[PHP] Re: include from another URL

2004-05-12 Thread AcZ
Nik wrote:
Hi there,
I'm new to these groups so forgive me if I'm asking at the wrong place (tell me where 
then :)
Ok,
I'm not PHP guru but I need to create a simple script that would do this:
Include a content from another URL into the current output. I have done something like
this:
-- code start
?php
 include 'http://myotherurl.com:8080';
?
-- code end
and it seems to work with one exception: it produces a warning message saying 
something like
 Warning: main(): stream does not support seeking in .../web-root/index.php on line 9
where line #9 is: include 'http://myotherurl.com:8080'; from above code.
It then shows a message from 'http://myotherurl.com:8080'
Thanks!!!
Nik
Nik,

try fopen instead of include..

http://br.php.net/manual/en/function.fopen.php
look at comments...
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[PHP] Re: Include from another URL?

2004-05-06 Thread Kim Steinhaug
You could always use this :

 $text = ;
 $fd=fopen($url,r);
 while ($line=fgets($fd,1000)) { $text.=$line; } fclose ($fd);
 echo $text;

-- 
-- 
Kim Steinhaug
--
There are 10 types of people when it comes to binary numbers:
those who understand them, and those who don't.
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www.steinhaug.com - www.easywebshop.no - www.webkitpro.com
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Nik [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Hi there,
 I'm new to these groups so forgive me if I'm asking at the wrong place
(tell
 me where then :)

 Ok,
 I'm not PHP guru but I need to create a simple script that would do this:

 Include a content from another URL into the current output. I have done
 something like
 this:

 -- code start
 ?php
  include 'http://myotherurl.com:8080';
 ?
 -- code end

 and it seems to work with one exception: it produces a warning message
 saying something like
  Warning: main(): stream does not support seeking in
.../web-root/index.php
 on line 9
 where line #9 is: include 'http://myotherurl.com:8080'; from above code.
 It then shows a message from 'http://myotherurl.com:8080'

 Thanks!!!
 Nik

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