[PHP] Re: Week calculating

2004-01-13 Thread memoimyself
A quick idea that can probably be perfected:

 2050 )
{
return false;
}

$ini_date = mktime(0, 0, 0, 1, 1, $year);   // Jan. 1
$end_date = mktime(0, 0, 0, 12, 31, $year); // Dec. 31

// The array to be returned.
$weekday_dates = array();

// There are 86400 seconds in a day.
for( $i = $ini_date; $i <= $end_date; $i += 86400 )
{
if( strtolower( date('D', $i) ) == strtolower($weekday) )
{
// Format the wanted dates.
$weekday_dates[] = date('y-m-d', $i);
}
}

return $weekday_dates;
}

$test = calc_weekday_dates ('Tue', 2004);
print '';
print_r($test);
print '';

?>

Seems to work. Now you can improve on it.

Cheers,

Erik Fleischer


On 13 Jan 2004 at 15:07, nabil wrote:

> Greetings;
> 
> I need a help here ... I want to make function that return the dates of
> Tuesdays in a given year
> 
> Example::
> 
> Calc_Tuesdays (2004);
> 
> //and it should return or echo
> 2004-01-06
> 2004-01-13
> 2004-01-20
> 2004-01-27
> 2004-02-03
> .
> .
> etc   ofcourse it should echo 5 Tuesdays in March by example
> so it should depends on the year not only current day+7
> 
> any help please !!
> Nabil
> 
> -- 
> PHP General Mailing List (http://www.php.net/)
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Re: [PHP] Re: Week calculating

2004-01-13 Thread Jason Wong
On Tuesday 13 January 2004 21:29, nabil wrote:
> sorry but what do u think about this ?
>
>  for ($j=1;$j<13;$j++) {
>for ($i=1;$i<32;$i++) {
>$mk = mktime(0, 0, 0, $j, $i, 2004);
>$datex = date ("l", $mk);
>$daterest = date ("j/n/Y", $mk);
>if ($datex == "Tuesday") {
>echo $datex.">".$daterest."";
>}
>}
> }
> ?>

You don't need the nested for-loop. Just a single loop to increment the 'day', 
going from, say, 1 to 366 would do. mktime() will take care of the month 
automatically.

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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[PHP] Re: Week calculating

2004-01-13 Thread nabil
sorry but what do u think about this ?

".$daterest."";
   }
   }
}
?>

the problem that it outputs 6 weeks in March ... why ?



"Nabil" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Greetings;
>
> I need a help here ... I want to make function that return the dates of
> Tuesdays in a given year
>
> Example::
>
> Calc_Tuesdays (2004);
>
> //and it should return or echo
> 2004-01-06
> 2004-01-13
> 2004-01-20
> 2004-01-27
> 2004-02-03
> .
> .
> etc   ofcourse it should echo 5 Tuesdays in March by example
> so it should depends on the year not only current day+7
>
> any help please !!
> Nabil


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