[PHP] RE: [PHP-DB] Help with date

2002-11-28 Thread Aaron Wolski 
Well...

1 day = 60*60*24 = 86400

You figure it out from there :)

Just one example.

Aaron

-Original Message-
From: Dankshit [mailto:[EMAIL PROTECTED]] 
Sent: November 28, 2002 12:06 PM
To: PHP; PHP1
Subject: [PHP-DB] Help with date


How can i add days to a date??




Equipe Pratic Sistemas
Rodrigo Corrêa
Fone: (14) 441-1700
[EMAIL PROTECTED]
[EMAIL PROTECTED] 
 




--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] RE: [PHP-DB] Help with Date

2002-11-21 Thread John W. Holmes 
> Is there a way to convert a date " 20/11/2002 " to a Float number in
PHP,
> since the date starts in 30/12/1899, just like the delphi treats the
> dates

Yeah, of course. To convert "20/11/2002" into a float, just do

echo (float)"20/11/2002";

and you get 20!!

Or you can use strtotime() to convert it to a Unix timestamp (integer,
number of seconds since Jan 1, 1970).

---John Holmes...



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] Re: [PHP-DB] Help with Date

2002-11-21 Thread DL Neil 
Rodrigo,

Is there a way to convert a date " 20/11/2002 " to a Float number in PHP,
since the date starts in 30/12/1899, just like the delphi treats the
dates

=Check out UNIX timestamps (but watch the valid date range),
=dn


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php