Re: [PHP] PHP CGI mode and command line variables

2003-07-24 Thread CDitty 
That worked like a charm.  Thanks Chris.  I've added this to my snippet 
collection.  :)

At 12:02 AM 7/24/2003, Chris Shiflett wrote:
--- CDitty [EMAIL PROTECTED] wrote:
 Thanks man.  That got rid of the error, however it is not using the
 variable in the script.
You have to read them in. I think you can just loop through $argv, so 
something
like this will show you what PHP is receiving:

?
echo A total of $argc parameters are available:\n\n;
foreach ($argv as $curr_parameter)
{
 echo $curr_parameter\n;
}
?
Hope that helps.

Chris

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[PHP] PHP CGI mode and command line variables

2003-07-23 Thread CDitty 
I have written a script that runs fine when I run it via the command 
line.  However, when I tack on variables to the command line, I get an error.

This works.
php -q ./import.php
This doesn't
php -q ./import.php?feed=eastwood
This is the error that it returns - Could not open input file: 
./import.php?feed=eastwood

Can anyone offer any advice for making this work?

Chris

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Re: [PHP] PHP CGI mode and command line variables

2003-07-23 Thread Chris Shiflett 
--- CDitty [EMAIL PROTECTED] wrote:
 I have written a script that runs fine when I run it via the
 command line. However, when I tack on variables to the command
 line, I get an error.
 
 This works.
 php -q ./import.php
 
 This doesn't
 php -q ./import.php?feed=eastwood

I might be wrong, but I don't think it's possible to simulate GET or POST from
the command line like that. I always have a shell script perspective and pass
things in as arguments like this:

./import.php --feed=eastwood

Of course, if it's under document root, you can test from the command line
using wget.

Hope that helps.

Chris

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Re: [PHP] PHP CGI mode and command line variables

2003-07-23 Thread CDitty 
Thanks man.  That got rid of the error, however it is not using the 
variable in the script.   I can't run this via wget or the browser since 
the importing files are rather large.

Any other ideas?

Chris

At 11:33 PM 7/23/2003, Chris Shiflett wrote:
--- CDitty [EMAIL PROTECTED] wrote:
 I have written a script that runs fine when I run it via the
 command line. However, when I tack on variables to the command
 line, I get an error.

 This works.
 php -q ./import.php

 This doesn't
 php -q ./import.php?feed=eastwood
I might be wrong, but I don't think it's possible to simulate GET or POST from
the command line like that. I always have a shell script perspective and 
pass
things in as arguments like this:

./import.php --feed=eastwood

Of course, if it's under document root, you can test from the command line
using wget.
Hope that helps.

Chris

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http://httphandbook.org/


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Re: [PHP] PHP CGI mode and command line variables

2003-07-23 Thread Chris Shiflett 
--- CDitty [EMAIL PROTECTED] wrote:
 Thanks man.  That got rid of the error, however it is not using the 
 variable in the script.

You have to read them in. I think you can just loop through $argv, so something
like this will show you what PHP is receiving:

?
echo A total of $argc parameters are available:\n\n;
foreach ($argv as $curr_parameter)
{
 echo $curr_parameter\n;
}
?

Hope that helps.

Chris

=
Become a better Web developer with the HTTP Developer's Handbook
http://httphandbook.org/

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