Re: [PHP] (another) regex difficulty
Am Donnerstag, 02.10.03 um 01:37 Uhr schrieb Cristian Lavaque: doh, I now understand your question, you don't mean the asterisk literally, but as any character that follows a backslash... sorry -_- that's right ;) -- anyway, thanks for your effort! my problem was that i misunderstood the escape-the-meta-char-idea (see below). Am Mittwoch, 01.10.03 um 23:23 Uhr schrieb Curt Zirzow: '\\' always gets translated to '\' So the string: '/(\\)/' translates to '/(\)/' which is an invalid regex, you'll get a complaint about unclosed paren. this is also a bit tricky: echo beg \\ end\n; echo beg \ end\n; c) Why do I hate regular expressions so much? perhaps because you're using them wrong. klugscheisser ;) I've answered all 5 of em so far. thanks, your answers helped a lot! - jns -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] (another) regex difficulty
regular expressions
the example below should turn any character exept \* (*= any char)
into an x:
$term = preg_replace('/[^(\\\)+(.){1}]/', 'x', $term);
but i guess because of the [brackets] the . (period) is treated as
character . instead as metacharacter (that matches any char).
anyone knows how to work around this?
thanks for your effort
best wishes,
jns
ps: thanks for your help, holmes and kilimajer!
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Re: [PHP] (another) regex difficulty
* Thus wrote jonas_weber @ gmx. ch ([EMAIL PROTECTED]):
regular expressions
the example below should turn any character exept \* (*= any char)
into an x:
$term = preg_replace('/[^(\\\)+(.){1}]/', 'x', $term);
preg_replace('/(?!\\).{1}/', 'x', $term);
this is untested but using the assertion (?!\\), meaning that the
string '\' doesn't appear before the character, should be the
direction to go.
see:
http://php.net/manual/en/pcre.pattern.syntax.php
Curt
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Re: [PHP] (another) regex difficulty
From: [EMAIL PROTECTED]
regular expressions
the example below should turn any character exept \* (*= any char)
into an x:
$term = preg_replace('/[^(\\\)+(.){1}]/', 'x', $term);
but i guess because of the [brackets] the . (period) is treated as
character . instead as metacharacter (that matches any char).
anyone knows how to work around this?
Maybe...
$term = preg_replace('/[^\\]./','x',$term);
which would replace any character that's NOT a \ followed by any other
character with an x...
Not tested, of course. :)
---John Holmes...
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Re: [PHP] (another) regex difficulty
01.10.03 at 18:17 Curt Zirzow wrote:
preg_replace('/(?!\\).{1}/', 'x', $term);
01.10.03 at 18:27 CPT John W. Holmes wrote:
$term = preg_replace('/[^\\]./','x',$term);
they don't work (thanks anyway)
it's pretty simple: i need a regex that matches any character in a
string except \* (* stands for any char that follows the \).
example: this is \ba test
should match: this a is test
isn't there a way to do this?
best wishes,
jns
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Re: [PHP] (another) regex difficulty
From: [EMAIL PROTECTED]
it's pretty simple: i need a regex that matches any character in a
string except \* (* stands for any char that follows the \).
example: this is \ba test
should match: this a is test
isn't there a way to do this?
Turn that around. What you need to do is remove \* from your string...
$new_str = preg_replace('/\\./','',$old_str);
Regular expressions are for pattern matching... not matching everything
BUT a pattern.
---John Holmes...
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Re: [PHP] (another) regex difficulty
* Thus wrote jonas_weber @ gmx. ch ([EMAIL PROTECTED]):
01.10.03 at 18:17 Curt Zirzow wrote:
preg_replace('/(?!\\).{1}/', 'x', $term);
01.10.03 at 18:27 CPT John W. Holmes wrote:
$term = preg_replace('/[^\\]./','x',$term);
they don't work (thanks anyway)
quote orignal message
the example below should turn any character exept \* (*= any
char) into an x:
/quote
Besides that all mine needed was a extra \
$term = 'char \not xed';
preg_replace('/(?!\\\).{1}/', 'x', $term);
result: xxnx
will replace anychar that isnt escaped by \ to an x, with the side
effect that the \ gets x'd too, thus
preg_replace('/(?!\\\)[\\\]{1}/', 'x', $term);
Finally fixes the problem:
result: x\nx
it's pretty simple: i need a regex that matches any character in a
string except \* (* stands for any char that follows the \).
example: this is \ba test
should match: this a is test
isn't there a way to do this?
This is completly different problem. It isn't a matching issue but
a replacement issue.
preg_replace('/\\\.{1}/', '', $term);
You want to remove all \* characters.
Curt
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