Re: [PHP] [NEWBIE GUIDE] For the benefit of new members
[snip] I feel we should add this to the rules. Dunno about the others, but it really drives mad to delete bunches of emails with equal contents posted within 5 minute interval. --- Please avoid sending duplicate letters to the list. If you feel your email was not delivered properly or no-one noticed it, try sending again in a couple of days. Reposting frequently will not help solving your problems; in addition, members won't be much pleased if you flood 'em, so you decrease your chances to get helpful answers. If your mail server doesn't work properly, please pay attention to thousands of decent free ones. --- wbr Stan F -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Difficulty with SQL LIKE clause
- Original Message - From: David Freedman [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Friday, February 25, 2005 11:27 PM Subject: [PHP] Difficulty with SQL LIKE clause When I use this query in PHP it works, and I get all things with the YEAR of 1977, as I expected. $query= SELECT * FROM my_table WHERE Year LIKE 1977 ; But, when I use this query it does not work. $query= SELECT * FROM my_table WHERE Year LIKE 197* ; I thought I should get the result of ALL things with the years in the 1970's (1970-1979). But the asterisk in the LIKE clause does not seem to work. I have tried various syntax's to try to get the 197* recognized but without any luck. Can the '*' be used? What am I doing wrong. AFAIK you cannot. SQL wildcard symbols are % and _. David F. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] http referer
- Original Message - From: Sebastian [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Saturday, February 26, 2005 8:31 PM Subject: [PHP] http referer ok, so i made a file manager and i need to prevent people from linking directly to files that do not come from another part of the site. i know i can use http_referer, but i wonder how fool proof it is, i dont want to spit out errors to a legit user that actually came from a valid page before trying to access the file url. some people have said http_referer is not always accurate. Never rely on it. It might be not set at all, it's easy to spoof. I would think about sessions here. btw this topic has been discussed much, so you probably should STFA. any examples, snips, would be helpful. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Preventing execution without inclusion
- Original Message -
From: Adam Hubscher [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Friday, January 14, 2005 1:25 AM
Subject: [PHP] Preventing execution without inclusion
From within the application, I use one page to include
classes/variables and so on. Is there a way (I may have been missing it
in the documentation for PHP, however I didnt see anything related) to
prevent a user from directly accessing/executing *.php by the file
making sure taht it was only included by index.php?
For example:
config.php defines:
function __autoload($class_name) {
$class_name = strtolower($class_name);
include_once('class.'.$class_name.'.php');
}
as per PHP5 example
1 (the preferred way): user accesses
http://www.example.org/index.php?function=Join, this loads the class
NewUser and begins its implementation. Because of the __autoload, it
includes class.join.php, in order to utilize the class.
2 (the wrong way): user accesses
http://www.example.org/includes/class.join.php without going through
index.php.
I am trying to prevent 2 from even occuring, utilizing a piece of code
that would check if index.php had included it, or not. This code would
be in the beginning of all the class files, at the top, before any other
code was to be executed.
A common way to do it:
# in your index.php just before any inclusion
define( '__INDEX__', true );
# in other files
if( !defined( '__INDEX__' ) ) die( 'You cannot execute this script' );
Sorry if I didn't get u the right way, I'm too tired..
WBR
Stan F
As of yet, it has eluded me...
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Re: [PHP] Php error with MySql
- Original Message - From: Wil [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Thursday, January 06, 2005 9:35 PM Subject: [PHP] Php error with MySql I get the following error Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wilmail/public_html/elblog.php on line 7 n= //error ends here with the following bit of code $qResult = mysql_query (SELECT * FROM blog_entries ORDER BY id DESC); Try echo mysql_error() just after your query. It's rather common to make typos or forget to select DB. $nRows = mysql_num_rows($qResult); $rString =n=.$nRows; If I am just naming a variable how is the argument not valid? Thanks, Wil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] bargraph gd not working
- Original Message - From: jm [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, December 14, 2004 3:22 AM Subject: [PHP] bargraph gd not working Hi guys: I'm using php5 on winxp with IIS. I'm trying to run a simple bar graph demo found it on phpbuilder site. When I run it I get nothing but an x in the top left corner of my web page(no errors nothing). GD is uncommented in my php.ini, ext dir set and I have verified that GD is installed through php -m,phpinfo() , and gd_info(). Can anyone offer me some advice on how to troubleshoot this problem. I searched google, and did see other posts like mine but no solutions. Any thoughts or suggestions would be appreciated Do other php/gd scripts work as expected? (ie display images) Do you send the correct headers to browser? Please show us the code cuz without it it's not so easy to help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php HTH Stan F -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Nested If...Else...
Try this:
echo pre;
print_r( variable_you_wanna_track );
echo /pre;
The output will be easy-readable. Or try var_dump().
This helps maintaining scripts in more pleasant way.
- Original Message -
From: Robb Kerr [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, July 24, 2004 8:49 PM
Subject: Re: [PHP] Nested If...Else...
On Sat, 24 Jul 2004 09:47:52 -0700 (PDT), Matthew Sims wrote:
What's wrong with this syntax. I just can't see my mistake.
if ($vBkgrndImage == AnswerPage) {
if ($vAnswerID_RS_PageContent !=
$row_RS_PageContent['CorrectAnswer']) {
$vBkgrndImage = Bkgrnd-Body-Incorrect.jpg;
} else {
$vBkgrndImage = Bkgrnd-Body-Correct.jpg;
}
}
Thanx
--
Robb Kerr
I can't see anything wrong. What's the error you're receiving?
$vBkgrndImage = Bkgrnd-Body-Incorrect whether $vAnswerID_RS_PageContent
equals $row_RS_PageContent['CorrectAnswer'] or not. I've added printouts
of
my variables to the bottom of the page so that I can check their content.
And even when both associated variables match, Bkgrnd-Body-Incorrect is
returned.
--
Robb Kerr
Digital IGUANA
Helping Digital Artists Achieve their Dreams
http://www.digitaliguana.com
http://www.cancerreallysucks.org
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Re: [PHP] Re: If...Or...Else
Operations OR and || have different execution priorities. I'd prefer || as
it's more important so not so many parentheses needed to ensure the order
of interpretation is exactly what u need.
- Original Message -
From: Tularis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, July 24, 2004 6:57 PM
Subject: [PHP] Re: If...Or...Else
if(a OR b) {
do something
} else {
do something else
}
or
if(a || b) {
do something
} else {
do something else
}
is enough :)
Robb Kerr wrote:
From time to time I need an If statement that includes an Or
condition...
?php
if ((condition1 == TRUE) OR (condition2 == TRUE)) {
do something;
} esle {
do something else;
}
?
What's the correct syntax for the If line?
Thanx
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Re: [PHP] Very weird issue....
- Original Message -
From: Alex Shi [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, July 21, 2004 1:39 AM
Subject: [PHP] Very weird issue
Hi all,
Please take a look at following very simple script;
#!/usr/bin/php -q
?
echo Hello, world!\n;
if (!$tty) {
$tty = fopen('php://stdin', 'r');
}
print Hello: ;
$ch = fgets($tty, 1024);
print $ch\n;
?
I tested it on many servers. Here is how it running (you can
figure out yourself): Firstly it displays Hello, world!, then
displays Hello: at second line and waits for user input;
You input a yes and it displays the yes; then end. So, on
the screen you will see:
Hello, world!
Hello: yes
yes
However, on one of the servers, it doesn't run like above,
but in a reversed way: Firstly, it displays nothing but waits
for your input; you input a yes, then it displays the yes,
then Hello, world!, then Hello: yes. So, on the screen it
looks like this:
yes
Hello, world!
Hello: yes
Weird? To me IT IS! I really don't understand why all the
echos/prints did not function until the script got data from
tty, even they are before fgets..
I found this issue during an unsuccessfull pear installation.
The pear installer stopped and waited for my input without
any prompt - there is prompt message but not displayed!
Can anyone let me know how this can happen? Thanks
in advance!
Alex
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I remember this used to happen in c++ because of buffering; there you had to
tie STDIN and STDOUT in some cases: cin.tie ( cout );
Input and output having strict order in program could follow each other not
the way you expected.
So I see it's caused by stream handling and buffering.
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