Re: [PHP] classes and variables

[Israel Ekpo]

You do not need to access $DB as a global variable

Since $db_database is a property of search_helper, you can initialize it by
passing a value via the constructor like this

class search_helper extends AjaxACApplication
{
 protected $db_database;

 public function __construct($database_name)
 {
   $this->db_database = $database_name;
 }

public function setDbName($database_name)
{
   $this->db_database = $database_name;
}

public function sayDbName()
{
 echo "The database name is " . $this->db_database;
}
}


This should allow you to do this

$helper = new search_helper($DB);

Later on you can also change the database name like this

$helper->setDbName($newDB);

This should state what the database name is

$helper->sayDbName();







On Mon, May 3, 2010 at 5:05 PM, Merlin Morgenstern wrote:

> Hi there,
>
> I am new to classes in PHP and do want to change a class that has been in a
> package I downloaded. I do simply want to access a variable from outside.
>
> This is the code:
>
>class search_helper extends AjaxACApplication
>{
>
>   //global $DB;
>
>   var $db_database = 'test';
>}
>
> I would like to replace 'test' with $DB. This is the variable from outside
> that holds the name of the Database.
>
> Thank you for any help!
>
> Merlin
>
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> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>


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[PHP] classes and variables

[Merlin Morgenstern]

Hi there,

I am new to classes in PHP and do want to change a class that has been 
in a package I downloaded. I do simply want to access a variable from 
outside.


This is the code:

class search_helper extends AjaxACApplication
{

   //global $DB;

   var $db_database = 'test';
}

I would like to replace 'test' with $DB. This is the variable from 
outside that holds the name of the Database.


Thank you for any help!

Merlin

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