[PHP] PHPTriad and php error

[hE]

hi to all,
I set up phptriad on my computer running windows xp. When I tried to 
test php with the following program I got an error Parse error: parse 
error, expecting `','' or `';'' in C:\apache\htdocs\mytest.php on line 10


html
head
titlePHP Test/title
/head
body
pThis is an HTML line
p
?php

echo “This is a PHP line”;
phpinfo();
?
/body/html

what is the reason?

p.s. phpinfo.php which comes with the installation executes correctly.

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Re: [PHP] PHPTriad and php error

[hE]

thanks for the help. I am a C/C++ programmer and decide to learn php and 
mysql to develop web pages. is it the correct place to ask questions 
similar to this? or is there any other group suitable for this?


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[PHP] mysql test and error

[hE]

hi,
I found an e-book in the net about php and mysql and with its sample 
program I am trying to test whether I have mysql working correctly or 
not. the following program gives error message. why?


html
headtitleTest MySQL/title/head
body
!-- mysql_up.php --
?php3
$host=”localhost”;
$user=”root”;
$password=””;
mysql_connect($host,$user,$password);
$sql=”show status”;
$result = mysql_query($sql);
if ($result == 0)
echo “bError “ . mysql_errno() . “: “
. mysql_error() . “/b”;
else
{
?
!-- Table that displays the results --
table border=”1”
trtdbVariable_name/b/tdtdbValue/b
/td/tr
?php3
for ($i = 0; $i  mysql_num_rows($result); $i++) {
echo “TR”;
$row_array = mysql_fetch_row($result);
for ($j = 0; $j  mysql_num_fields($result); $j++)
{
echo “TD” . $row_array[$j] . “/td”;
}
echo “/tr”;
}
?
/table
?php3 } ?
/body/html

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Re: [PHP] mysql test and error

[hE]

The following program gave the error:

 Parse error: parse error in C:\apache\htdocs\mysqltest.php on line 10


html
headtitleTest MySQL/title/head
body
!-- mysql_up.php --
?php
$host=”localhost”;
$user=”root”;
$password=””;
mysql_connect($host,$user,$password);
$sql=”show status”;
$result = mysql_query($sql);
if ($result == 0)
echo 'bError ' . mysql_errno() . ': '. mysql_error() . '/b';
else
{
?
!-- Table that displays the results --
table border=”1”
trtdbVariable_name/b/tdtdbValue/b
/td/tr
?php
for ($i = 0; $i  mysql_num_rows($result); $i++) {
echo 'TR';
$row_array = mysql_fetch_row($result);
for ($j = 0; $j  mysql_num_fields($result); $j++)
{
echo 'TD'. $row_array[$j] . '/td';
}
echo '/tr';
}
?
/table
/body/html

what is the reason?

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[PHP] Please Help......

[Man He]

Hi all,

   Can anybody give me a guideline or idea on how to write a PHP scriot 
which is used to create a domain or sub-domain and a default page and a same 
time. My OS is Red Hat Linux 6.1.

   For example, in my program, when i press activate' button, the script 
will create me a sub-domain try.php.com and a default page index.php is 
created for that sub-domain. Thanks for advice..
_
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