Re: Re: [PHP] How do I convert from perl to php?

2001-11-20 Thread digital1 

So I would have to write a seperate if condition for each form input field i wanted to 
require? that doesn't make for a very dynamic script...

> if(!(isset($name) && isset($address) && isset($phone)) {
> echo "You left one empty.";
> }
> 
> On Tue, 20 Nov 2001 [EMAIL PROTECTED] wrote:
> 
> > I am a perl user trying to convert to php
> >
> > how would i turn this perl into php?
> >
> > use CGI;
> >
> > $name = param(name);
> > $address = param(address);
> > $phone = param(phone);
> >
> > @required = qw( name address phone );
> >
> > foreach $key($required)
> > {
> >  if (!$$key) { &out("You left one empty."); }
> > }
> >
> > ??
>


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[PHP] How do I convert from perl to php?

2001-11-20 Thread digital1 

I am a perl user trying to convert to php

how would i turn this perl into php?

use CGI;

$name = param(name);
$address = param(address);
$phone = param(phone);

@required = qw( name address phone );

foreach $key($required)
{
 if (!$$key) { &out("You left one empty."); }
}

??


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--- Begin Message ---

how would i turn this perl into php?

use CGI;

$name = param(name);
$address = param(address);
$phone = param(phone);

@required = qw( name address phone );

foreach $key($required)
{
 if (!$$key) { &out("You left one empty."); }
}

??

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http://www.olypen.com




--- End Message ---

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