Re: [PHP] Re: PHP, over javascript code simple \n
single ' will work fine. :) not double "
On Fri, 20 Aug 2004 11:49:10 +0200, aRZed <[EMAIL PROTECTED]> wrote:
>
> > > print("
> > if (document.rpcjs_louie.ColCustName.value == \"\") { walangfield +=
> > \"Missing: Firstname\n\"; }
> > ");
> > ?>
>
> try simply escaping the "\" before the "n" with an additional "\" or in
> other words: use "\\n" instead of "\n". PHP will interpret "\\" as an "\".
>
>
>
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Louie Miranda
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[PHP] Re: PHP, over javascript code simple \n
try simply escaping the "\" before the "n" with an additional "\" or in other words: use "\\n" instead of "\n". PHP will interpret "\\" as an "\". -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: PHP, over javascript code simple \n
Got it.
use ' and not "
because php reads if its under "
On Fri, 20 Aug 2004 11:10:24 +0800, Louie Miranda <[EMAIL PROTECTED]> wrote:
> Im having problems. Because my javascript is inside a PHP code.
> Now below are 1 line code of a print function that display this on the
> html header.
> i must put "\n" after the Firstname. But PHP actually reads \n so when
> i view it on a browser the js code moves down. Which is wrong, because
> it wont work anymore.. what i want is js should use the \n instead. is
> there any alternative for \n? so it can display properly on php?
>
> print("
> if (document.rpcjs_louie.ColCustName.value == \"\") { walangfield +=
> \"Missing: Firstname\n\"; }
> ");
> ?>
>
> --
> Louie Miranda
> http://www.axishift.com
>
--
Louie Miranda
http://www.axishift.com
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