I'm not 100% sure this works, but maybe try something like this:
img src="? include 'myphpcode.php'; ?>">
If that doesn't work, you can always have the php generate the entire
tag
?
$image = "myimagefile.gif"; // What ever you need
print "img src=\"$image\">";
?>
Hope this helps :-)
"Karl J. Stubsjoen" wrote:
Hello,
I'd like the source of an image tag to point to PHP code. I'd
like that PHP
code to generate an image (accordingly) and print/output the results
back to
the calling image. So:
img src="myphpcode.php">
Where, myphpcode.php returns a valid image.
I've done this before, but it is not fresh in my brain.
Any help would be appreciated!
Karl
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