Re: [PHP] Image from a secure site
2007/3/12, Richard Lynch [EMAIL PROTECTED]:
Instead of trying to re-invent the authentication wheel, just use
http://php.net/curl
wow!! Thanks you A LOOOT!!! thats amazing!!!
On Thu, March 8, 2007 4:51 pm, Manolet Gmail wrote:
hi, i install 4 IP cameras and i want to extract the images from their
web interface that is protected be a username and password (HTTP AUTH)
and show it into another system. so i do a function to connect to it
and get the image...
function subd($host,$port,$ownername,$passw,$request) {
$sock = fsockopen($host,$port);
if(!$sock) {
print('Socket error');
exit();
}
$authstr = $ownername:$passw;
$pass = base64_encode($authstr);
$in = GET $request\r\n;
$in .= HTTP/1.0\r\n;
$in .= Host:$host\r\n;
$in .= Authorization: Basic $pass\r\n;
$in .= \r\n;
fputs($sock, $in);
while (!feof($sock)) {
$result .= fgets ($sock,128);
}
fclose( $sock );
return $result;
}
and next i want to print it into the browser..
$request = /IMAGE.JPG?cidx=20072261649239281;
$result =
subd('contelec.sytes.net',2002,invitado,invitado,$request);
header ('Content-type: image/jpeg');
imagejpeg($result);
exit();
but doesnt work if you want to check the cam you can go to
http://contelec.sytes.net:2002 the username is invitado and the
password is invitado.
please help me!
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Re: [PHP] Image from a secure site
Well in case someone need to do this... this is the code.. very easy at all..
header ('Content-type: image/jpeg');
$ch
=curl_init(http://contelec.sytes.net:2002/IMAGE.JPG?cidx=20072261649239281;);
curl_setopt($ch,CURLOPT_USERPWD,invitado:invitado);
curl_exec($ch);
curl_close($ch);
2007/3/13, Manolet Gmail [EMAIL PROTECTED]:
2007/3/12, Richard Lynch [EMAIL PROTECTED]:
Instead of trying to re-invent the authentication wheel, just use
http://php.net/curl
wow!! Thanks you A LOOOT!!! thats amazing!!!
On Thu, March 8, 2007 4:51 pm, Manolet Gmail wrote:
hi, i install 4 IP cameras and i want to extract the images from their
web interface that is protected be a username and password (HTTP AUTH)
and show it into another system. so i do a function to connect to it
and get the image...
function subd($host,$port,$ownername,$passw,$request) {
$sock = fsockopen($host,$port);
if(!$sock) {
print('Socket error');
exit();
}
$authstr = $ownername:$passw;
$pass = base64_encode($authstr);
$in = GET $request\r\n;
$in .= HTTP/1.0\r\n;
$in .= Host:$host\r\n;
$in .= Authorization: Basic $pass\r\n;
$in .= \r\n;
fputs($sock, $in);
while (!feof($sock)) {
$result .= fgets ($sock,128);
}
fclose( $sock );
return $result;
}
and next i want to print it into the browser..
$request = /IMAGE.JPG?cidx=20072261649239281;
$result =
subd('contelec.sytes.net',2002,invitado,invitado,$request);
header ('Content-type: image/jpeg');
imagejpeg($result);
exit();
but doesnt work if you want to check the cam you can go to
http://contelec.sytes.net:2002 the username is invitado and the
password is invitado.
please help me!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Image from a secure site
Instead of trying to re-invent the authentication wheel, just use
http://php.net/curl
On Thu, March 8, 2007 4:51 pm, Manolet Gmail wrote:
hi, i install 4 IP cameras and i want to extract the images from their
web interface that is protected be a username and password (HTTP AUTH)
and show it into another system. so i do a function to connect to it
and get the image...
function subd($host,$port,$ownername,$passw,$request) {
$sock = fsockopen($host,$port);
if(!$sock) {
print('Socket error');
exit();
}
$authstr = $ownername:$passw;
$pass = base64_encode($authstr);
$in = GET $request\r\n;
$in .= HTTP/1.0\r\n;
$in .= Host:$host\r\n;
$in .= Authorization: Basic $pass\r\n;
$in .= \r\n;
fputs($sock, $in);
while (!feof($sock)) {
$result .= fgets ($sock,128);
}
fclose( $sock );
return $result;
}
and next i want to print it into the browser..
$request = /IMAGE.JPG?cidx=20072261649239281;
$result =
subd('contelec.sytes.net',2002,invitado,invitado,$request);
header ('Content-type: image/jpeg');
imagejpeg($result);
exit();
but doesnt work if you want to check the cam you can go to
http://contelec.sytes.net:2002 the username is invitado and the
password is invitado.
please help me!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Image from a secure site
hi, i install 4 IP cameras and i want to extract the images from their
web interface that is protected be a username and password (HTTP AUTH)
and show it into another system. so i do a function to connect to it
and get the image...
function subd($host,$port,$ownername,$passw,$request) {
$sock = fsockopen($host,$port);
if(!$sock) {
print('Socket error');
exit();
}
$authstr = $ownername:$passw;
$pass = base64_encode($authstr);
$in = GET $request\r\n;
$in .= HTTP/1.0\r\n;
$in .= Host:$host\r\n;
$in .= Authorization: Basic $pass\r\n;
$in .= \r\n;
fputs($sock, $in);
while (!feof($sock)) {
$result .= fgets ($sock,128);
}
fclose( $sock );
return $result;
}
and next i want to print it into the browser..
$request = /IMAGE.JPG?cidx=20072261649239281;
$result = subd('contelec.sytes.net',2002,invitado,invitado,$request);
header ('Content-type: image/jpeg');
imagejpeg($result);
exit();
but doesnt work if you want to check the cam you can go to
http://contelec.sytes.net:2002 the username is invitado and the
password is invitado.
please help me!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
