try this:
Thanks for showing that I add new element to the array. This is because on last
iteration $k is null and I access $ar[$k] which automatically adds the new element.
Why? I don't know? Maybe because I refer it by reference!
The fixed code is
This will not add new element to the array.
You ask why I did that.
First to say that I wanted to make something really weird to happy my day :))
Second I wanted to implement a feature from PHP's(Zend's) ToDo list.
Third think about if the array is so big (some megabytes) since I hold really big
strings in every $v. Then if I use the standart foreach() statement PHP will have to
copy $ar[$k] to $v :)))
Best regards and fun with PHP,
Andrey Hristov
On Thursday 07 March 2002 08:48 pm, you wrote:
> On Thu, 2002-03-07 at 09:53, Andrey Hristov wrote:
> > The code below is too weird. I spent 15 min writing it but now works:
> >
> > for(reset($ar),list($k,)=each($ar),$v=&$ar[$k];$k;list($k,)=each($ar),$v=
> >&$ar[$k]){ var_dump($k,$v);
> > $v='ather'.($j+++0);
> > var_dump($k,$v);
> > }
> >
> > The $ar array is generated in this way :
> >
> > for ($i=0;$i<10;$i++){
> > $ar['foo'.$i] = 'bar'.$i;
> > }
>
> Hi there,
>
> I'm not sure exactly what the above code is for--but it seems to be
> going to an awful lot of trouble to do it. :) If I start with the array:
>
> Array
> (
> [foo0] => bar0
> [foo1] => bar1
> [foo2] => bar2
> [foo3] => bar3
> [foo4] => bar4
> [foo5] => bar5
> [foo6] => bar6
> [foo7] => bar7
> [foo8] => bar8
> [foo9] => bar9
> )
>
> ...and run the first for() loop above over it, I get this:
>
> Array
> (
> [foo0] => ather0
> [foo1] => ather1
> [foo2] => ather2
> [foo3] => ather3
> [foo4] => ather4
> [foo5] => ather5
> [foo6] => ather6
> [foo7] => ather7
> [foo8] => ather8
> [foo9] => ather9
> [] =>
> )
>
> Note the extra null element at the end.
>
> Why not just do this?
>
> $j = 0;
> foreach ($ar as $key => $val) {
> $ar[$key] = 'ather' . $j++;
> }
>
> ...which results in:
>
> Array
> (
> [foo0] => ather0
> [foo1] => ather1
> [foo2] => ather2
> [foo3] => ather3
> [foo4] => ather4
> [foo5] => ather5
> [foo6] => ather6
> [foo7] => ather7
> [foo8] => ather8
> [foo9] => ather9
> )
>
> Also, I'm unsure what you're going for with the ($j+++0). It just
> increments $j and adds 0, which doesn't seem to do anything.
>
> Please forgive me if I have misunderstood.
>
>
> Cheers,
>
> Torben
>
> > Best regards,
> > Andrey Hristov
> >
> > P.S.
> > There is in PHP's ToDo list such feature.
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