[PHP] Re: getting directory info

[Wm]

This is giving me a parse error:

?php $path = '/usr/local/...full.path.snipped.../httpdocs/thumbnails/';
  $dir = opendir($path) or die(Could not open $dir);
  while ($file = readdir($dir)){
  if (stristr($file, 'jpg') || stristr($file, 'jpeg')){
  echo A HREF=/enlargements/$file$file/ABR\n;
  }
  }
  ?BR

This is the only PHP on the page, so it arguably has to be in the above...
:-(

Wm


Richard Lynch [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...

 ?php
   $path = '/full/path/to/your/jpeg/dir/'; # Be sure it's world-readable!
   $dir = opendir($path) or die(Could not open $dir);
   while ($file = readdir($dir)){
 if (stristr($file, 'jpg') || stristr($file, 'jpeg')){
   echo A HREF=$file$file/ABR\n;
 }
   }
 ?




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[PHP] Re: getting directory info

[Richard Lynch]

Can I use php to get a list of all the jpgs in a folder?  I want to make a
photo album type thing for a website, and I want it to be real simple (i.e.
you put photos (jpgs) in a folder called photos and upload them.  Then the
album is built dynamically using php.  Thoughts?

http://php.net/opendir
http://php.net/readdir
http://php.net/stristr

?php
  $path = '/full/path/to/your/jpeg/dir/'; # Be sure it's world-readable!
  $dir = opendir($path) or die(Could not open $dir);
  while ($file = readdir($dir)){
if (stristr($file, 'jpg') || stristr($file, 'jpeg')){
  echo A HREF=$file$file/ABR\n;
}
  }
?

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