and would like to know how can I submit
some HTML form got via file_get_contents(URL). For example:

form name=someform method=post
input type=submit
/form

so how can I submit 'someform' form.

Thanks in advance for any suggestions.
[/snip]

Click 'Submit'



Your form tag needs an action statement

form name=someform action=some.php method=POST

All of the form's variables will be available in the $_POST array

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Re: [PHP] Re: Passing variable to a page in a frameset



On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:


Actually you may want to check back with basic html at the target
parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]


Target won't work for me because the originating page with the search  
box is not part of any frameset. I'm trying to get the search results  
from that page to go to a page that is part of a frameset.


- jody

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RE: [PHP] How to submit form via PHP

On Fri, 2008-08-15 at 13:30 -0500, Jay Blanchard wrote:
 [snip]
 Hello. I'm pretty noob in PHP and would like to know how can I submit
 some HTML form got via file_get_contents(URL). For example:
 
 form name=someform method=post
 input type=submit
 /form
 
 so how can I submit 'someform' form.
 
 Thanks in advance for any suggestions.
 [/snip]
 
 Click 'Submit'
 
 
 
 Your form tag needs an action statement

No it doesn't... without an action statement it will submit to the same
URL in which it was presented.

Cheers,
Rob.
-- 
http://www.interjinn.com
Application and Templating Framework for PHP


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Re: [PHP] How to submit form via PHP

2008-08-15 Thread Dotan Cohen

2008/8/15 Jay Blanchard [EMAIL PROTECTED]:
 [snip]
 Hello. I'm pretty noob in PHP and would like to know how can I submit
 some HTML form got via file_get_contents(URL). For example:

 form name=someform method=post
 input type=submit
 /form

 so how can I submit 'someform' form.

 Thanks in advance for any suggestions.
 [/snip]

 Click 'Submit'



 Your form tag needs an action statement

 form name=someform action=some.php method=POST

 All of the form's variables will be available in the $_POST array


I think he's asking how to make a POST request via
file_get_contents(URL), as opposed to a GET request.

-- 
Dotan Cohen

http://what-is-what.com
http://gibberish.co.il
א-ב-ג-ד-ה-ו-ז-ח-ט-י-ך-כ-ל-ם-מ-ן-נ-ס-ע-ף-פ-ץ-צ-ק-ר-ש-ת

A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?

RE: [PHP] How to submit form via PHP

2008-08-15 Thread Warren Vail

Key to this one may be understanding what is being asked.  I think pe.ve.ce
performed a file read (file_get_contents) on the form from another website
and wants to be able to simulate a browser submit from his code.

If this is correct, I would recommend you take a look at CURL.  There are
probably several approaches that work, but as I understand that CURL is an
implementation of the C libraries used by early browsers.  If that is not
correct, someone here will set us straight.  Many ISP's won't support CURL,
because it is often used for questionable activities and considered a
security exposure, but I believe CURL is what you want.

Hth,

Warren Vail

 -Original Message-
 From: Jay Blanchard [mailto:[EMAIL PROTECTED] 
 Sent: Friday, August 15, 2008 11:31 AM
 To: [EMAIL PROTECTED]; php-general@lists.php.net
 Subject: RE: [PHP] How to submit form via PHP
 
 [snip]
 Hello. I'm pretty noob in PHP and would like to know how can 
 I submit some HTML form got via file_get_contents(URL). For example:
 
 form name=someform method=post
 input type=submit
 /form
 
 so how can I submit 'someform' form.
 
 Thanks in advance for any suggestions.
 [/snip]
 
 Click 'Submit'
 
 
 
 Your form tag needs an action statement
 
 form name=someform action=some.php method=POST
 
 All of the form's variables will be available in the $_POST array
 
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Re: [PHP] Re: Passing variable to a page in a frameset


On 15 Aug 2008, at 19:39, Jody Cleveland wrote:

On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:


Actually you may want to check back with basic html at the target
parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]


Target won't work for me because the originating page with the  
search box is not part of any frameset. I'm trying to get the search  
results from that page to go to a page that is part of a frameset.


Are you saying that the frame you want to have the search results  
shown in doesn't exist when the search form is submitted? If it does  
then it doesn't matter where the form is, just specify the target as  
the name of the frame and it will almost certainly work.


If however you want the search to create the frameset when it runs  
then you have a completely different problem which is best solved  
using some sort of session. The script that handles the POST will need  
to store the details of the search somewhere and output the frameset.  
The frame that needs to contain the results would then grab the  
details and run the search outputting the results.


If I'm completely misunderstanding you please feel free to elaborate.

-Stut

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RE: [PHP] SESSION problem

 -Original Message-
 From: tedd [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 12:10 PM
 To: php-general@lists.php.net
 Subject: [PHP] SESSION problem

 Hi gang:

 Arrggg -- what the heck is going on?

 I can't get anything to pass via SESSION -- what's wrong?

 Here's the example -- (all the code is there):

 I populate the $_SESSIONs here.

 http://www.webbytedd.com/b2/session-test/index.php

 If you click Proceed to Step 2, you'll see that nothing is passed.

 Now, where did I go wrong?

 Cheers,

 tedd

 PS: I've tried this on two different servers and get the same results.

Have you tried:

echo SID;

...? I'm wondering if you're going to get different values on the two
pages. What that means beyond two different sessions is beyond me, but
it's a start.

Todd Boyd
Web Programmer

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Re: [PHP] Re: Passing variable to a page in a frameset



On Aug 15, 2008, at 1:46 PM, Stut wrote:


On 15 Aug 2008, at 19:39, Jody Cleveland wrote:

On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:


Actually you may want to check back with basic html at the target
parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]


Target won't work for me because the originating page with the  
search box is not part of any frameset. I'm trying to get the  
search results from that page to go to a page that is part of a  
frameset.


Are you saying that the frame you want to have the search results  
shown in doesn't exist when the search form is submitted? If it does  
then it doesn't matter where the form is, just specify the target as  
the name of the frame and it will almost certainly work.


If however you want the search to create the frameset when it runs  
then you have a completely different problem which is best solved  
using some sort of session. The script that handles the POST will  
need to store the details of the search somewhere and output the  
frameset. The frame that needs to contain the results would then  
grab the details and run the search outputting the results.


That is exactly what I want. I apologize for the confusion. I was  
having a hard time trying to put what I was trying to do in words.  
But, yes, your second paragraph is exactly what I want to do. My  
knowledge of PHP is very limited, and I've tried to search for  
something that will do this, but couldn't find anything.


- jody


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RE: [PHP] Re: Passing variable to a page in a frameset

2008-08-15 Thread Warren Vail

Probably something I don't understand about your implementation, but the
form parameter will allow a target parameter, and if the frameset contains a
frame that is named (even one different from the one that contains the
search form), the results should be placed in the target frame.  Without a
target, if the form is outside the frameset, it will replace the entire
frameset, exactly what you describe.

Warren 

 -Original Message-
 From: Jody Cleveland [mailto:[EMAIL PROTECTED] 
 Sent: Friday, August 15, 2008 11:40 AM
 To: php-general@lists.php.net
 Subject: Re: [PHP] Re: Passing variable to a page in a frameset
 
 
 On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:
 
  Actually you may want to check back with basic html at the target
  parameter on your search form statement.
 
  HTH,
 
  Warren Vail
  Vail Systems Technology
  [EMAIL PROTECTED]
 
 Target won't work for me because the originating page with 
 the search box is not part of any frameset. I'm trying to get 
 the search results from that page to go to a page that is 
 part of a frameset.
 
 - jody
 
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RE: [PHP] How to submit form via PHP

2008-08-15 Thread Jay Blanchard

[snip]
On Fri, 2008-08-15 at 13:30 -0500, Jay Blanchard wrote:
 [snip]
 Hello. I'm pretty noob in PHP and would like to know how can I submit
 some HTML form got via file_get_contents(URL). For example:
 
 form name=someform method=post
 input type=submit
 /form
 
 so how can I submit 'someform' form.
 
 Thanks in advance for any suggestions.
 [/snip]
 
 Click 'Submit'
 
 
 
 Your form tag needs an action statement

No it doesn't... without an action statement it will submit to the same
URL in which it was presented.
[/snip]

True, I was just eyeballs deep in coding something and answered much too
quickly.

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Re: [PHP] Re: Passing variable to a page in a frameset


On 15 Aug 2008, at 19:50, Jody Cleveland wrote:

On Aug 15, 2008, at 1:46 PM, Stut wrote:

On 15 Aug 2008, at 19:39, Jody Cleveland wrote:

On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:


Actually you may want to check back with basic html at the target
parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]


Target won't work for me because the originating page with the  
search box is not part of any frameset. I'm trying to get the  
search results from that page to go to a page that is part of a  
frameset.


Are you saying that the frame you want to have the search results  
shown in doesn't exist when the search form is submitted? If it  
does then it doesn't matter where the form is, just specify the  
target as the name of the frame and it will almost certainly work.


If however you want the search to create the frameset when it runs  
then you have a completely different problem which is best solved  
using some sort of session. The script that handles the POST will  
need to store the details of the search somewhere and output the  
frameset. The frame that needs to contain the results would then  
grab the details and run the search outputting the results.


That is exactly what I want. I apologize for the confusion. I was  
having a hard time trying to put what I was trying to do in words.  
But, yes, your second paragraph is exactly what I want to do. My  
knowledge of PHP is very limited, and I've tried to search for  
something that will do this, but couldn't find anything.


Ok, then I have to ask the question... why frames?

If you really need frames then you need to come up with a way to pass  
the search from the script the search form loads to the specific frame  
in the frameset it outputs. You could do this through a GET parameter,  
or via a session or in several other ways. In any case you'd be far  
better off not using frames if possible, so why frames?


-Stut

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Re: [PHP] Re: Passing variable to a page in a frameset


 That is exactly what I want. I apologize for the confusion. I was having a
 hard time trying to put what I was trying to do in words. But, yes, your
 second paragraph is exactly what I want to do. My knowledge of PHP is very
 limited, and I've tried to search for something that will do this, but
 couldn't find anything.

 - jody


In that case, I would not use frames at all.  I believe in the top frame all
you wanted to store was the search text, right?

Just have your search link do something like this:

html
head
script language=JavaScript
!--
function submitForm() {
 document.search_form.action='
http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html
';
 document.search_form.submit();
}
//--
/script
/head
body
form name=search_form method=post action=
input type=text name=search_name value=
a href=javascript:submitForm()SEARCH/a
/form
/body
/html

And then on
http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html
just
assign your posted search value and make a hidden form field.
html
head
body
?php
$searched_text = $_POST['search_name'];
?
form name=my_search method=post action=
input type=hidden name=search_text value=$searched_text
table width='800' border='0' align='center' cellpadding='2' cellspacing='2'
bordercolor='#00'
tr
td?php echo You searched for: .$searched_text; ?/td
/tr
/table
/form
/body
/html

Re: [PHP] preg_replace strange behaviour, duplicates

2008-08-15 Thread Micah Gersten

Take a look at the negative assertions on this page:
http://us2.php.net/manual/en/regexp.reference.php

Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



Adz07 wrote:
 I am trying to nail down a bit of code for changing processor names depending
 on matches.
 Problem i am having is the replacement takes place then it seems to do it
 again replacing the text just replaced as there are similar matches
 afterwards. example (easier)

 $string = The new Intel Core 2 Duo T8300;

 $patterns = array(/Intel Core 2 Duo/,/Intel Core 2/);

 $replacements = array(/Intel Core 2 Duo Processor Technology/,/Intel Core
 2 Processor Technology/);

 I would expect to get the following:

 The new Intel Core 2 Duo Processor Technology T8300

 but i get 

 The new Intel Core 2 Processor Technology Duo Processor Technology T8300

 I can see why its doing it, reading the string in and making the replacement
 but then reading the string in for the next pattern, but i don't want it to
 do this. How do i stop preg_replace from reading in the same part of the
 string that has been replaced already?

 (it's a bad day! :( )
   

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Re: [PHP] Re: Passing variable to a page in a frameset

On Aug 15, 2008, at 2:05 PM, Stut wrote:

On 15 Aug 2008, at 19:50, Jody Cleveland wrote:

On Aug 15, 2008, at 1:46 PM, Stut wrote:

On 15 Aug 2008, at 19:39, Jody Cleveland wrote:

On Aug 15, 2008, at 1:22 PM, Warren Vail wrote:

Actually you may want to check back with basic html at the
target

parameter on your search form statement.

HTH,

Warren Vail
Vail Systems Technology
[EMAIL PROTECTED]

Target won't work for me because the originating page with the
search box is not part of any frameset. I'm trying to get the
search results from that page to go to a page that is part of a
frameset.

Are you saying that the frame you want to have the search results
shown in doesn't exist when the search form is submitted? If it
does then it doesn't matter where the form is, just specify the
target as the name of the frame and it will almost certainly work.

If however you want the search to create the frameset when it runs
then you have a completely different problem which is best solved
using some sort of session. The script that handles the POST will
need to store the details of the search somewhere and output the
frameset. The frame that needs to contain the results would then
grab the details and run the search outputting the results.

That is exactly what I want. I apologize for the confusion. I was
having a hard time trying to put what I was trying to do in words.
But, yes, your second paragraph is exactly what I want to do. My
knowledge of PHP is very limited, and I've tried to search for
something that will do this, but couldn't find anything.

Ok, then I have to ask the question... why frames?

If you really need frames then you need to come up with a way to
pass the search from the script the search form loads to the
specific frame in the frameset it outputs. You could do this through
a GET parameter, or via a session or in several other ways. In any
case you'd be far better off not using frames if possible, so why
frames?

I work for a consortium of 30 libraries. Each library has their own
website, but they all share the same web catalog. On each library's
website there is a search box to search the catalog, which is on a
completely different server from the websites. We've been finding that
once people use that search box, they get distracted with the catalog
and have no easy way to get back to the library's website. The problem
I was tasked with is, coming up with a way to search the catalog with
an easy way to return to where the user was before they initiated the
search.

The only way I thought to do this was to use a frameset for the search
results. Which, you can see here:

http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html

If anyone has any ideas, other than using frames for the results, I'd
love to hear them. The problem is, there's nothing I can do on the web
catalog end.

- jody

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Re: [PHP] Re: Passing variable to a page in a frameset

On 15 Aug 2008, at 20:21, Jody Cleveland wrote:

I work for a consortium of 30 libraries. Each library has their own
website, but they all share the same web catalog. On each library's
website there is a search box to search the catalog, which is on a
completely different server from the websites. We've been finding
that once people use that search box, they get distracted with the
catalog and have no easy way to get back to the library's website.
The problem I was tasked with is, coming up with a way to search the
catalog with an easy way to return to where the user was before they
initiated the search.

The only way I thought to do this was to use a frameset for the
search results. Which, you can see here:

http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html

Is POST the only way to get the search results, or will it work with a
GET?

If GET will work then you need to set the search form to post to a
script on your site which then outputs a frameset with a URL on your
server that shows the header, and the URL for the shared search server
with all the POSTed variables as GET parameters as the second frame.
Job done.

If not then you're going to need to play silly wotsits with a hidden
form in the top frame which reposts the search to the bottom form. Not
pretty and would require JS but it should work.

-Stut

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Re: [PHP] Re: Passing variable to a page in a frameset

On Aug 15, 2008, at 2:27 PM, Stut wrote:

On 15 Aug 2008, at 20:21, Jody Cleveland wrote:

I work for a consortium of 30 libraries. Each library has their own
website, but they all share the same web catalog. On each library's
website there is a search box to search the catalog, which is on a
completely different server from the websites. We've been finding
that once people use that search box, they get distracted with the
catalog and have no easy way to get back to the library's website.
The problem I was tasked with is, coming up with a way to search
the catalog with an easy way to return to where the user was before
they initiated the search.

The only way I thought to do this was to use a frameset for the
search results. Which, you can see here:

http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html

Is POST the only way to get the search results, or will it work with
a GET?

If GET will work then you need to set the search form to post to a
script on your site which then outputs a frameset with a URL on your
server that shows the header, and the URL for the shared search
server with all the POSTed variables as GET parameters as the second
frame. Job done.

GET should work too. Do you know of any examples anywhere online for
this? My brain shuts off at the thought of how I'd do that.

- jody

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Re: [PHP] Re: Passing variable to a page in a frameset


 I work for a consortium of 30 libraries. Each library has their own
 website, but they all share the same web catalog. On each library's website
 there is a search box to search the catalog, which is on a completely
 different server from the websites. We've been finding that once people use
 that search box, they get distracted with the catalog and have no easy way
 to get back to the library's website. The problem I was tasked with is,
 coming up with a way to search the catalog with an easy way to return to
 where the user was before they initiated the search.

 The only way I thought to do this was to use a frameset for the search
 results. Which, you can see here:

 http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html

 If anyone has any ideas, other than using frames for the results, I'd love
 to hear them. The problem is, there's nothing I can do on the web catalog
 end.

 - jody



Easiest solution - Open the search page in a new window. Then they can just
close it to get back to the previous window...

I now understand what you're trying to say in regards to the frames.

The top frame resides completely on your server so you can place a Go back
to homepage link to direct people back to YOUR libraries homepage. And the
bottom frame contains the search results page that you have no control over
and cannot alter to simply place a Home link on it. And that should remain
since the global search results page is accessed by multiple libraries.

Like I said above, the easiest thing to do is just open it in a seperate
window so they can close it at any time and still be at the same place on
your libraries website.

Re: [PHP] Re: Passing variable to a page in a frameset

On 15 Aug 2008, at 20:34, Jody Cleveland wrote:

On Aug 15, 2008, at 2:27 PM, Stut wrote:

On 15 Aug 2008, at 20:21, Jody Cleveland wrote:

I work for a consortium of 30 libraries. Each library has their
own website, but they all share the same web catalog. On each
library's website there is a search box to search the catalog,
which is on a completely different server from the websites. We've
been finding that once people use that search box, they get
distracted with the catalog and have no easy way to get back to
the library's website. The problem I was tasked with is, coming up
with a way to search the catalog with an easy way to return to
where the user was before they initiated the search.

The only way I thought to do this was to use a frameset for the
search results. Which, you can see here:

http://beta.menashalibrary.org/sites/beta.menashalibrary.org/themes/salamander/searchframe.html

Is POST the only way to get the search results, or will it work
with a GET?

If GET will work then you need to set the search form to post to a
script on your site which then outputs a frameset with a URL on
your server that shows the header, and the URL for the shared
search server with all the POSTed variables as GET parameters as
the second frame. Job done.

GET should work too. Do you know of any examples anywhere online for
this? My brain shuts off at the thought of how I'd do that.

Off the top of my head and very untested...

?php
$vars = array();
foreach ($_POST as $k = $v)
{
$vars[] = urlencode($k).'='.urlencode($v);
}
$searchurl = 'http://search.server.com/search.php?'.implode('',
$vars);

?
frameset
frame src=/header.html /
frame src=?php echo $searchurl; ? /
/frameset

Modify to your own frameset/url requirements but that's the basic idea.

-Stut

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Re: [PHP] Re: Passing variable to a page in a frameset


 GET should work too. Do you know of any examples anywhere online for this?
 My brain shuts off at the thought of how I'd do that.

 - jody


When you GET a value you are retrieving a passed value that appears in the
address bar:
Example

http://www.mysite.com?name=joe

www.mysite.com is the website

?name=joe is the value being passed by GET

To put this value into a PHP variable you would simply do:
?php
$name = $_GET['name'];
? http://www.google.com/search?hl=enq=encrypt+javascript

Re: [PHP] Re: Passing variable to a page in a frameset

On 8/15/08, Dan Shirah [EMAIL PROTECTED] wrote:

  GET should work too. Do you know of any examples anywhere online for
 this? My brain shuts off at the thought of how I'd do that.

 - jody


 When you GET a value you are retrieving a passed value that appears in the
 address bar:
 Example

 http://www.mysite.com?name=joe http://www.mysite.com/?name=joe

 www.mysite.com is the website

 ?name=joe is the value being passed by GET

 To put this value into a PHP variable you would simply do:
 ?php
 $name = $_GET['name'];
 ?


Although, since you have no control over the actual search page to edit the
code and have it pull in the $_GET[''] values you will probably have to
disect the search page to get its form elements so you can feed them to it
and force a submit.

I just looked at your site, and after I input my search criteria and click
submit I have to again enter in the search criteria and submit to actually
get some results.

RE: [PHP] How to submit form via PHP

2008-08-15 Thread pe . ve . ce

Thanks, that was what I needed. Also I found this: 
http://curl.haxx.se/libcurl/php/examples/./simplepost.html. Is it somehow 
possible to retrieve result of that operation?

Thanks in advance.

Matěj czech_d3v3l0pr Grabovský


  Původní zpráva 
 Od: Warren Vail [EMAIL PROTECTED]
 Předmět: RE: [PHP] How to submit form via PHP
 Datum: 15.8.2008 21:04:12
 
 Key to this one may be understanding what is being asked.  I think pe.ve.ce
 performed a file read (file_get_contents) on the form from another website
 and wants to be able to simulate a browser submit from his code.

 If this is correct, I would recommend you take a look at CURL.  There are
 probably several approaches that work, but as I understand that CURL is an
 implementation of the C libraries used by early browsers.  If that is not
 correct, someone here will set us straight.  Many ISP's won't support CURL,
 because it is often used for questionable activities and considered a
 security exposure, but I believe CURL is what you want.

 Hth,

 Warren Vail

  -Original Message-
  From: Jay Blanchard [mailto:[EMAIL PROTECTED]
  Sent: Friday, August 15, 2008 11:31 AM
  To: [EMAIL PROTECTED]; php-general@lists.php.net
  Subject: RE: [PHP] How to submit form via PHP
 
  [snip]
  Hello. I'm pretty noob in PHP and would like to know how can
  I submit some HTML form got via file_get_contents(URL). For example:
 
  form name=someform method=post
  input type=submit
  /form
 
  so how can I submit 'someform' form.
 
  Thanks in advance for any suggestions.
  [/snip]
 
  Click 'Submit'
 
 
 
  Your form tag needs an action statement
 
  form name=someform action=some.php method=POST
 
  All of the form's variables will be available in the $_POST array
 
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  unsubscribe, visit: http://www.php.net/unsub.php
 





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Re: [PHP] Re: Passing variable to a page in a frameset

There you go!

Entering in the search criteria pulls up the search in a new window and
automatically pulls results based on your search.  Then I can just close the
window to return to where I was on your site.

I think that is simple and easy to use.  And I'm sure not much of a headache
for you!

Re: [PHP] Re: Passing variable to a page in a frameset



On Aug 15, 2008, at 2:58 PM, Dan Shirah wrote:



There you go!

Entering in the search criteria pulls up the search in a new window  
and automatically pulls results based on your search.  Then I can  
just close the window to return to where I was on your site.


I think that is simple and easy to use.  And I'm sure not much of a  
headache for you!


It wasn't exactly what I had wanted, but it works and was very easy.

Thanks again for taking the time to help me.

- jody


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RE: [PHP] How to submit form via PHP

 -Original Message-
 From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
 Sent: Friday, August 15, 2008 2:54 PM
 To: php-general@lists.php.net
 Subject: RE: [PHP] How to submit form via PHP

 Thanks, that was what I needed. Also I found this:
 http://curl.haxx.se/libcurl/php/examples/./simplepost.html. Is it
 somehow possible to retrieve result of that operation?

 Thanks in advance.

 Matěj czech_d3v3l0pr Grabovský

I believe:

curl_setopt(CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);

...will send the output from cURL to the variable rather than the web 
browser/screen.

Todd Boyd
Web Programmer

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[PHP] Open Source Classifides

2008-08-15 Thread Joey

Hello All,

 

Does anyone know of a good php based classified system?

 

Thanks!

Re: [PHP] PHP Script/Thread ID thingie

2008-08-15 Thread Richard Lynch

On Fri, August 15, 2008 10:52 am, Stut wrote:
 On 15 Aug 2008, at 16:37, [EMAIL PROTECTED] wrote:
 I'm logging things with error_log, and would like to be able to sort
 out one script run from another.

 So I'm looking for some kind of script id or thread id or PHP
 script run execution ID type of function.

 getmypid() just returns the same apache child process ID all the
 time, so that's not what I want.

 zend_thread_id() looks useful, but I suspect it's not quite what I'm
 looking for.  But I'd have to re-compile with ZTS and --debug-mode
 and I don't think the function I'm looking for should require
 that...

 Perhaps I've just missed the right function name?

 Or perhaps this should be a Feature Request?

 Don't think there is such a thing, but you could generate one by
 combining the pid, timestamp and the script filename, maybe into an
 md5 hash value or similar. Thinking about it, ip.pid would be
 enough, i.e. 127.0.0.1.12345.

The IP and pid will not actually change...

It's just me surfing to my own app (or one I inherited) on my own
desktop.

Apache isn't getting nearly exercised enough to need a second child,
so the pid is the same all the time...

Guess I'll have to create one as Eric Butera suggested...

Seems kind of odd that there isn't some kind of
script/thread/M_INIT/R_INIT id hanging around and exposed that
developers could use.
[shrug]

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I just want you to buy an Indie CD for yourself:
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Re: [PHP] PHP Script/Thread ID thingie


On 15 Aug 2008, at 23:30, Richard Lynch wrote:

On Fri, August 15, 2008 10:52 am, Stut wrote:

On 15 Aug 2008, at 16:37, [EMAIL PROTECTED] wrote:

I'm logging things with error_log, and would like to be able to sort
out one script run from another.

So I'm looking for some kind of script id or thread id or PHP
script run execution ID type of function.

getmypid() just returns the same apache child process ID all the
time, so that's not what I want.

zend_thread_id() looks useful, but I suspect it's not quite what I'm
looking for.  But I'd have to re-compile with ZTS and --debug-mode
and I don't think the function I'm looking for should require
that...

Perhaps I've just missed the right function name?

Or perhaps this should be a Feature Request?


Don't think there is such a thing, but you could generate one by
combining the pid, timestamp and the script filename, maybe into an
md5 hash value or similar. Thinking about it, ip.pid would be
enough, i.e. 127.0.0.1.12345.


The IP and pid will not actually change...

It's just me surfing to my own app (or one I inherited) on my own
desktop.

Apache isn't getting nearly exercised enough to need a second child,
so the pid is the same all the time...

Guess I'll have to create one as Eric Butera suggested...

Seems kind of odd that there isn't some kind of
script/thread/M_INIT/R_INIT id hanging around and exposed that
developers could use.
[shrug]


I don't find that odd since there's on external context to such an ID  
other than that which you create within the script so you can just use  
something randomly unique.


-Stut

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Re: [PHP] Sessions - Failed to initialize storage...

2008-08-15 Thread Bojan Tesanovic


Hm , this issue has been reported
http://bugs.php.net/bug.php?id=25876 and http://bugs.php.net/bug.php? 
id=32330


and it occurs sporadically for some users
though most of them said that setting
ini_set(session.save_handler, files);  solved the problem and / 
tmp dir must be writable by server


so 2 steps
1. make sure that on prod server .htaccess is actually read , as you  
set php_value session.save_handler files in it

2. /tmp is writable





On Aug 15, 2008, at 8:20 PM, Chris Ditty wrote:

Fatal error: session_start(): Failed to initialize storage module.  
in /home/webroot/www/service/payarrange/index.php on line 4


Line 4 is the session_start();


Bojan Tesanovic [EMAIL PROTECTED] 8/15/2008 1:10 PM 
Can you give us the exact error that you got, that can help to  
debug ...



On Aug 15, 2008, at 7:53 PM, Chris Ditty wrote:


Can someone tell me what I am missing here?  This is working fine
on my development machine(5.2.6), but on the production box(4.3.2),
it doesn't want to work.  I am getting that error on my
session_start() function.

Is the difference in versions what is causing the problems?

I've googled and none of the results fit my problem.  Below is
my .htaccess file.
php_value session.save_handler files
php_value session.save_path /tmp
php_value session.name PHPSESSID
php_flag session.auto_start off
php_value session.cookie_path /
php_flag session.use_cookies on
php_value session.cache_expire 180
php_flag session.use_trans_sid on



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Enroll today!


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Memphis Light, Gas  Water Division, and no such inference should  
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[PHP] Re: Conditional compilation

2008-08-15 Thread Shawn McKenzie


Herman Gomez wrote:

Hi,

Here is something I used to do in C/C++ to include/exclude automaticaly 
all debugging code at compiling time:


#define debug TRUE
#ifdef(debug)
//debugging code
#endif

That way I can include/exclude easily all debugging code in the final 
compiled code. In PHP I have not been able to find anything like that.
The only solution I've found is having this kind of code in every debug 
code block:


if ($debug) {
//debugging code
}

But this means that the debugging code is in the final compiled 
(interpreted) code, wasting cpu cycles even if there won't be any 
debugging in production.


Does somebody know if there is something like conditional compilation in 
PHP that I can use?


Regards,
Herman Gomez
Madrid, Spain.


Well PHP isn't compiled it's interpreted.  Still I don't see much diff 
and no overhead between the following:


#ifdef(debug)
//debugging code
#endif

---and---

if (defined('DEBUG')) {
//debugging code
}

I don't think checking a define is cpu intensive or even measurable. 
You could assume that it's defined as true or false and:


if (DEBUG === true)) {
//debugging code
}

Still, I don't think that even checking $debug is measurable.

-Shawn

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RE: [PHP] SESSION problem

2008-08-15 Thread tedd


At 1:47 PM -0500 8/15/08, Boyd, Todd M. wrote:

Have you tried:

echo SID;

...? I'm wondering if you're going to get different values on the two
pages. What that means beyond two different sessions is beyond me, but
it's a start.


Todd Boyd
Web Programmer


Todd:

I added code to show the SID and it's the same, but still nothing happens.

http://www.webbytedd.com/b2/session-test/index.php

I know what the problem is, but don't know how to fix it.

If you will look at the code, I am using a variable within the 
SESSION declaration:


$_SESSION[$i] = $i;

If I comment that out, the $_SESSION['test'] will be passed.

Thanks,

tedd

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Re: [PHP] Re: Conditional compilation

On Fri, 2008-08-15 at 18:34 -0500, Shawn McKenzie wrote:
 Herman Gomez wrote:
  Hi,
  
  Here is something I used to do in C/C++ to include/exclude automaticaly 
  all debugging code at compiling time:
  
  #define debug TRUE
  #ifdef(debug)
  //debugging code
  #endif
  
  That way I can include/exclude easily all debugging code in the final 
  compiled code. In PHP I have not been able to find anything like that.
  The only solution I've found is having this kind of code in every debug 
  code block:
  
  if ($debug) {
  //debugging code
  }
  
  But this means that the debugging code is in the final compiled 
  (interpreted) code, wasting cpu cycles even if there won't be any 
  debugging in production.
  
  Does somebody know if there is something like conditional compilation in 
  PHP that I can use?
  
  Regards,
  Herman Gomez
  Madrid, Spain.
 
 Well PHP isn't compiled it's interpreted.  Still I don't see much diff 
 and no overhead between the following:
 
 #ifdef(debug)
   //debugging code
 #endif
 
 ---and---
 
 if (defined('DEBUG')) {
   //debugging code
 }
 
 I don't think checking a define is cpu intensive or even measurable. 
 You could assume that it's defined as true or false and:
 
 if (DEBUG === true)) {
   //debugging code
 }
 
 Still, I don't think that even checking $debug is measurable.

That depends on where the conditional exists. In C you can place it
anywhere, including wihtin a tight loop. In PHP you end up having to
either take an overhead penalty or duplicate code to force the
conditional outside of a tight loop.

Contrast the following:

?php

if( DEBUG === true )
{
for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.
// Do something dependent on debug mode.
}
}
else
{
for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.
}
}

?

Versus:

?php

for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.

if( DEBUG === true )
{
// Do something dependent on debug mode.
}
}

?

Now depending on what Do something common between DEBUG and !DEBUG
modes does, it can be a real PITA to do code duplication to optimize
debug mode handling, but on the other hand, you really don't want to
check if DEBUG is enabled 1 million times.

If I recall though... a few years ago the answer to this question was
that there's no reason why you can't use the C pre-processor to
accomplish the same thing with PHP. The down side though is that then
you lose debugging information such as the real line number on which an
error occurs.

Cheers,
Rob.
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Application and Templating Framework for PHP


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Re: [PHP] SESSION problem

2008-08-15 Thread VamVan

Tedd,

I think according to PHP manual. Session_start() must be the first line in
the code. Dont worry it will remember your session until you close the
browser and also it wont duplicate it.

Thanks

On Fri, Aug 15, 2008 at 4:39 PM, tedd [EMAIL PROTECTED] wrote:

 At 1:47 PM -0500 8/15/08, Boyd, Todd M. wrote:

 Have you tried:

echo SID;

 ...? I'm wondering if you're going to get different values on the two
 pages. What that means beyond two different sessions is beyond me, but
 it's a start.


 Todd Boyd
 Web Programmer


 Todd:

 I added code to show the SID and it's the same, but still nothing happens.

 http://www.webbytedd.com/b2/session-test/index.php

 I know what the problem is, but don't know how to fix it.

 If you will look at the code, I am using a variable within the SESSION
 declaration:

 $_SESSION[$i] = $i;

 If I comment that out, the $_SESSION['test'] will be passed.

 Thanks,

 tedd

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Re: [PHP] Re: Conditional compilation

2008-08-15 Thread Shawn McKenzie


Robert Cummings wrote:

On Fri, 2008-08-15 at 18:34 -0500, Shawn McKenzie wrote:

Herman Gomez wrote:

Hi,

Here is something I used to do in C/C++ to include/exclude automaticaly 
all debugging code at compiling time:


#define debug TRUE
#ifdef(debug)
//debugging code
#endif

That way I can include/exclude easily all debugging code in the final 
compiled code. In PHP I have not been able to find anything like that.
The only solution I've found is having this kind of code in every debug 
code block:


if ($debug) {
//debugging code
}

But this means that the debugging code is in the final compiled 
(interpreted) code, wasting cpu cycles even if there won't be any 
debugging in production.


Does somebody know if there is something like conditional compilation in 
PHP that I can use?


Regards,
Herman Gomez
Madrid, Spain.
Well PHP isn't compiled it's interpreted.  Still I don't see much diff 
and no overhead between the following:


#ifdef(debug)
//debugging code
#endif

---and---

if (defined('DEBUG')) {
//debugging code
}

I don't think checking a define is cpu intensive or even measurable. 
You could assume that it's defined as true or false and:


if (DEBUG === true)) {
//debugging code
}

Still, I don't think that even checking $debug is measurable.


That depends on where the conditional exists. In C you can place it
anywhere, including wihtin a tight loop. In PHP you end up having to
either take an overhead penalty or duplicate code to force the
conditional outside of a tight loop.

Contrast the following:

?php

if( DEBUG === true )
{
for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.
// Do something dependent on debug mode.
}
}
else
{
for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.
}
}

?

Versus:

?php

for( $i = 0; $i  100; $i++ )
{
// Do something common between DEBUG and !DEBUG modes.

if( DEBUG === true )
{
// Do something dependent on debug mode.
}
}

?

Now depending on what Do something common between DEBUG and !DEBUG
modes does, it can be a real PITA to do code duplication to optimize
debug mode handling, but on the other hand, you really don't want to
check if DEBUG is enabled 1 million times.

If I recall though... a few years ago the answer to this question was
that there's no reason why you can't use the C pre-processor to
accomplish the same thing with PHP. The down side though is that then
you lose debugging information such as the real line number on which an
error occurs.

Cheers,
Rob.


Great!  Then the answer is:   wait,   wait,

write it in C!

-Shawn

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Re: [PHP] Re: Conditional compilation