[PHP] Creating a Directory

[PartyPosters]

Hello, I am using the following script to upload files to my server. Is there 
anyway I can create a directory (on the fly) for the new image to go, as I want 
people to be able to upload files with the same name.


Thanks

$uploadDir = 'uploads/';
$uploadFile = $uploadDir . $_FILES['form_data']['name'];
print pre;
if (move_uploaded_file($_FILES['form_data']['tmp_name'], $uploadFile))
{
print File is valid, and was successfully uploaded. ;
   # print Here's some more debugging info:\n;
#print_r($_FILES);
}
else
{
 print File is invalid. ;
   # print Possible file upload attack!  Here's some debugging info:\n;
 #   print_r($_FILES);
}
print /pre;

RE: [PHP] Creating a Directory

[Jay Blanchard]

[snip]
Hello, I am using the following script to upload files to my server. Is
there anyway I can create a directory (on the fly) for the new image to
go, as I want people to be able to upload files with the same name.
[/snip]

You know that manual thingie? It's awersome! http://us3.php.net/mkdir

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[PHP] Creating a directory

[Danny Brow]

What's the best way to create a directory with PHP, I tried using:

if (array_exists('dir',$_POST)) {
$dir_name = test123;  
shell_exec('mkdir $dir_name'); 

I don't want to have to declare a variable, I would like to do this all
on one line. Like:
shell_exec('mkdir $_POST['dir']'); // but it don't work
} else {
print Get get some coffee!;
}

I'll be putting some error checking in later :)

Thanks,
Dan.

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Re: [PHP] Creating a directory

[Pluance]

Use mkdir in PHP Functions.
See Also: http://www.php.net/manual/en/function.mkdir.php

On Fri, 12 Nov 2004 03:54:52 -0500, Danny Brow [EMAIL PROTECTED] wrote:
 What's the best way to create a directory with PHP, I tried using:
 
 if (array_exists('dir',$_POST)) {
$dir_name = test123;
shell_exec('mkdir $dir_name');
 
 I don't want to have to declare a variable, I would like to do this all
 on one line. Like:
shell_exec('mkdir $_POST['dir']'); // but it don't work
 } else {
print Get get some coffee!;
 }
 
 I'll be putting some error checking in later :)
 
 Thanks,
 Dan.
 
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Re: [PHP] Creating a directory

[Jason Wong]

On Friday 12 November 2004 08:54, Danny Brow wrote:
 What's the best way to create a directory with PHP, I tried using:

 if (array_exists('dir',$_POST)) {
  $dir_name = test123;

I'm 99% sure you mean 'test123'.

  shell_exec('mkdir $dir_name');

I'm 100% sure you meant to use  instead of '.

 } else {
 print Get get some coffee!;

I'm 50% sure that should be print RTFM.

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Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *
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Re: [PHP] Creating a directory

[Danny Brow]

Thanks, I should have looked that up. 4am, time for bed.

Thanks again,
Dan.

On Fri, 2004-11-12 at 18:01 +0900, Pluance wrote:
 Use mkdir in PHP Functions.
 See Also: http://www.php.net/manual/en/function.mkdir.php
 
 On Fri, 12 Nov 2004 03:54:52 -0500, Danny Brow [EMAIL PROTECTED] wrote:
  What's the best way to create a directory with PHP, I tried using:
  
  if (array_exists('dir',$_POST)) {
 $dir_name = test123;
 shell_exec('mkdir $dir_name');
  
  I don't want to have to declare a variable, I would like to do this all
  on one line. Like:
 shell_exec('mkdir $_POST['dir']'); // but it don't work
  } else {
 print Get get some coffee!;
  }
  
  I'll be putting some error checking in later :)
  
  Thanks,
  Dan.
  
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  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php
  
 
 

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Re: [PHP] Creating a directory

[Danny Brow]

On Fri, 2004-11-12 at 17:12 +, Jason Wong wrote:
 On Friday 12 November 2004 08:54, Danny Brow wrote:
  What's the best way to create a directory with PHP, I tried using:
 
  if (array_exists('dir',$_POST)) {
   $dir_name = test123;
 
 I'm 99% sure you mean 'test123'.

I meant $dir_name = $_POST['dir']; This works with out the single quote.
but all my variables have single or double quotes around them.

 
   shell_exec('mkdir $dir_name');
 
 I'm 100% sure you meant to use  instead of '.

this is how I normally do this when declaring variables, but that maybe
the difference here. 

 
  } else {
  print Get get some coffee!;
 
 I'm 50% sure that should be print RTFM.

RTFM  /dev/null :)


I'm 25-50% sure that this was a complete waste of a reply to a question.


 
 -- 
 Jason Wong - Gremlins Associates - www.gremlins.biz
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *
 --
 Search the list archives before you post
 http://marc.theaimsgroup.com/?l=php-general
 --
 /*
 I like your SNOOPY POSTER!!
 */
 

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