[PHP] Empty Reference to an Object
Hi, I´m trying to give an empty reference as a parameter, in a function. Or rather make a parameter that is a reference optional. I have a function that should react differently if it is given an object or not. It works, but it gives me a warning that the second argument is not being given obviously. Sadly I cannot make the parameter optional in the function definition because mine has to be a reference. One can´t do such a thing as function( $parameter1, objectparameter = NULL) this results into a parsing error. I cannot believe that there is no way of making an object parameter optional. So tell me please what I´m missing. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Empty Reference to an Object
Hello Sebastian,
Tuesday, January 13, 2004, 3:09:39 PM, you wrote:
SO I cannot believe that there is no way of making an object parameter
SO optional.
function ($parameter1, $parameter2 = NULL)
{
// etc
}
If passed to your function, $parameter2 will be your object (or
string or whatever you wanted), if not passed in it'll be null.
--
Best regards,
Richardmailto:[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Empty Reference to an Object
At 16:14 2004-01-13, you wrote:
Hello Sebastian,
Tuesday, January 13, 2004, 3:09:39 PM, you wrote:
SO I cannot believe that there is no way of making an object parameter
SO optional.
function ($parameter1, $parameter2 = NULL)
{
// etc
}
If passed to your function, $parameter2 will be your object (or
string or whatever you wanted), if not passed in it'll be null.
this might work this is an ugly solution from the top of my head, not tested:
?php
$myObject = (ifYour object exists)? $yourObject : new stdClass;
foo(blaha,$myObject);
function foo($para1,$param2){
if(get_class($param2) =='stdClass') $param2 = NULL; // get_class
might return stdclass not sure
}
?
/ Jimmy
--
Best regards,
Richardmailto:[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Empty Reference to an Object
On 13 January 2004 15:10, Sebastian Ossio wrote: Hi, I´m trying to give an empty reference as a parameter, in a function. Or rather make a parameter that is a reference optional. I have a function that should react differently if it is given an object or not. It works, but it gives me a warning that the second argument is not being given obviously. Sadly I cannot make the parameter optional in the function definition because mine has to be a reference. One can´t do such a thing as function( $parameter1, objectparameter = NULL) this results into a parsing error. I cannot believe that there is no way of making an object parameter optional. So tell me please what I´m missing. PHP5 ;). This is one of the improvements that will be in PHP 5 when it is released. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
