Re: [PHP] Exact string replacement...

[Desikan]

hi there,
Have u tried this...
  ?php
$string = 'foo';
print preg_replace(/^\s$string\s/,' ','bfoo foo foobar.') . \n;
print eregi_replace(^[[:space:]].$string.[[:space:]],' ','bfoo
foo alfoobar.') . \n;
  ?
This is not working properly..

Output I got is

bfoo foo foobar. bfoo foo alfoobar

help me out

Rgds,
Desikan


On Sat, 9 Feb 2002 03:01:40 -0500, Brian Clark [EMAIL PROTECTED]
said:
 * Desikan ([EMAIL PROTECTED]) [Feb 09. 2002 02:52]:
 
  hi Thanks,
 
 Sure, 
 
But I want to do thr replace operation for 
regular exprerssion and not exactly for the string alone...
like ^and$,a*, etc
 
 ?php
 
 $string = 'foo';
 print preg_replace(/^\s$string\s/,' ',' foo foobar.') . \n;
 print eregi_replace(^[[:space:]].$string.[[:space:]],' ',' foo
 foobar.') . \n;
 
 ?
 
 I like the top better..
 
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[PHP] Exact string replacement...

[Desikan]

Hi there,

Please help me out in the following...

?php
$is='is';
echo eregi_replace( .$is. , ,This is a test string which contains
is in dismissal);
?


Actually I want to replace is alone from the string and not all the
words that contains is...

I have tried with ^.$is.$ --- but yields nothing

Also tried with \b...


thanks and regards,
Desikan

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