[PHP] Transfer variable to next web-page

2001-11-17 Thread Olav Drageset

I just started..

How do you transfer a variable from one web-page to another
I try to use a form like this:
?
echo(P 
FORM method='POST' action='join2.php'
text for button
INPUT type='submit' value='Next step'
INPUT type='hidden' name='htmlVariableName' value='$phpVariableName'
/FORM
);
?

and catch it injoin2.phpby:

$phpVariableName=htmlVariableName;

echo$phpVariableName;

This do not work.
Can anyone tel me what should be done
Neither books, php-manual nor HTML-specification does tel me.

Olav




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Re: [PHP] Transfer variable to next web-page

2001-11-17 Thread Richard S. Crawford

Use

 $phpVariableName = $htmlVariableName;

Remember to use the $ in front of the variable that you toss from the HTML 
form.


At 10:00 AM 11/17/2001, Olav Drageset wrote:
I just started..

How do you transfer a variable from one web-page to another
I try to use a form like this:
?
echo(P
FORM method='POST' action='join2.php'
text for button
INPUT type='submit' value='Next step'
INPUT type='hidden' name='htmlVariableName' value='$phpVariableName'
/FORM
);
?

and catch it injoin2.phpby:

$phpVariableName=htmlVariableName;

echo$phpVariableName;

This do not work.
Can anyone tel me what should be done
Neither books, php-manual nor HTML-specification does tel me.

Olav




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Sliante,
Richard S. Crawford

http://www.mossroot.com
mailto:[EMAIL PROTECTED]
AIM: Buffalo2K   ICQ: 11646404  Y!: rscrawford
It is only with the heart that we see rightly; what is essential is 
invisible to the eye.  --Antoine de Saint Exupéry

Push the button, Max!


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RE: [PHP] Transfer variable to next web-page

2001-11-17 Thread Matthew Loff


Richard already answered the variable part, but I thought I'd point out
that you need to use double quotes in your HTML tags... Single quotes
are incorrect...

?
echo(P 
FORM method=\POST\ action=\join2.php\
text for button
INPUT type=\submit\ value=\Next step\
INPUT type=\hidden\ name=\htmlVariableName\
value=\$phpVariableName\
/FORM
);
?

Or...

?
echo('P 
FORM method=POST action=join2.php
text for button
INPUT type=submit value=Next step
INPUT type=hidden name=htmlVariableName value='. $phpVariableName
.'
/FORM
);
?

Or... Better yet, why not just:

P
FORM method=POST action=join2.php
text for button
INPUT type=submit value=Next step
INPUT type=hidden name=htmlVariableName
value=?=$phpVariableName?
/FORM


See the PHP manual for escaping HTML and string literals if you're
confused by any of this..
http://www.php.net/manual/en/language.basic-syntax.php#language.basic-sy
ntax.phpmode
http://www.php.net/manual/en/language.types.string.php



-Original Message-
From: Olav Drageset [mailto:[EMAIL PROTECTED]] 
Sent: Saturday, November 17, 2001 1:01 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Transfer variable to next web-page


I just started..

How do you transfer a variable from one web-page to another
I try to use a form like this:
?
echo(P 
FORM method='POST' action='join2.php'
text for button
INPUT type='submit' value='Next step'
INPUT type='hidden' name='htmlVariableName' value='$phpVariableName'
/FORM
);
?

and catch it injoin2.phpby:

$phpVariableName=htmlVariableName;

echo$phpVariableName;

This do not work.
Can anyone tel me what should be done
Neither books, php-manual nor HTML-specification does tel me.

Olav




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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]


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