php-general Digest 17 Sep 2013 19:38:29 -0000 Issue 8365
php-general Digest 17 Sep 2013 19:38:29 - Issue 8365 Topics (messages 322075 through 322075): Resolving a PHP Notice Error 322075 by: Ron Piggott Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- I am wanting to establish a default sort by preference when the user hasn’t specified one. I setup to test this with: ?php if ( !is_set( $sort_by_preference ) ) { $sort_by_preference = government_wording; } ? But I am receiving a Notice error: Notice: Undefined variable: sort_by_preference in GIFI_codes.php on line 11- Line 11 is “if ( !is_set( $sort_by_preference ) ) {“What is the correct way to test this without triggering a Notice error?Ron Ron Piggott www.TheVerseOfTheDay.info ---End Message---
Re: [PHP] Resolving a PHP Notice Error
On Tue, Sep 17, 2013 at 3:38 PM, Ron Piggott ron.pigg...@actsministries.org wrote: I am wanting to establish a default sort by preference when the user hasn’t specified one. I setup to test this with: ?php if ( !is_set( $sort_by_preference ) ) { Did you create a function is_set(), or did you mean to use the construct isset()? -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Resolving a PHP Notice Error
I am wanting to establish a default sort by preference when the user hasn’t specified one. I setup to test this with: ?php if ( !is_set( $sort_by_preference ) ) { $sort_by_preference = government_wording; } ? But I am receiving a Notice error: Notice: Undefined variable: sort_by_preference in GIFI_codes.php on line 11- Line 11 is “if ( !is_set( $sort_by_preference ) ) {“What is the correct way to test this without triggering a Notice error?Ron Ron Piggott www.TheVerseOfTheDay.info
Re: [PHP] Resolving a PHP Notice Error
2013/9/17 Ron Piggott ron.pigg...@actsministries.org I am wanting to establish a default sort by preference when the user hasn’t specified one. I setup to test this with: ?php if ( !is_set( $sort_by_preference ) ) { $sort_by_preference = government_wording; } ? But I am receiving a Notice error: Notice: Undefined variable: sort_by_preference in GIFI_codes.php on line 11- Line 11 is “if ( !is_set( $sort_by_preference ) ) {“What is the correct way to test this without triggering a Notice error?Ron Ron Piggott Because actually you are looking for isset() (not is_set()). www.TheVerseOfTheDay.info -- github.com/KingCrunch
[PHP] assign database result to iinput text box
I have following html code to show my input text box and php to connect server and select result from database server. I would like to know how I can I use php to assign the value to my input text. Your help and information is great appreciated, Regards, Iccsi, INPUT type=text name=Mytxt id=MytextID / ?php $username = root; $password = myPassword; $hostname = localhost; //connection to the database $dbhandle = mysql_connect($hostname, $username, $password) or die(Unable to connect to MySQL); echo Connected to MySQLbr; //select a database to work with $selected = mysql_select_db(iccsimd,$dbhandle) or die(Could not select aerver); //execute the SQL query and return records $result = mysql_query(SELECT invid, invdate, note, amount FROM invheader); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php