Re: Re[2]: [PHP] check if a file is included
On Tue, Sep 16, 2008 at 3:09 AM, ANR Daemon [EMAIL PROTECTED] wrote:
Greetings, Jochem Maas.
In reply to Your message dated Tuesday, September 16, 2008, 3:38:44,
ANR Daemon schreef:
Greetings, Jochem Maas.
In reply to Your message dated Friday, September 12, 2008, 17:05:58,
I like my 'schreef' better.
Why you talking to my template? It has strict order to not speak with
unknown
people.
actually $_SERVER[script_name] is probably better if not being used
from
a webserver.
you didn't mention wanting to use the cmdline.
untested code follows:
?php
function indirectCall($s)
{
if (php_sapi_name() == 'cli') {
return strstr($s, $argv[0]) !== false;
} else {
return strstr($s, $_SERVER[REQUEST_URI]) !== false;
}
}
Actually, it must be (Windows-proof):
a, why must it be windows proof, nobody asked for that?
It must work similarly on every platform it can be executed.
b, does this take into account that $_SERVER['SCRIPT_FILENAME'] is not
available of some versions of IIS?
I was unaware of this issue. Is it PHP-specific?
c, you'd think __FILE__ and $_SERVER['SCRIPT_FILENAME'] used consistent
slashes on a given system, no? (I doubt
you need to do the funky translation.
Apache/W32 2.2, PHP/W32 5.2.6
__FILE__ has backspashes, $_SERVER['SCRIPT_FILENAME'] has forward slashes.
d, there is no account take for symlinks, if you really want to be
pedantic:
realpath(__FILE__) != realpath(getenv('PATH_TRANSLATED'))
RTFM anyone?
cgi.fix_pathinfo boolean
Provides real PATH_INFO/PATH_TRANSLATED support for CGI. PHP's previous
behaviour was to set PATH_TRANSLATED to SCRIPT_FILENAME, and to not grok
what
PATH_INFO is. For more information on PATH_INFO, see the cgi specs. Setting
this to 1 will cause PHP CGI to fix it's paths to conform to the spec. A
setting of zero causes PHP to behave as before. Default is zero. You should
fix your scripts to use SCRIPT_FILENAME rather than PATH_TRANSLATED.
PATH_TRANSLATED isn't available under apache2 (and 2.2) SAPI. But in
contrast
to issue you mentioned above, this behaviour is well-documented.
e. the OP wanted it to work on the cmdline as well (sounds silly to me
but there you have it)
It works on cmdline flawlessly.
Tested on both local and network locations as well as from web server, with
any possible mix of slashes.
but really this is all madness. put the file outside the webroot
That's what i'm typically doing. Only one PHP file that available from
webserver root is the index.php.
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Sincerely Yours, ANR Daemon [EMAIL PROTECTED]
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Hi all,
I don't know who know phpbb, but i like it's approach to this problem...
simple set a constant in the scripts you should access and use defined
function for check it on includes... like:
index.php
define( 'IN_MY_APP', 1 );
include1.php
if ( !defined( 'IN_MY_APP' )) {
**header( 'HTTP/1.1 404 Not Found' );
header( 'Location: /' );
}
--
Thanks,
Diogo Neves
Web Developer @ SAPO.pt by PrimeIT.pt
Re: [PHP] check if a file is included
Please stop top-posting. Lest you be smitten with a vengeance reserved only for top-posters. A nasty one. :-) -- Richard Heyes HTML5 Graphing for IE7, FF, Chrome, Opera and Safari: http://www.phpguru.org/RGraph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] check if a file is included
On Sat, Sep 13, 2008 at 2:16 PM, Richard Heyes [EMAIL PROTECTED] wrote: Please stop top-posting. Lest you be smitten with a vengeance reserved only for top-posters. A nasty one. :-) -- Richard Heyes HTML5 Graphing for IE7, FF, Chrome, Opera and Safari: http://www.phpguru.org/RGraph It had to be done! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] check if a file is included
I have a file called interceptor.php, which I would like to make use of
in two ways
1. either call it directly from the browser or
2. included from another file
I know I could use something like this to see if it was called via a url
like http://www.site.com/interceptor.php :
if (strstr('interceptor',$__SERVER[REQUEST_URI])) {
// url
} else {
//probably included
}
but I would like to know if there is a neater, cleaner, sparkly way of
doing this.
Thanks
Clive
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Re: [PHP] check if a file is included
but I would like to know if there is a neater, cleaner, sparkly way of doing
this.
The way your doing it is fine. You could wrap it up in a custom function, eg:
// True means called directly.
function wasThisFileIncludedOrCalledDirectly ()
{
return strstr($__SERVER[REQUEST_URI], 'interceptor');
}
Or something like that.
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http://www.phpguru.org/RGraph
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Re: [PHP] check if a file is included
actually $_SERVER[script_name] is probably better if not being used from a webserver. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] check if a file is included
clive schreef:
actually $_SERVER[script_name] is probably better if not being used from
a webserver.
you didn't mention wanting to use the cmdline.
untested code follows:
?php
function indirectCall($s)
{
if (php_sapi_name() == 'cli') {
return strstr($s, $argv[0]) !== false;
} else {
return strstr($s, $_SERVER[REQUEST_URI]) !== false;
}
}
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Re: [PHP] check if a file is included
At 2:44 PM +0200 9/12/08, clive wrote:
I have a file called interceptor.php, which I would like to make
use of in two ways
1. either call it directly from the browser or
2. included from another file
I know I could use something like this to see if it was called via a
url like http://www.site.com/interceptor.php :
if (strstr('interceptor',$__SERVER[REQUEST_URI])) {
// url
} else {
//probably included
}
but I would like to know if there is a neater, cleaner, sparkly way
of doing this.
Thanks
Clive
Another way.
You could define a variable ($interceptor = 0) in the main portion of
your script and then populate the variable ($interceptor = 1) in the
included portion and then check the value to see if it's been
included or not.
Cheers,
tedd
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Re: [PHP] check if a file is included
On Fri, Sep 12, 2008 at 8:44 AM, clive [EMAIL PROTECTED] wrote:
I have a file called interceptor.php, which I would like to make use of in
two ways
1. either call it directly from the browser or
2. included from another file
I know I could use something like this to see if it was called via a url
like http://www.site.com/interceptor.php :
if (strstr('interceptor',$__SERVER[REQUEST_URI])) {
// url
} else {
//probably included
}
but I would like to know if there is a neater, cleaner, sparkly way of doing
this.
Thanks
Clive
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http://us3.php.net/get_included_files
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Re: [PHP] check if a file is included
On Fri, Sep 12, 2008 at 7:41 PM, Ashley Sheridan [EMAIL PROTECTED] wrote: Could you not check one of the variables in the $_SERVER array to determine if the script called by the browser is the current file? -- Forwarded message -- To: clive [EMAIL PROTECTED] 2. included from another file Don't forget #2. I just threw it out as a suggestion because the current requested file might not be intercept.php. If I were trying to do such a thing I'd probably go about it differently altogether depending on why I needed to know what was in the file. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
