Re: [PHP] Differences between PHP on LAMP and PHP on Windows Servers
From: Matijn Woudt tijn...@gmail.commailto:tijn...@gmail.com Date: Wednesday, May 23, 2012 3:59 PM To: a...@ashleysheridan.co.ukmailto:a...@ashleysheridan.co.uk a...@ashleysheridan.co.ukmailto:a...@ashleysheridan.co.uk Cc: Jeff Gates gat...@si.edumailto:gat...@si.edu, php-general@lists.php.netmailto:php-general@lists.php.net php-general@lists.php.netmailto:php-general@lists.php.net Subject: Re: [PHP] Differences between PHP on LAMP and PHP on Windows Servers On Wed, May 23, 2012 at 9:35 PM, Ashley Sheridan a...@ashleysheridan.co.ukmailto:a...@ashleysheridan.co.uk wrote: On Wed, 2012-05-23 at 20:54 +0200, Matijn Woudt wrote: On Tue, May 22, 2012 at 8:15 PM, Gates, Jeff gat...@si.edumailto:gat...@si.edu wrote: Can anyone tell me what differences I might encounter by working with PHP on a Unix server verses working with PHP on a Windows server. We use Windows production servers here but many of us would like to get more LAMP environments. So, I'm wondering if I can use the hive mind here to get a sense of the pros and cons of each platform. Thanks. Jeff Apart from all other suggestions, one of the most common errors are because of different php.ini settings. If you can keep those settings (mostly) equal, there will not be that many errors. - Matijn I would say that's not limited to the distinction between Windows and Linux but any server. I've seen what appears to be an identical setup (same version of PHP, MySQL, etc) fail only because of a small setting in the php.ini file, just because the default was slightly different on the second system; both were running Linux. Yes, ofcourse, that comment was meant for any two systems. - Matijn Well, let me also add a related question: what types of problems might I encounter if I was trying to set up a Drupal or Wordpress instance on a Windows server running PHP as opposed to a Unix server? Jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Differences between PHP on LAMP and PHP on Windows Servers
Can anyone tell me what differences I might encounter by working with PHP on a Unix server verses working with PHP on a Windows server. We use Windows production servers here but many of us would like to get more LAMP environments. So, I'm wondering if I can use the hive mind here to get a sense of the pros and cons of each platform. Thanks. Jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Google Search Appliance and PHP
I am a newbie in PHP. I need to create a search using Google's Search Appliance for a site I'm designing but don't have the slightest idea on how to do it. Because I want to incorporate the site's design into the search results page I can't use the GSA's simple page layout wizard. Here's what I need to be able to learn how to do: 1. Create a search form and send it to our GSA (this is pretty easy). 2. Create a processing page to parse the XML 3. Create a results page using the header and footer of my site. Can anyone help me with simple explanation on how to do steps 2 and 3? Thanks, Jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Syntax Question
I, too, am a super newbie. I have a beginning knowledge of being able to
read php and understand its syntax but I can¹t write it. This is a bit
complicated but here¹s my problem:
I want to create a variable in PHP that I can use to link to an image in our
museum's image website. We have done it with ColdFusion here but I need the
same thing for PHP because I¹m building a site using a php-based CMS called
Omeka.
In ColdFusion the variable is written:
cfset tmpImageDirectory = getToken(artwork.accessionNumber, 1, .)
Basically, it¹s saying find the image on our server by looking for its
accession number within the year directory. Since the first part of the
accession number is the year we got the artwork this variable is saying look
for the accession number in the year directory by first looking at the first
part of that accession number (the year), look in that year directory and
then use the entire accession number to find the image within that
directory. An example of an accession number is 2011.15. That¹s saying that
artwork was the 15th artwork brought into our collection in 2011. On our
image server it will be found in a directory called 2011. (Am I making
sense?)
Then the Coldfusion call is:
a
href=http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart
.si.edu/images/#tmpImageDirectory#/#artwork.accessionNumber#_1a.jpg (the
1a.jpg is simply the size image we want to call).
I need to be able to do the same thing with PHP but have no idea how.
More information: within my site I¹m housing the accession number in a mySQL
database. I¹ve gotten a bit of help on this already (but not enough, that¹s
why I¹m turning to you).
I was told I need to create two variables [('Dublin Core','Identifier') is
the name of the field that houses the accession number):
$accessionNumber = item('Dublin Core','Identifier');
$tmpImageDirectory = strtok($accessionNumber,.);
And then create a third variable to create a url variable
$url =
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.si.e
du/images/
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.si.e
du/images/$tmpImageDirectory/$artwork.accessionNumber_1a.jpg +
$tmpImageDirectory + / + $accessionNumber + _1ajpg;
That's as far as I've gotten. I don't know how to put all of these together
using proper PHP syntax. Can someone help me with this? Thanks.
Best, Jeff
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Re: [PHP] Syntax Question
On 8/3/11 10:41 AM, ad...@buskirkgraphics.com ad...@buskirkgraphics.com
wrote:
-Original Message-
From: Gates, Jeff [mailto:gat...@si.edu]
Sent: Wednesday, August 03, 2011 10:23 AM
To: php-general@lists.php.net
Subject: [PHP] Syntax Question
I, too, am a super newbie. I have a beginning knowledge of being able
to
read php and understand its syntax but I can¹t write it. This is a
bit
complicated but here¹s my problem:
I want to create a variable in PHP that I can use to link to an image
in our
museum's image website. We have done it with ColdFusion here but I need
the
same thing for PHP because I¹m building a site using a php-based CMS
called
Omeka.
In ColdFusion the variable is written:
cfset tmpImageDirectory = getToken(artwork.accessionNumber, 1, .)
Basically, it¹s saying find the image on our server by looking for its
accession number within the year directory. Since the first part of the
accession number is the year we got the artwork this variable is saying
look
for the accession number in the year directory by first looking at the
first
part of that accession number (the year), look in that year directory
and
then use the entire accession number to find the image within that
directory. An example of an accession number is 2011.15. That¹s saying
that
artwork was the 15th artwork brought into our collection in 2011. On
our
image server it will be found in a directory called 2011. (Am I making
sense?)
Then the Coldfusion call is:
a
href=http://ids.si.edu/ids/dynamic?container.fullpageid=http://americ
anart
.si.edu/images/#tmpImageDirectory#/#artwork.accessionNumber#_1a.jpg
(the
1a.jpg is simply the size image we want to call).
I need to be able to do the same thing with PHP but have no idea how.
More information: within my site I¹m housing the accession number in a
mySQL
database. I¹ve gotten a bit of help on this already (but not enough,
that¹s
why I¹m turning to you).
I was told I need to create two variables [('Dublin Core','Identifier')
is
the name of the field that houses the accession number):
$accessionNumber = item('Dublin Core','Identifier');
$tmpImageDirectory = strtok($accessionNumber,.);
And then create a third variable to create a url variable
$url =
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart
.si.e
du/images/
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart
.si.e
du/images/$tmpImageDirectory/$artwork.accessionNumber_1a.jpg +
$tmpImageDirectory + / + $accessionNumber + _1ajpg;
That's as far as I've gotten. I don't know how to put all of these
together
using proper PHP syntax. Can someone help me with this? Thanks.
Best, Jeff
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$url =
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.si.e
du/images/
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.si.e
du/images/. $tmpImageDirectory ./. $artwork .accessionNumber_1a.jpg .
$tmpImageDirectory ./. $accessionNumber ._1ajpg;
I am not sure I agree with the way you are setting the $url it looks like
you have mashed and a url hyperlink partially into 1.
Like you are trying to set the $url as a image with a link are you trying to
set a link or an image as the $url?
If you are trying to set a image as the $url do this.
$url = image
src=http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.s
i.edu/images/. $tmpImageDirectory ./. $accessionNumber ._1ajpg ALT='';
Sorry if this is not correct for what you are trying to do. I just do not
understand the intent.
To be honest with you, I'm not sure what that $url is supposed to do. This
is the info (albeit without any explanation) someone told me to use. But he
didn't tell me how to use it.
Basically, I need to be able to link to an image on our web server
dynamically. The structure of the web server is as I described: each image
has an accession number and each image is housed in a directory on that
server that is named the year that artwork was accessioned. We can retrieve
the accession number that is stored in the data field ('Dublin
Core','Identifier')
An example of an actual (non-dynamic) link to the image server might look
like this:
http://ids.si.edu/ids/dynamic?container.fullpageid=http://americanart.si.ed
u/images/2011/2011.15_1a.jpg
I just need to be able to build that link dynamically for each artwork on
the site. (Personally, I'm not wedded to the code I posted earlier if
someone can find a better way of doing it. This is just what I was told to
use. Again, I'm a newbie.)
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