First of all, Hi! I just started getting into php a week ago, but already ran into a problem I can't seem to solve. The issue is this : I code 2 different websites, each has it's own mySQL-DB. Website A has a login-section, each time you successfully log in, a key is generated which stays only valid for a certain period of time (done via database). Now, I have a link from the login section on website A to a sign-up-form on website B. This sign-up is supposed to only be accessible if you have a valid key from website A, which qualifies you as a member. Website B lets you fill out the form no matter what key you offer it, but when you have finished, right before I insert the data into my DB, I want it to check back with website A whether the key is valid or not.
That's where I'm stuck right now. I have a php file in website A's directory, which, when given a key value, will check whether it is valid or not. Is there any way I can treat this website like a function and have it give me a return value after it has "run through" ? I tried it by putting a header from B to validate.php on A, and have that only call the 'exit;' when a valid key is provided, but it seems to proceed with website B's code no matter what the header to website A does. Is there any other way or workaround that I can accomplish this ? I just need a link to that validation page, and after the link the code should proceed or not based on the "return value" from that link. By the way, I work with php3, so I hope there's a solution for that version ;) Thanks in advance for any help, I hope my english wasn't too bad for you to understand what I meant. -- NEU FÜR ALLE - GMX MediaCenter - für Fotos, Musik, Dateien... Fotoalbum, File Sharing, MMS, Multimedia-Gruß, GMX FotoService Jetzt kostenlos anmelden unter http://www.gmx.net +++ GMX - die erste Adresse für Mail, Message, More! +++ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
