In article [EMAIL PROTECTED], [EMAIL PROTECTED]
says...
Anthony Ritter wrote:
I am trying to access a website that has tab delimited data and use
PHP to open the file, read from the
file for output.
I'd like to then place this data into an array, loop through the
array and output only the next to last record.
Is there any way to loop through the following records - there are 96
- and keep only the *next to last last one* (which would be the most
current record) before hitting EOF.
They store the records every 15 minutes for a 24 hour span.
I do not need all 96 records - only the most current - or - next to
last - record.
Read the file with the file function (http://www.php.net/file). This will
give you an array, with each element representing a line in the original
file.
Pop the last element away (http://www.php.net/array_pop) twice. The second
time you do this, store the element you will gain (pop will return the
element it popped). There you have it...
In code:
?
$content = file(
'http://waterdata.usgs.gov/ny/nwis/uv?format=rdbperiod=1site_no=01420500'
);
array_pop( $content );
$current = array_pop( $content );
?
OK - this is a fine candidate for 'how many ways can it be done?'. My
contribution [NB untested]:
?
$content = file(
'http://waterdata.usgs.gov/ny/nwis/uv?format=rdbperiod=1site_no=01420500
');
$current = $content{count($content)-2};
Use count to find the number of elements and use count-2 to select the
second-to-last element. Recall that the first element is [0].
Cheers
--
David Robley
Temporary Kiwi!
Quod subigo farinam
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