Re: [PHP] Using javascript with php
getElementByID() On Wed, February 15, 2006 4:10 pm, Sugrue, Sean wrote: To all, I have a check box input which I assign an array to the name. I want to pass the array to a javascript and based on a certain criteria check the box. I use the syntax: formname.elements['array[]'][index].checked= true. It works with IE but since my buddy added an html validator to a config file we all use and now the code will not work in Firefox. Does anyone out there perform this task differently? Any suggestions? Sean -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Using javascript with php
To all, I have a check box input which I assign an array to the name. I want to pass the array to a javascript and based on a certain criteria check the box. I use the syntax: formname.elements['array[]'][index].checked= true. It works with IE but since my buddy added an html validator to a config file we all use and now the code will not work in Firefox. Does anyone out there perform this task differently? Any suggestions? Sean -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Using javascript with php
On Wed, Feb 15, 2006 at 05:10:53PM -0500, Sugrue, Sean wrote:
To all,
I have a check box input which I assign an array to the name. I want to
pass the array to a javascript and based on a certain criteria check
the box. I use the syntax: formname.elements['array[]'][index].checked=
true. It works with IE but since my buddy added an html validator
to a config file we all use and now the code will not work in Firefox.
Does anyone out there perform this task differently? Any suggestions?
I always assign ID's to my elements and reference them that way.
input name=array[] id=array_item_1 type=checkbox
var element = document.getElementById('array_item_1');
element.checked = true;
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Re: [PHP] Using javascript function from php
I am just learning php, and am currently converting some jsp pages to php.
I used the follwing code in jsp to toggle between two images
Instead of driving yourself nuts with echo and quote and backslash and
semi-colon quote semi-colon, just do like this:
?php
//PHP code here
?
!-- Look ma! No PHP --
SCRIPT type=text/javascript language=javascript
function toggle(imagename,src1,src2){
if(document.images document.images[imagename])
{
image1=new Image;
image1.src=src1;
if(document.images[imagename].src !=
image1.src){document.images[imagename].src = image1.src}
else{document.images[imagename].src=src2}
}
}
/SCRIPT
?php
//more PHP here
?
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[PHP] Using javascript function from php
Hi,
I am just learning php, and am currently converting some jsp pages to php.
I used the follwing code in jsp to toggle between two images
SCRIPT type=text/javascript language=javascript
function toggle(imagename,src1,src2){
if(document.images document.images[imagename])
{
image1=new Image;
image1.src=src1;
if(document.images[imagename].src !=
image1.src){document.images[imagename].src = image1.src}
else{document.images[imagename].src=src2}
}
}
/SCRIPT
start code snippet.
out.println(A);
out.println(onclick=\toggle(' + child + image','images/ + type
+ .jpg','images/ + childimg ');return(false);\);
out.println(img src='images/ + type + .jpg' alt='' name= + child
+ image/a);
out.println(input type=hidden name= + child + value=' + childimg
+ ');
end code snippet...
I have tried many different ways to achieve this in php, but nothing
works. This is my latest attempt
start code snippet.
print(A href=\javascript:;\ onclick=);
echo \if(document.images document.images[ . $child . image])\n;
echo {\n;
echo image1=new Image;\n;
echo image1.src=images/$type.jpg;\n;
echo if(document.images[ . $child . image].src !=
image1.src){document.images[ . $child . image].src = image1.src}\n;
echo else{document.images[ . $child . image].src=images/$childimg}\n;
echo }\n;
echo };\n;
echo return(false);\\n;
print(img src='images/$type.jpg' alt='' name= . $child .
image\n/a\n);
print(input type=hidden name=$child value='$childimg'\n);
end code snippet.
Could someone please let me know how to do this
Cheers
Barb
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[PHP] using javascript within php
I want to set focus on a text area with javascript if the entry by the user
is not what I want.
This is what i have so far.
?php
if (isset($submitted){
if(empty($name)) {
$fname_error = *Please Enter your firstname or initial;
//the code to set focus to the textbox should go here
}
}
?
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Re: [PHP] using javascript within php
Ross Hulford wrote: snip PHP == Server Side HTML/JavaScript == Client Side -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] using javascript within php
[snip]
I want to set focus on a text area with javascript if the entry by the
user
is not what I want.
if (isset($submitted){
if(empty($name)) {
$fname_error = *Please Enter your firstname or initial;
//the code to set focus to the textbox should go here
}
[/snip]
if(empty($name)) {
$fname_error = *Please Enter your firstname or initial;
//the code to set focus to the textbox should go here
echo window.document.YOURFORMNAME.name.focus();;
}
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Re: [PHP] Using JavaScript variables in PHP
form method=post action=your_php_file.php input name=id /form in your_php_file.php, try select * from somedatabase where field=$id Mike Knittel [EMAIL PROTECTED] 11/20/2003 11:45 PM To: [EMAIL PROTECTED] cc: Subject:[PHP] Using JavaScript variables in PHP How does one go about using a JavaScript variable with PHP code. I have a function in JavaScript that takes a single input parameter (ID). I want to use this ID variable as the value on the where clause of a database query. Example: select * from somedatabase where field=ID Can this be done, and if so how? I have been unable to figure this out. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Using JavaScript variables in PHP
How does one go about using a JavaScript variable with PHP code. I have a function in JavaScript that takes a single input parameter (ID). I want to use this ID variable as the value on the where clause of a database query. Example: select * from somedatabase where field=ID Can this be done, and if so how? I have been unable to figure this out. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Using JavaScript variables in PHP
How does one go about using a JavaScript variable with PHP code. I have a function in JavaScript that takes a single input parameter (ID). I want to use this ID variable as the value on the where clause of a database query. Example: select * from somedatabase where field=ID Can this be done, and if so how? I have been unable to figure this out. Not unless you include the javascript variable in a subsequent GET or POST request to the server - once your browser renders an HTTP response, PHP's involvement is long finished. - michal migurski- contact info and pgp key: sf/cahttp://mike.teczno.com/contact.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Using JavaScript variables in PHP
Mike Knittel wrote: How does one go about using a JavaScript variable with PHP code. I have a function in JavaScript that takes a single input parameter (ID). I want to use this ID variable as the value on the where clause of a database query. Example: select * from somedatabase where field=ID Can this be done, and if so how? I have been unable to figure this out. Not unless you send a request to the server (reload the page, go to another page, etc.). php runs server side, JavaScript runs client side. -- By-Tor.com It's all about the Rush http://www.by-tor.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Using Javascript
Hello Uma, Monday, July 22, 2002, 8:09:44 AM, you wrote: UST Hello, UST I need to display a value on the text box during onClick event where the UST data is fetched from the database..I have given the code like this but it UST is giving unterminated string constant.. UST input type=text name=text1 onClick=(dd.value=? echo $correct; ?); UST Can anyone please tell me how to solve this ... UST Thanks Regards, UST Uma Hi, Try to use: input type=text name=text1 onClick=dd.value='? echo $correct; ?'; -- Best regards, Zoltanmailto:[EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Using Javascript
Hello, I need to display a value on the text box during onClick event where the data is fetched from the database..I have given the code like this but it is giving unterminated string constant.. input type=text name=text1 onClick=(dd.value=? echo $correct; ?); Can anyone please tell me how to solve this ... Thanks Regards, Uma -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
