Re: [PHP] Verry strange GET behaviour
On the topic of passing args, can someone please explain to me why I'm unable to use $_GET or $_POST if my php script is run as a .cgi? Basically, I have a simple html input form that has: form name=testform action=test.cgi method=GET input type=text name=textbox input type=submit value=Submit /form and a simple php script in a file called test.cgi which looks like: #!/usr/local/bin/php ?php print $_GET['testbox']; ? Now, if I rename this script to test.php, everything works fine, but not while run as a cgi. I have no such problems when implementing the exact same code using Perl, so I'm thinking that php requires a different method of obtaining args when run as a cgi. If anyone can tell me the method, I would greatly appreciate it. Thanks, John --- Chris Shiflett [EMAIL PROTECTED] wrote: --- Ben Edwards [EMAIL PROTECTED] wrote: Been having a problem accessing a variable that is passed on a URL. This question is asked several times a week. You have register_globals disabled, and if you are asking this question, you need to leave register_globals disabled. Use $_GET['_section'] to access your variable. Hope that helps. Chris = My Blog http://shiflett.org/ HTTP Developer's Handbook http://httphandbook.org/ RAMP Training Courses http://www.nyphp.org/ramp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php __ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Verry strange GET behaviour
--- Chris Shiflett [EMAIL PROTECTED] wrote:
--- John Wilcox [EMAIL PROTECTED] wrote:
On the topic of passing args, can someone please
explain to me why
I'm unable to use $_GET or $_POST if my php script
is run as a .cgi?
What you may want to do is to have the Web server
interpret .cgi files as PHP,
assuming all your CGIs are PHP scripts. Then you can
leave out your #! line at
the top also.
The reason why I'm having my php run as a .cgi in the
first place, is because I want the script to inherit
the user/group of the virtual host that it's running
under (using suEXEC), and this is not possible when
using a php script interpreted through the web server.
It must be run as a .cgi, since .cgi's will inherit
the user/group. This is no problem in Perl, since it
provides a way to pass variables from one .cgi to
another (using my $query = new CGI;
param('testbox');). But I can't figure out how to do
this in PHP, since using $_GET['testbox']; always
produces Undefined index: testbox in test.cgi on line
8.. Thanks,
John
P.S. If anyone has any other ideas of how to get a PHP
script to run as a specific user/group under a Virtual
Host, I'm all ears.. All I need is for the script to
be able to mkdir as a specific user/group, but this is
proving to be more than a small challenge!
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[PHP] Passing POST args to PHP when run as a CGI (was Re: [PHP] $_ENV not working for me with PHP 4.2.0)
--- Curt Zirzow [EMAIL PROTECTED] wrote:
Technically it is 4.1.0 (where did you see the
4.2.0?) but anything
prior to that you should use $HTTP_ENV_VARS
my mistake, you're right, it was 4.1.0.
http://php.net/manual/en/language.variables.predefined.php
http://php.net/manual/en/reserved.variables.php
A diff of your php.ini will tell the story I'll bet
a diff output
would be something like:
306c306
variables_order = GPCS
---
variables_order = EGPCS
yes, you're correct, my php.ini uses 'variable_order =
GPCS'. I tried changing this to EGPCS, but
$_ENV['USER']; would still not work.
To get the user that apache is really running as you
want to do
something like:
print `whoami`;
I've been playing around a bit more, and made a simple
script:
?php
echo getenv('USER'), br /;
print `whoami` . br /;
print $_ENV['USER'];
?
It produces the following output:
john
nobody
(and an error is produced in the logfile for
$_ENV['USER']: Undefined index: USER)
Now, I'm running this PHP script from within a virtual
host with a certain user/group (test/test - made
possible by using suEXEC), so I can't understand why
getenv('USER'); is returning john..
Anyway, I've been reading up on using suEXEC with PHP
scripts, and it looks like the scripts have to be run
as a .cgi in order to inherit the user/group of the
virtual host.. I've tried changing around one of my
PHP scripts so that it runs as a cgi (basically I just
renamed the file to test.cgi and added
#!/usr/local/bin/php to the beginning of the script).
The only problem is that now my $_POST['TEST'];
doesn't work within the script, so my new problem is
how to figure out passing variables from one script to
another when using PHP as a .cgi. Am I doing
something wrong, or does something need to be changed
in order for PHP to be able to receive these POST
variables?
If anyone has any ideas, please let me know. Thanks
in advance,
John
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[PHP] $_ENV not working for me with PHP 4.2.0
I've been trying to make a simple script which just outputs the username that the script is currently executing under (in order to test that suexec is working properly). I've tried using the following line: ?php print $_ENV['USER']; ? and it fails to produce any output and returns the following error in my log file: [Sun Oct 5 14:02:35 2003] [error] PHP Notice: Undefined index: USER in /home/test/test.php on line 1 Now, I've tried the same command on another server running PHP 4.2.0 and it correctly outputs the username as expected. Both these machines are running Debian Linux. Now I figure it must be some configuration setting that is messing this up somehow, but I have no idea where to look. I've checked out the documentation and it states that PHP versions later than 4.2.0 use the $_ENV global variable to access environment variables, so it seems like I'm using it correctly. Anyways, if anyone has any suggestions, please let me know! Thanks in advance, John Wilcox __ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] $_ENV not working for me with PHP 4.2.0
Hi Tom, when I put echo `printenv`; into a script, I
see in big bold letters: USER=john so this environment
variable seems to be available.. getenv('USER');
works fine, so I guess I'll just use that instead.. No
idea why $_ENV['USER']; doesn't work though. Thanks
for the suggestion,
John
--- Tom Rogers [EMAIL PROTECTED] wrote:
Hi,
Monday, October 6, 2003, 4:43:20 AM, you wrote:
JW I've been trying to make a simple script which
just
JW outputs the username that the script is
currently
JW executing under (in order to test that suexec is
JW working properly). I've tried using the
following
JW line:
JW ?php print $_ENV['USER']; ?
JW and it fails to produce any output and returns
the
JW following error in my log file: [Sun Oct 5
14:02:35
JW 2003] [error] PHP Notice: Undefined index:
USER in
JW /home/test/test.php on line 1
JW Now, I've tried the same command on another
server
JW running PHP 4.2.0 and it correctly outputs the
JW username as expected. Both these machines are
running
JW Debian Linux.
JW Now I figure it must be some configuration
setting
JW that is messing this up somehow, but I have no
idea
JW where to look. I've checked out the
documentation and
JW it states that PHP versions later than 4.2.0 use
the
JW $_ENV global variable to access environment
variables,
JW so it seems like I'm using it correctly.
Anyways, if
JW anyone has any suggestions, please let me know!
JW Thanks in advance,
JW John Wilcox
JW __
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JW The New Yahoo! Shopping - with improved product
search
JW http://shopping.yahoo.com
Do this to see what is available in your enviroment,
it would seem that USER is
not being set by the system or is called something
else.
echo `printenv`;
(use backticks)
--
regards,
Tom
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